Answer:

Explanation:
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In this case, since we have grams of iron (III) oxide whose molar mass is 159.69 g/mol are able to compute the produced grams of iron by using its atomic mass that is 55.845 g/mol and their 2:4 molar ratio in the chemical reaction:

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Answer is: A. Chemical energy to electromagnetic energy and thermal energy.
Balanced chemical reaction: 2Mg(s) + O₂(g) → 2MgO(s) + energy.
This is chemical change (chemical reaction), because new substance (magnesium oxide MgO) is formed, the atoms are rearranged and the reaction is followed by an energy change (exothermic reaction because energy is released).
Chemical changes (chemical synthesis) is when a substance combines with another (in this example magnesium and oxygen) to form a new substance.
Explanation:
It is known that in one day there are 24 hours. Hence, number of seconds in 24 hours are as follows.

Hence, total charge passed daily is calculated as follows.

And, number of Faraday of charge is as follows.

= 134300.52 F
The oxidation state of aluminium in
is +3.

So, if we have to produce 1 mole of Al(s) we need 3 Faraday of charge.
Therefore, from 134300.52 F the moles of Al obtained with 89% efficiency is calculated as follows.

= 39842.487 mol
or, = 
Molar mass of Al = 27 g/mol
Therefore, mass in gram will be calculated as follows.
Mass in grams = 
= 
= 1075.7 kg/day
Thus, we can conclude that the daily aluminum production of given aluminium is 1075.7 kg/day.
The final temperature of the water is the equilibrium temperature, or the also the final temperature of the iron after a long period of time. Applying the conservation of energy:
m,iron*C,iron*ΔT = - m,water*C,water*ΔT
The density of water is 1000 g/mL.
(25 g)(0.449 J/g·°C)(T - 398 K) = - (25 mL)(1000 g/mL)(4.18 J/g·°C)(T - 298)
Solving for T,
<em>T = 298.01 K</em>