Question

Here is a sketch of a 2px orbital: This sketch is about 800pm wide. The coordinate ( x , y , and z ) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 2px orbital. Complete each row of the table below by deciding how PA , the probability of finding the electron at point A , compares to PB , the probability of finding the electron at point B . point Apoint Bcompare PA to PB 100 pm to the left of the nucleus, along the -x axis. 100 pm below the nucleus along the -z axis. PAPB 100 pm in front of the nucleus, along the -y axis. 100 pm behind the nucleus, along the +y axis. PAPB 100 pm to the right of the nucleus, along the +x axis. 100 pm above the nucleus, along the +z axis. PAPB

Answer 1

PA to PB 100 pm to the left of the nucleus, along the -x axis.
100 pm below the nucleus along the -z axis.

PAPB 100 pm in front of the nucleus, along the -y axis. 100 pm behind the nucleus, along the +y axis.

PAPB 100 pm to the right of the nucleus, along the +x axis. 100 pm above the nucleus, along the +z axis.