Question

Deuterium is an isotope of hydrogen. The nucleus of a deuterium atom consists of one proton and one neutron. When two deuterium nuclei fuse, helium-3 is formed, and a neutron is emitted. Which equation illustrates this process?
2 upper H subscript 2 plus upper o subscript 2 right arrow 2 upper H subscript 2 upper O.

2 superscript 2 subscript 1 upper H right arrow superscript 3 subscript 1 H plus superscript 1 superscript 1 H.

2 superscript 1 subscript 1 upper H right arrow superscript 2 subscript 1 H plus superscript 0 subscript 1 e.

2 superscript 2 subscript 1 upper H right arrow superscript 3 subscript 2 upper H e plus superscript 1 subscript 0 n.

Answer 1

Answer:

Answer D

Explanation:

Just took the test

Answer 2

Answer: The nuclear fusion reaction of two deuterium nucleus to form He-3 nucleus is $_1^2\textrm{H}+_1^2\textrm{H}\rightarrow _2^3\textrm{He}+_0^1\textrm{n}$

Explanation:

Nuclear fusion reactions are defined as the reaction in which, two or more lighter atoms combine to form a heavier atom. The number of atoms formed in this reaction decreases from the given atoms.

The nuclear equation for the fusion of two deuterium nucleus follows:

$_1^2\textrm{H}+_1^2\textrm{H}\rightarrow _2^3\textrm{He}+_0^1\textrm{n}$

Hence, the nuclear fusion reaction of two deuterium nucleus is given above.