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Hunter-Best [27]
2 years ago
6

How many moles of CaCO3 are needed to get 2.35 moles of CaO

Chemistry
1 answer:
GrogVix [38]2 years ago
7 0

I'm pretty sure its 30.6 grams of CA

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In a fixed cylinder are 3moles of oxygen gas at 300Kelvin and 1.25atm. What is the volume of the container?
vladimir2022 [97]

Answer:

The volume of the container is 59.112 L

Explanation:

Given that,

Number of moles of Oxygen, n = 3

Temperature of the gas, T = 300 K

Pressure of the gas, P = 1.25 atm

We need to find the volume of the container. For a gas, we know that,

PV = nRT

V is volume

R is gas constant, R =  0.0821 atm-L/mol-K

So,

V=\dfrac{nRT}{P}\\\\V=\dfrac{3\ mol\times 0.0821\ L-atm/mol-K \times 300\ K}{1.25\ atm}\\\\V=59.112\ L

So, the volume of the container is 59.112 L

6 0
1 year ago
Green light has a frequency of 6.01*10^14 Hz. What is the wavelength?
NemiM [27]
<span>λν = c

c= speed of light= 3.0x10^8 m/s
</span>λ=wavelength
v= frequency

Plug and Chug. 
8 0
1 year ago
Which equation illustrates conservation of mass?
pochemuha
Answer = c


Conservation of mass (mass is never lost or gained in chemical reactions), during chemical reaction no particles are created or destroyed, the atoms are rearranged from the reactants to the products.
4 0
1 year ago
Read 2 more answers
Which of the following contributes the most hydronium ions to a solution? weak acid strong acid weak base strong base
zavuch27 [327]
The correct answer is the second option. A strong acid contributes the most hydronium ions in a solution. When an acid is in aqueous form, it dissociates into ions namely where one of the ions are hydronium ions. If the acid is a strong one, the ions dissociates completely contributing more hydronium ions.
4 0
1 year ago
An old sample of concentrated sulfuric acid to be used in the laboratory is approximately 98.1 percent h2so4 by mass. calculate
Airida [17]
Basis: 100 mL solution

From the given density, we calculate for the mass of the solution.

                        density  = mass / volume
                        mass = density x volume

                       mass = (1.83 g/mL) x (100 mL) = 183 grams

Then, we calculate for the mass H2SO4 given the percentage.
                   
                      mass of H2SO4 = (183 grams) x (0.981) = 179.523 grams

Calculate for the number of moles of H2SO4,
                  moles H2SO4 = (179.523 grams) / (98.079 g/mol)
                        moles H2SO4 = 1.83 moles

Molarity:
                     M = moles H2SO4 / volume solution (in L)
                         = 1.83 moles / (0.1L ) = 18.3 M

Molality:
                     m = moles of H2SO4 / kg of solvent
                        = 1.83 moles / (183 g)(1-0.983)(1 kg/ 1000 g) = 588.24 m
8 0
2 years ago
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