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Nimfa-mama [501]
2 years ago
14

If the composition of the reaction mixture at 400 k is [brcl] = 0.00415 m, [br2] = 0.00366 m, and [cl2] = 0.000672 m, what is th

e reaction quotient, q?
Chemistry
1 answer:
Scorpion4ik [409]2 years ago
7 0
Q is unlike K value it describes the reaction that is not at equilibrium.
by considering this reaction:
aA+ bB⇄ cC
and our reaction is:
Br2 + Cl2 ⇄ 2 BrCl

According to Q low:
Q= concentration of products/concentration of reactants
but this equation in the gaseous or aqueous states only.
∴ Q = [BrCl]^2 / [Br2] [Cl2]

and we have [Br2] = 0.00366 m  [Cl2]= 0.000672 m  [BrCl] = 0.00415 m

by substitution:
                          = [0.00415]^2 / ( [0.00366] * [0.000672])
             ∴   Q   = 7
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Hafnium has six naturally occurring isotopes: 0.16% of 174Hf, with an atomic weight of 173.940 amu; 5.26% of 176Hf, with an atom
ser-zykov [4K]

Answer:

177.277amu

Explanation:

the total occuring isotopes for Hafnium is =6.

First isotope had an atomic weight of 173.940amu

Second isotope =175.941amu

Third isotope =176.943amu

Fourth isotope=177.944amu

Fifth isotope. =178.946amu

sixth isotope .179.947amu

<em>Avera</em><em>ge</em><em> </em><em>ato</em><em>mic</em><em> </em><em>wei</em><em>ght</em><em> </em><em>of</em><em> </em><em>Haf</em><em>nium</em><em>=</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>the </em><em>atomi</em><em>c</em><em> </em><em>weights</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>iso</em><em>topes</em><em>/</em><em> </em><em>Tota</em><em>l</em><em> </em><em>occu</em><em>ring</em><em> </em><em>isotopes</em>

Thus, 173.940amu+175.941amu+176.943amu+177.944amu+178.946amu+179.947amu.= 1063.661amu

Average atomic weight= 1063.661amu /6 = 177.2768333amu

= 177.277amu to 3 decimal places.

6 0
2 years ago
If Maria winks exactly 5 times every minute while she is awake and she sleeps exactly 8 hours a day, how many times does Maria w
irina1246 [14]
24 minus 8 is 16
5 times 60 is 300
300 times 16 is 4800.
She winks 4800 times a day
5 0
2 years ago
In an experiment, a scientist compares the effect of adding acid rain to
lilavasa [31]

Lake Minnetonka in Southern Minneosta is buffer solution

Explanation:

One can conclude from the observation that Lake Minnetonka is a buffer solution. A buffer solution is a special solution that resist changes in pH or pOH when a small amount of an acid or base is added.

  • Buffers are solutions in equilibrium with a fairly constant pH.
  • They are  aqueous solutions containing weak acids and their salts or weak bases and their salts.
  • Since the pH of water sample from Lake Minnetonka did not change, it is a buffer.

Learn more:

buffer brainly.com/question/4431162

blood as a buffer brainly.com/question/12855542

#learnwithBrainly

3 0
2 years ago
Read 2 more answers
What is the net cell reaction for the iron-silver voltaic cell?
RSB [31]
The net cell reaction for the iron-silver voltaic cell would be:

<span>3Ag+ + Fe --------> 3Ag + Fe3+
</span>
wherein it comes from the reaction of the cathode and the anode:

<span>Ag+ + e- -------> Ag, for the cathode and;
</span>
<span>Fe -------> Fe3+ + 3e-, for the anode
</span>
When both equations would be multiplied, the it would now yield the balanced net reaction as stated above.
4 0
2 years ago
Which of the following gives the molarity of a 17.0% by mass solution of sodium acetate, CH 3COONa (molar mass = 82.0 g/mol) in
weeeeeb [17]

Answer:

The molarity of this solution is 2.26 M (option D)

Explanation:

Step 1: Data given

Mass % = 17%

Molar mass of CH3COONa = 82.0 g/mol

Density of the solution = 1.09 g/mL

Step 2:

Assume the mass of the solution is 1.00 gram

⇒ 17.0 % CH3COONa = 0.17 grams

⇒ 83.0 % H2O = 0.83 grams

Step 3:

Density = 1.09 g/mL

Volume of the solution = total mass / density of solution

Volume of solution : 1.00 grams / 1.09 g/mL

Volume of the solution = 0.917 mL = 0.000917 L

Step 4: Calculate  number of moles of CH3COONa

Number of moles = Mass / molar mass

Number of moles CH3COONa = 0.170 grams / 82.0 g/mol

Number of moles = CH3COONa = 0.00207 moles

Step 5: Calculate molarity

Molarity = moles / volume

Molarity solution =   0.00207 / 0.000917 L

Molarity solution =  2.26 mol/L = 2.26 M

The molarity of this solution is 2.26 M (option D)

6 0
2 years ago
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