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Alchen [17]
1 year ago
12

A radioactive nuclide is used to detect eye tumors. An atom of this radionuclide contains 15 protons, 15 electrons, and 17 neutr

ons. Which is symbol of this radionuclide?
Chemistry
2 answers:
Mazyrski [523]1 year ago
8 0

Answer:  _{15}^{32}\textrm {P}

Explanation:- Atomic number is the number of protons or the number of electrons.

Mass number is the sum of number of protons and number of neutrons.

Atomic number = number of electrons= number of protons = 15

Mass number = number of protons + number of neutrons= 15+17= 32.

The representation of element is :

where Z= atomic number, A= mass number , X= chemical symbol of element

The representation of the element with atomic number 15 and mass number 32 is :  _{15}^{32}\textrm {P}

choli [55]1 year ago
3 0
Knowing that the number of protons of an element is equivalent to its atomic number, it can be determined from the periodic table of elements that this radiosonde is phosphorus. Since the number of its neutrons is 17, it can also be determined that its atomic mass is n + p = 15 + 17 = 32. This means the isotope is phosphorus-32.<span />
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Octane is a liquid component of gasoline. Given the following vapor pressures of octane at various temperatures, estimate the bo
Hitman42 [59]

Answer:

110.8 ºC

Explanation:

To solve this problem we will make use of the Clausius-Clayperon equation:

lnP = - ΔHºvap/RT + C

where P is the pressure, ΔHºvap is the enthalpy of vaporization, R is the gas constant, T is the temperature, and C is a constant of integration.

Now this equation has a form y = mx + b where

y = lnP

x = 1/T

m = -ΔHºvap/R

Now we have to assume that ΔHºvap remains constant which is a good asumption given the narrow range of temperatures in the data ( 104-125) ºC

Thus what we have to do is find the equation of the best fit for this data using a  software as excel or your calculator.

T ( K)               1/T                  ln P

377               0.002653       5.9915

384              0.002604       6.2115

390              0.002564       6.3969

395              0.002532       6.5511

398              0.002513        6.6333

The best line has a fit:

y = -4609.5 x  + 18.218

with R² = 0.9998

Now that we have the equation of the line, we simply will substitute for a pressure of 496 mm in Leadville.

ln(496) = -4609.5(1/Tb) + 18.218

6.2066 = -4609.5(1/Tb) +18.218

⇒ 1/Tb = (18.218 - 6.2066)/4609.5 = 0.00261

Tb = 383.76 K  = (383.76 -273)K = 110.8 ºC

Notice we have touse up to 4 decimal places since rounding could lead to an erroneous answer ( i.e boiling temperature greater than 111, an impossibility given the data in the question). This is as a result of the value 496 mmHg so close to 500 mm Hg.

Perhaps that is the reason the question was flagged.

7 0
2 years ago
If you add 25.0 mL of water to 125 mL of a 0.150 M LiOH solution, what will be the molarity of the resulting diluted solution?
Alborosie

Concentration is the number of moles of solute in a fixed volume of solution

Concentration(c) = number of moles of solute(n) / volume of solution (v)

25.0 mL of water is added to 125 mL of a 0.150 M LiOH solution and solution becomes more diluted.

original solution molarity - 0.150 M

number of moles of LiOH in 1 L - 0.150 mol

number of LiOH moles in 0.125 L  - 0.150 mol/ L x 0.125 L = 0.01875 mol

when 25.0 mL is added the number of moles of LiOH will remain constant but volume of the solution increases

new volume -  125 mL + 25 mL = 150 mL

therefore new molarity is

c = 0.01875 mol / 0.150 L  = 0.125 M

answer is 0.125 M

7 0
2 years ago
Determine the molar solubility of CuCl in a solution containing 0.050 KCl. Ksp of CuCl is 1.0 x 10-6
Volgvan

Answer:

2.0x10^{-5}\frac{mol}{L}

Explanation:

Hello!

In this case, since the dissolution of copper (I) chloride is:

CuCl(s)\rightarrow Cu^++Cl^-

And its equilibrium expression is:

Ksp=[Cu^+][Cl^-]

We can represent the molar solubility via the reaction extent as x, however, since there is 0.050 M KCl we immediately add such amount to the chloride ion concentration since KCl is readily ionized; therefore we write:

1.0x10^{-6}=(x)(0.050+x)

Thus, solving for x, we obtain:

1.0x10^{-6}=0.050x+x^2\\\\x^2+0.050x-1x10^{-6}=0

By using the quadratic equation, we obtain:

x_1=2.0x10^{-5}M\\\\x_2=-0.05M

Clearly, the solution is x_1=2.0x10^{-5}M because no negative results are

allowed. Therefore, the molar solubility is:

2.0x10^{-5}\frac{mol}{L}

Best regards!

5 0
2 years ago
When salt is introduced to water, the temperature at which freezing occurs is?
Vladimir [108]
28.4 degrees fahrenheit
5 0
2 years ago
Given the statements:
olga nikolaevna [1]
C. The salt bridge maintains the flows of ions and allows electrons to move from the anode to the cathode. 
3 0
2 years ago
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