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Serjik [45]
2 years ago
12

2) Of the following, which has the shortest de Broglie wavelength? A) an airplane moving at a velocity of 300 mph B) a helium nu

cleus moving at a velocity of 1000 mph C) a nitrogen molecule moving at a velocity of 1000 mph D) a nitrogen molecule moving at a velocity of 5000 mph
Chemistry
1 answer:
8090 [49]2 years ago
5 0

Answer:

B) a helium nucleus moving at a velocity of 1000 mph

Explanation:

According to the De Broglie relation

λ= h/mv

h= planks constant

m= mass of the body

v= velocity of the body.

As we can see from De Broglie's relation, the wavelength of matter waves depends on its mass and velocity. Hence, a very small mass moving at a very high velocity will have the greatest De Broglie wavelength.

Of all the options given, helium is the smallest matter. A velocity of 1000mph is quite high hence it will have the greatest De Broglie wavelength.

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A solution of sodium acetate (ch3coona) in water is weakly basic. <br> a. True <br> b. False
guajiro [1.7K]
Hello!

The statement that a solution of sodium acetate (CH₃COONa) is weakly basic is true:

Sodium acetate is the conjugate base of Acetic Acid. When sodium acetate is dissolved in water, it follows the equation that is shown below:

CH₃COONa(s) → CH₃COO⁻(aq) + Na⁺(aq)

Now the Acetate (CH₃COO⁻) ion, has an equilibrium in water to produce hydroxyl (OH⁻) ions and (Acetic Acid CH₃COOH)

CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻

This is a weak equilibrium, and the hydroxyl ions cause the solution to be weakly basic.

Have a nice day!
7 0
2 years ago
Iodine has a lower atomic weight than tellurium (126.90 for I, 127.60 for Te) even though it has a higher atomic number (53 for
andrew11 [14]

Answer and Explanation:

Iodine have lower atomic mass than tellurium even though the atomic number of iodine is more than the atomic number of tellurium

This is because the atomic weight of any element is the sum of number of proton and number of neutron, even though the number of proton in iodine is more so but the number of neutron is less as compared to tellurium which makes the tellurium of high atomic mass

6 0
2 years ago
Read 2 more answers
A small portion of a crystal lattice is sketched below. What is the name of the unit cell of this lattice? Your answer must be a
Nikolay [14]

This is an incomplete question, the given sketch is shown below.

Answer : The name of given unit cell is, FCC (face-centered cubic unit cell)

Explanation :

Unit cell : It is defined as the smallest 3-dimensional portion of a complete space lattice which when repeated over the and again in different directions produces the complete space lattice.

There are three types of unit cell.

  • SCC (simple-centered cubic unit cell)
  • BCC (body-centered cubic unit cell)
  • FCC (face-centered cubic unit cell)

In SCC, the atoms are arranged at the corners.

Z=\frac{1}{8}\times 8=1

The number of atoms of unit cell = Z = 1

In BCC, the atoms are arranged at the corners and the body center.

Z=\frac{1}{8}\times 8+1=2

The number of atoms of unit cell = Z = 2

The given unit cell is, FCC because the atoms are arranged at the corners and the center of the 6 faces.

Z=\frac{1}{8}\times 8+\frac{1}{2}\times 6=4

The number of atoms of unit cell = Z = 4

Thus, the name of given unit cell is, FCC (face-centered cubic unit cell)

7 0
2 years ago
The Lewis structure for CO2 has a central The Lewis structure for C O 2 has a central blank atom attached to blank atoms.
kirza4 [7]

Answer:

See the explanation

Explanation:

1) The Lewis structure for  CO_2 has a central Carbon<em> </em>atom attached to Oxygen atoms.

In the CO_2  we will have a structure:  O=C=O the <u>central atom</u> "carbon" we will have <u>2 sigma bonds and 2 pi bonds</u>, therefore, we have an <u>Sp hybridization</u>. For O we have <u>1 pi and 1 sigma bond</u>, therefore, we have an <u>Sp2 hybridization</u>.

2) These atoms are held together by <u>double bonds.</u>

<u></u>

Again in the structure of CO_2: O=C=O we only have double bonds.

3. Carbon dioxide has a Carbon dioxide has a <u>Linear</u> electron geometry.

Due to the double bonds we have to have a linear structure because in this geometry the atoms will be further apart from each other.

4. The carbon atom is <u>Sp</u> hybridized.

We will have for carbon 2 pi bonds, so we will have an <u>Sp</u> hybridization.

5. Carbon dioxide has two Carbon dioxide has two C(p) - O(p) π bonds and two C(sp) - O(Sp2) σ bonds.

(See figures)

Figure 1: Carbon hybridization

Figure 2: Oxygen hybridization

6 0
2 years ago
Ammonia (nh3(g), hf = –46.19 kj/mol) reacts with hydrogen chloride (hcl(g), hf = –92.30 kj/mol) to form ammonium chloride (nh4cl
steposvetlana [31]

Answer: The \Delta H_{rxn} for the given chemical reaction is -175.51 kJ/mol

Explanation: Enthalpy change of the reaction is defined as the amount of heat released or absorbed in a given chemical reaction.

Mathematically,

\Delta H_{rxn}=\Delta H_f_{(products)}-\Delta H_f_{(reactants)}

We are given a chemical reaction. The reaction follows:

NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)

H_f_{(NH_3)}=-46.19kJ/mol

H_f_{(HCl)}=-92.30kJ/mol

H_f_{(NH_4Cl)}=-314.4kJ/mol

Enthalpy change for the reaction of he given chemical reaction is given by:

\Delta H_{rxn}=H_f_{(NH_4Cl)}-(H_f_{(NH_3)}+H_f_{(HCl)})

Putting the values in above equation, we get

\Delta H_{rxn}=-314.4-(-92.30-46.19)kJ/mol

\Delta H_{rxn}=-175.51kJ/mol

8 0
2 years ago
Read 2 more answers
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