<h3>
Answer:</h3>
B. 0.33 mol
<h3>
Explanation:</h3>
We are given;
Gauge pressure, P = 61 kPa (but 1 atm = 101.325 kPa)
= 0.602 atm
Volume, V = 5.2 liters
Temperature, T = 32°C, but K = °C + 273.15
thus, T = 305.15 K
We are required to determine the number of moles of air.
We are going to use the concept of ideal gas equation.
- According to the ideal gas equation, PV = nRT, where P is the pressure, V is the volume, R is the ideal gas constant, (0.082057 L.atm mol.K, n is the number of moles and T is the absolute temperature.
- Therefore, to find the number of moles we replace the variables in the equation.
- Note that the total ball pressure will be given by the sum of atmospheric pressure and the gauge
- Therefore;
- Total pressure = Atmospheric pressure + Gauge pressure
We know atmospheric pressure is 101.325 kPa or 1 atm
Total ball pressure = 1 atm + 0.602 atm
= 1.602 atm
That is;
PV = nRT
n = PV ÷ RT
therefore;
n = (1.602 atm× 5.2 L) ÷ (0.082057 × 305.15 K)
= 0.3326 moles
= 0.33 moles
Therefore, there are 0.33 moles of air in the ball.
<span>NaCH3COO (s) + HCl (aq) ---> HCH3COO (aq) + NaCl (s)</span>
Explanation:
Vapor pressure is defined as the pressure exerted by vapors or gas on the surface of a liquid.
Vapor pressure is inversely proportional to the number of solute particles. Hence, more will be the solute particles lower will be the vapor pressure and vice-versa.
(a) 
It dissociates to give two particles.
(b) 
Total number of particles it give upon dissociation are 1 + 2 = 3. Hence, it gives 3 particles.
(c) 
Total number of particles it give upon dissociation are 1 + 3 = 4. Hence, it gives 4 particles.
(d) Surcose being a cobvalent compound doe not dissociate into ions. Therefore, there will be only 1 particle is present.
(e) 
Total number of particles it give upon dissociation are 1 + 1 = 2. Hence, it gives 2 particles.
5-10 seconds xxx :) hope this helps