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Anarel [89]
2 years ago
11

This information is taken directly from Exercise 3 in the CHEM 111/112 Laboratory Manual. Another example of excellence in the p

resentation of data comes from a study on the cholera outbreak in London in 1854 drawn by John Snow. By overlaying the residences of the casualties on a city map that showed sources of water, the pump on Broad Street appears to be clearly implicated in the transmission of the disease." While writing a report, a student uses this source for background information about data presentation le of excellence in data presentation comes from a study of the cholera outbreak in London in 1854. John Snow created a city map that showed the residences of the casualties and sources of water. According to this map, the pump on Broad Street appears to be clearly implicated in the transmission of the disease." He uses this citation for the report: "3. Leung. T. W. Schaefer. A. ed Exercise 3: The Graphical Depiction of Scientitic Data. General Chemistry of the Texas Environment, 7th edition. 2018. 10. Was this cited correctly? O no O yes

Chemistry
1 answer:
kolbaska11 [484]2 years ago
5 0

Answer:

<h2>No</h2>

the information was not cited correctly....

Explanation:

I hope the following explanation will help you a lot.

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Which of these species are free radicals? check all that apply. check all that apply. no2 no o o2 o3?
professor190 [17]
Answer: NO2, NO, and O2.

<span>Free radicals are toxic substances produced by the body. In normal circumstances,the body can neutralize but<span> when the level of these substances is to much,they accumulate and can generate diseases, such as osteoporosis and cancer.</span></span>


4 0
2 years ago
Calculate the grams of so2 gas present at stp in a 5.9 l container. (r = 0.0821 l·atm/k·mol)
Neko [114]
There is an exact value for the standard volume at standard conditions of 1 atm and 273 K. This standard volume for any ideal gas is 22.4 L/mol. Thus,

Moles SO₂ = 5.9 L * 1 mol/22.4 L = 0.263 mol

The molar mass for SO₂ is 64.066 g/mol. So, the mass is:

Mass = 0.263 mol * 64.066 g/mol = <em>16.87 g SO₂</em>
6 0
2 years ago
For a particular reaction, the change in enthalpy is â9kJmole and the activation energy is 13kJmole. The enthalpy change (ÎH) an
Svetllana [295]

Answer:

The answer is Option a, that is "−9kJmole,5kJmole".

Explanation:

Please find the complete question in the attached file.

In the question, it uses the catalyst inside a process, which does not modify the process eigenvalues, however, it decreases the active energy with an enthalpy of -9kJmole, and also the power for activating decreases around 13 to 5 kJ mole, that's why the choice a is correct.

4 0
2 years ago
An atom of lead has a radius of and the average orbital speed of the electrons in it is about . Calculate the least possible unc
victus00 [196]

The question is incomplete. Here is the complete question.

An atom of lead has a radius of 154 pm and the average orbitalspeed of the electron in it is about 1.8x10^{8} m/s. Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of lead. Write your answer as a percentage of the average speed, and round it to significant 2 digits.

Answer: v% = 0.21 m/s

Explanation: To calculate the uncertainty, use <u>Heisenberg's Uncertainty Principle</u>, which states that:  ΔpΔx≥\frac{h}{4\pi }

where h is <u>Planck's constant</u> and it is equal to 6.626.10^{-34}m²kg/s.

Since p (momentum) is p = m.v:

mΔv.Δx ≥ \frac{h}{4\pi }

Δv = \frac{h}{4\pi.x.m }

Given that: r = x = 1.54.10^{-10}m and mass of an electron is m=9.1.10^{-31}kg

Δv = \frac{6.626.10^{-34} }{4.3.14.1.54.10^{-10}.9.1.10^{-31}}

Δv = 0.0376.10^{7}

As percentage of average speed:

Δv.\frac{1}{v}.100% = \frac{0.0376.10^{7} }{1.8.10^{8} }.10² = 0.021.10 = 0.21%

The least possible uncertainty in a speed of an electron is 0.21%.

5 0
2 years ago
What does Hess's law state can be done in order to be able to react solid magnesium with oxygen gas safely (that is, without exp
aleksley [76]

Answer:

C. The reaction can be broken down and performed in steps

Explanation:

Hess's Law of Constant Heat Summation states that irrespective of the number of steps followed in a reaction, the total enthalpy change for the reaction is the sum of all enthalpy changes corresponding to all the steps in the overall reaction. The implication of this law is that  the change of enthalpy in a chemical reaction is independent of the pathway between the initial and final states of the system.

To obtain MgO safely without exposing magnesium to flame, the reaction sequence shown in the image attached may be carried out. Since the enthalpy of the overall reaction is independent of the pathway between the initial and final states of the system, the sum of the enthalpy of each step yields the enthalpy of formation of MgO.

3 0
1 year ago
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