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Andreas93 [3]
2 years ago
9

A 100. mL sample of 0.200 M aqueous hydrochloric acid is added to 100. mL of 0.200 M aqueous ammonia in a calorimeter whose heat

capacity (excluding any water) is 480. J/K. The following reaction occurs when the two solutions are mixed. HCl(aq) + NH3(aq) → NH4Cl(aq) The temperature increase is 2.34°C. Calculate ΔH per mole of HCl and NH3 reacted.
Chemistry
1 answer:
Free_Kalibri [48]2 years ago
8 0

Answer:

-154KJ/mol

Explanation:

mole of 100ml sample of 0.2M aqueous HCl = Molarity × volume in Liter

= 0.2 × 100 / 1000  ( 1L = 1000 ml) = 0.02 mol and 0.02 mole of HCl solution require 0.02 mole of ammonia according to the mole ratio in the balanced equation.

Heat loss by the reaction = heat gain by calorimeter = mcΔT + 480 J/K

where m is the mass of water = 100g + 100g = 200g since mass of 100ml of water = 100g and it is in both of them and specific heat capacity of water 4.184 J/gK

heat gain by calorimeter  = (4.184 × 200 + 480) × 2.34 = 3081.3 J

ΔH per mole = heat loss / number of mole = 3081.3 / 0.02 = 154065.6 = -154KJ/mol

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</span>There are three types of mutations:
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3 0
2 years ago
When a complex ion forms, ______________ arrange themselves around _________, creating a new ion with a charge equal to the sum
alisha [4.7K]

Answer:

lignands, the central atom/metal ion

Explanation:

7 0
2 years ago
A 251 g strip of glass wool is used to insulate a reaction flask. During the reaction the temperature of the glass wool increase
Ivahew [28]

Answer:

8.9 KJ

Explanation:

Given data:

Mass of strip = 251 g

Initial temperature = 22.8 °C

Final temperature = 75.9 °C

Specific heat  capacity of granite = 0.67 j/g.°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 75.9 °C - 22.8 °C

ΔT = 53.1 °C

Q = 251 g × 0.67 j/g.°C × 53.1 °C

Q = 8929.8 J

Jolue to KJ.

8929.8J ×1 KJ / 1000 J

8.9 KJ

8 0
2 years ago
CuSO4(aq) + 2NaOH(aq) Cu(OH)2(s) + Na2SO4(aq)
REY [17]
Your answer is right.

Important elements to consider:

- to use the balanced equation (which you did)
- divide the masses of each compound by the correspondant molar masses (which you did)
- compare the theoretical proportions with the current proportions

Theoretical: 2 mol of Na OH : 1 mol of CuSO4
Then 4 mol of NaOH need 2 mol of CUSO4.

Given that you have more than 2 mol of of CUSO4 you have plenty of it and the NaOH will consume first, being this the limiting reagent.

6 0
2 years ago
How many atoms of S are in 98.0 grams of hydrosulfuric acid?
noname [10]
<h2>Answer:6.022\times 10^{23}</h2>

Explanation:

The formula for sulphuric acid is H_{2}SO_{4}.

Molecular mass of sulphuric acid is 2(2)+32+16(4)=98g

given weight=98g

Number of moles of sulphuric acid given is \frac{\text{given weight}}{molar mass}=\frac{98}{98}=1

The formula indicates that one mole of H_{2}SO_{4} contains 2 moles of H atoms,1 mole of S atoms,4 moles of O atoms.

So,the compound contains 1 mole of sulphur atoms.

1 mole of sulphur has 6.022\times 10^{23} atoms

7 0
2 years ago
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