Answer : The percent difference between the ideal and real gas is, 4.06 %.
Explanation : Given,
Ideal pressure (true value) = 49.3 atm
Real pressure (measured value) = 47.3 atm
The formula used to calculate percent difference is :
Percent difference =
Percent difference =
Percent difference = 4.06 %
Therefore, the percent difference between the ideal and real gas is, 4.06 %.
Answer: The weight/weight % or percent by mass of the solute is 5.41 %.
Explanation:
Mass of the sodium sulfate,w = 9.74 g
Volume of the water = 165 mL
Density of the water = 1 g/mL
Mass of the water =
Mass of the solution, W:
Mass of solute + Mass of solvent =9.47 g + 165 g=174.47 g
The weight/weight % or percent by mass of the solute is 5.41 %.
Answer : The molarity of solution is, 1.00 M
Explanation : Given,
Moles of = 0.500 mol
Volume of solution = 0.500 L
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the molarity of solution is, 1.00 M
Answer:
The final pressure is approximately 0.78 atm
Explanation:
The original temperature of the gas, T₁ = 263.0 K
The final temperature of the gas, T₂ = 298.0 K
The original volume of the gas, V₁ = 24.0 liters
The final volume of the gas, V₂ = 35.0 liters
The original pressure of the gas, P₁ = 1.00 atm
Let P₂ represent the final pressure, we get;
∴ The final pressure P₂ ≈ 0.78 atm.