Answer:
Zn(OH)₂
<em>Explanation:
</em>
Zn is above Fe in the activity series, so it is more readily oxidized:
Zn(s) ⟶ Zn²⁺(aq) + 2e⁻
The zinc ions go into solution.
The electrons travel from the Zn to the surface of the iron nail, where they reduce the water to hydrogen and hydroxide ions.
2H₂O(ℓ) + 2e⁻ ⟶ H₂(g) + 2OH⁻(aq)
Neither the zinc ions nor the hydroxide ions can move far through the gel.
Their concentration builds up around the hail. The ions find each other and form a precipitate.
Zn²⁺(aq) + 2OH⁻(aq) ⟶ Zn(OH)₂(s)
<u>Answer:</u> Zinc will react with lead (II) nitrate solution.
<u>Explanation:</u>
Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.
The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.
General equation for single displacement reaction follows:

When zinc is reacted with calcium nitrate, the reaction does not take place as zinc is less reactive than calcium. Zinc lies below in the series than calcium.

But, when zinc is reacted with lead (II) nitrate, the reaction do take place as zinc is more reactive than lead. Zinc lies above in the series than lead.
The chemical equation for the reaction of zinc and lead (II) nitrate follows:

Hence, zinc will react with lead (II) nitrate solution.
Answer:
"statement 2" for the first pair and "statement 1" for the second pair
Explanation:
When we have the balanced equation for this reaction:
AB3 ↔ A+3 + 3B-
So we can get Ksp:
when Ksp = [A+3][B-]^3
when [A+3] = 0.047 mol and from the balanced equation when
1 mol [A+3] → 3 mol [B-]
0.047 [A+3] → ??
[B-] = 3*0.047 = 0.141
so by substitution in Ksp formula:
∴Ksp = 0.047 * 0.141^3
= 1.32x10^-4
Answer:
6.696 g/cm3
Explanation:
From the question;
Mass = 17.41g
Volume of water before = 46.3 cm3
Volume of water after = 48.9 cm3
Volume of antimony = Volume after - Volume before = 48.9 - 46.3 = 2.6 cm3
Density = Mass / Volume
Density = 17.41 / 2.6 = 6.696 g/cm3