All categories

2 years ago

How many elements are in H2CrO4

Chemistry

2 answers:

andriy [413]2 years ago

8 0

There are 7 elements

alexgriva [62]2 years ago

3 0

Answer:

3 elements

Explanation:

The elements are:

- Chromium

- Hydrogen

- Oxygen

You might be interested in

How many miles of Fe2+ ions and MnO4- ions were titrated in each part 1 trial

Fudgin [204]

Answer:

In 1000 ml there is 0.10 moles of Fe 2+

Therefore, in 10 ml there is (0.1/1000)*10= 0.001 mol of Fe2+

mole ratio for rxn Fe2+ : MnO4- is

1 : 2

therefore if 0.001 moles of Fe2+ react then 0.001*2 =0.002 moles of MnO4- react with Fe2+

hence, molarity of MnO4- = (mol*vol)/1000

= 0.002*10.75/1000= 2.15*10-5M

Explanation:

Hope this helps

5 0

2 years ago

How many structures are possible for a trigonal bipyramidal molecule with a formula of ax3y2?

ryzh [129]

Check the attached file for the answer.

4 0

1 year ago

What is the temperature change on a 75.0 gram sample of mercury if 480.0 cal of heat are added to it? The specific heat of mercu

Olegator [25]

Answer:

$\Delta T=194^oC$

Explanation:

Hello,

In this case, in terms of the heat, mass, heat capacity and change in temperature, we can analyze thermal changes as:

$Q=mCp\Delta T\\$

In such a way, we compute the required change in temperature as shown below:

$\Delta T=\frac{Q}{mCp}=\frac{480.0cal}{75.0g*0.033\frac{cal}{g^oC} } \\\\\Delta T=194^oC$

Such change in temperature is positive indicating an increase in the temperature as the involved heat is positive, in means that heat was added to increase the temperature.

Best regards.

6 0

1 year ago

A beach has a supply of sand grains composed of calcite, ferromagnesian silicate minerals, and non-ferromagnesian silicate miner

bezimeni [28]

Ferromagnesian silicate minerals (i looked it up)

4 0

1 year ago

a.) The diameter of a uranium atom is 3.50 Å . Express the radius of a uranium atom in both meters and nanometers. b.) How many

Svetradugi [14.3K]

Answer:

Th answer to your question is:

a) 3.5 x10⁻¹⁰ meters; 0.35 nm

b) 6857142.86 atoms

c) Volume = 2.06 x 10⁻²³ cm³

Explanation:

a) data

Uranium atoms = 3.5A°

meters

1 A° ---------------- 1 x 10 ⁻¹⁰ m

3.5A° --------------- x

x = 3.5(1 x10⁻¹⁰)/ 1 = 3.5 x10⁻¹⁰ meters

1 A° ------------------ 0.1 nm

3.5 A° ---------------- 0.35 nm

b) 2.4 mm

Divide 2,40 mm / uranium diameter

But, first convert 3,5A° to mm = 3.5 x 10⁻⁷ mm

# of uranium atoms = 2.4 / 3.5 x 10⁻⁷ = 6857142.86

c) volume in cubic cm

Convert 3.5A° to cm = 3.5 x 10⁻⁸

Volume = 4/3 πr³ = (4/3) (3.14)(1.7 x10⁻⁸)³

Volume = 2.06 x 10⁻²³ cm³

6 0

2 years ago