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Diano4ka-milaya [45]
2 years ago
15

Here is a sketch of a 2px orbital: This sketch is about 800pm wide. The coordinate ( x , y , and z ) axes are also shown. You ca

n rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 2px orbital. Complete each row of the table below by deciding how PA , the probability of finding the electron at point A , compares to PB , the probability of finding the electron at point B . point Apoint Bcompare PA to PB 100 pm to the left of the nucleus, along the -x axis. 100 pm below the nucleus along the -z axis. PAPB 100 pm in front of the nucleus, along the -y axis. 100 pm behind the nucleus, along the +y axis. PAPB 100 pm to the right of the nucleus, along the +x axis. 100 pm above the nucleus, along the +z axis. PAPB
Chemistry
1 answer:
amid [387]2 years ago
7 0
<span><u>PA to PB 100 pm to the left of the nucleus, along the -x axis.</u>
<u>100 pm below the nucleus along the -z axis.</u>

PAPB 100 pm in front of the nucleus, along the -y axis. 100 pm behind the nucleus, along the +y axis.

PAPB 100 pm to the right of the nucleus, along the +x axis. 100 pm above the nucleus, along the +z axis. </span>
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