How many structures are possible for a trigonal bipyramidal molecule with a formula of ax3y2?

4. A sample of silicon contains 5.23 x 1011 atoms. Write this amount as a whole number.

Marat540 [252]

The answer is 523000000000

8 0

2 years ago

Jeff wants to find the volume of a gas in a cylinder. He knows that at 28°C and a pressure of 1 atm, the volume of the gas was 6

emmasim [6.3K]

Answer:

by using ideal gas law

Explanation:

ideal gas law:

PV=nRT

where:

P is pressure measured in Pascal (pa)

V is volume measured in letters (L)

n is number of moles

R is ideal gas constant

T is temperature measured in Kelvin (K)

by applying the given:

P(initial) V(initial)=nRT(initial)

P(final) V(final)=nRT(final)

nR is constant in both equations since same gas

then,

P(initial) V(initial) / T(initial) = P(final) V(final) / T(final)

then by crossing multiply both equations

V (final)= { (P(initial) V(initial) / T(initial)) T(final) } /P (final)

P(initial)=P(final)= 1 atm = 101325 pa

V(initial)= 6 L

T(initial) = 28°c = 28+273 kelvin

T(final) = 39°c = 39+273 kelvin

by substitution

V(final) = 6.21926 L

6 0

1 year ago

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NH4NO3, whose heat of solution is 25.7 kJ/mol, is one substance that can be used in cold pack. If the goal is to decrease the te

makvit [3.9K]

Answer:

There are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

Explanation:

To decrease the temperature of the solution there are necessaries:

4,184J/g°C×(5,0°C-25,0°C)×(100,0g+X) = -Y

8368J + 83,68J/gX = Y (1)

Where x are grams of NH₄NO₃ you need to add and Y is the energy that you need to decrease the heat.

Also, the energy Y will be:

Y = 25700J/mol× $\frac{1mol}{80,043g}$ X

Y = 321J/g X (2)

Replacing (2) in (1)

8368J + 83,68J/g X = 321J/g X

8363J = 237,32J/gX

X = 35,2g

Thus, there are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

I hope it helps!

6 0

2 years ago

What is the mass of 22.4 L of H2 at STP?

Vanyuwa [196]

A. 1.01 is the right answer

Since

The formula is Pv= nRT

P=1 atm

V= 22.4 L

N= x

r= 0.0821

t = 273 k (bc it’s standard temperature)

So (1)(22.4)=(x)(0.0821)(273)

X= 1.001

7 0

2 years ago

Read 2 more answers

The bond dissociation energy to break 4 bond(s) in 1 mole of CH₄ molecules is:_____ **Any help would be greatly appreciated!**

frozen [14]

Answer:

The bond dissociation energy to break 4 bonds in 1 mol of CH is 1644 kJ

Explanation:

Since there are 4 C-H bonds in CH₄, the bond dissociation energy of 1 mol of CH₄ is 4 × bond dissociation energy of one C-H bond.

From the table one mole is C-H bond requires 411 kJ, that is 411 kJ/mol. Therefore, 4 C-H bonds would require 4 × 411 kJ = 1644 kJ

So, the bond dissociation energy to break 4 bonds in 1 mol of CH₄ is 1644 kJ

5 0

2 years ago