Deuterium is an isotope of hydrogen. The nucleus of a deuterium atom consists of one proton and one neutron. When two deuterium
2 answers:
<u>Answer:</u> The nuclear fusion reaction of two deuterium nucleus to form He-3 nucleus is
<u>Explanation:</u>
Nuclear fusion reactions are defined as the reaction in which, two or more lighter atoms combine to form a heavier atom. The number of atoms formed in this reaction decreases from the given atoms.
The nuclear equation for the fusion of two deuterium nucleus follows:
Hence, the nuclear fusion reaction of two deuterium nucleus is given above.
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Answer: The molecular of the compound is,
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.
We are given:
Mass of
Mass of
We know that:
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44 g of carbon dioxide, 12 g of carbon is contained.
So, in of carbon dioxide,
of carbon will be contained.
For calculating the mass of hydrogen:
In 18 g of water, 2 g of hydrogen is contained.
So, in of water,
of hydrogen will be contained.
For calculating the mass of oxygen:
Mass of oxygen in the compound =
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen =
Moles of Oxygen =
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is moles.
For Carbon =
For Hydrogen =
For Oxygen =
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H : O = 2 : 3 : 1
Hence, the empirical formula for the given compound is
The empirical formula weight = 2(12) + 3(1) + 1(16) = 43 gram/eq
Now we have to calculate the molecular formula of the compound.
Formula used :
Molecular formula =
Therefore, the molecular of the compound is,
Answer:
Explanation:
Given , molarity of glycerol=
Volume= 1 L.
Therefore, No of moles of glycerol=
Now, volume of water needed, V=998.8 mL.
Density is given as= 0.9982 g/mL.
Therefore, mass of water =
Now, molality=
Hence, this is the required solution.
Answer:
a. 123.9°C
b.
c.
Explanation:
Hello, I'm attaching a picture with the numerical development of this exercise.
a. Since the steam is overheated vapour, the specific volume is gotten from the corresponding table. Then, as it became a saturated vapour, we look for the interval in which the same volume of state 1 is, then we interpolate and get the temperature.
b. Now, at 80°C, since it is about a rigid tank (constant volume for every thermodynamic process), the specific volume of the mixture is 0.79645 m^3/kg as well, so the specific volume for the liquid and the vapour are taken into account to get the quality of 0.234.
c. Now,since this is an isocoric process, the heat transfer per kg of steam is computed as the difference in the internal energy, considering the initial condition (showed in a. part) and the final one computed here.
** The thermodynamic data were obtained from Cengel's thermodynamics book 7th edition.
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