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iogann1982 [59]
1 year ago
11

Consider this equilibrium: N2(g) + 3H2(g) 2NH3(g) + energy. Certain conditions provide less than 10% yield of NH3 at equilibrium

. Which statement describes this equilibrium?
The Keq is large and products are favored.
The Keq is small and products are favored.
The Keq is large and reactants are favored.
The Keq is small and reactants are favored.
The conditions of the reaction must be known to answer the question.
Chemistry
1 answer:
alisha [4.7K]1 year ago
5 0
The correct option is this: THE KEQ IS SMALL AND THE REACTANT ARE FAVOURED.
Since we are told in the question that the reaction give rise to only 10% product, this means that much product are not been produced, thus the reactants are favoured. Keq stands for the equilibrium constant of the reaction and it measures the rate at which the reactants are converted to products. For this reaction, the equilibrium constant is small and the backward reaction [reactant] is favoured.
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Artyom0805 [142]
Partial pressure is the amount of pressure or force that is exerted by the atoms into the outer environment. it is dependent on the temperature and pressure of the present surroundings. in this case, we are asked in this problem to determine the partial pressure of oxygen at 16oC and 1 atm. We have to look into a solubility data table commonly found in handbooks and determined via experiments and correlations. According to literature, the value of the partial pressure is equal to 0.617 mM.This is under the assumption that the salinity of the water in which oxygen is dissolved is equal to zero.
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1 year ago
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A new student is planning to use thin layer chromatography (TLC) for his research project. After setting up the apparatus the st
tamaranim1 [39]

Answer:

The open system evaporates the solvent in the solution

Explanation:

An open system is a system in which exchange of materials and energy can occur. If a TLC set up is left open, then the set up constitutes an open system.

During TLC, the sample is dotted on the plate and inserted into a suitable solvent. The solvent moves up the plate and achieves the required separation of the mixture.

Most of these solvents used used TLC are volatile organic compounds. Therefore, if the TLC set up is left open, the solvent will evaporate leading to poor results after running the TLC experiment.

7 0
2 years ago
Assuming that the experiments performed in the absence of inhibitors were conducted by adding 5 μl of a 2 mg/ml enzyme stock sol
prohojiy [21]

Hey there!:

From the given data ;

Reaction  volume = 1 mL , enzyme content = 10 ug ( 5 ug in 2 mg/mL )

Enzyme mol Wt = 45,000 , therefore [E]t is 10 ug/mL , this need to be express as "M" So:

[E]t in molar  = g/L * mol/g

[E]t  = 0.01 g/L * 1 / 45,000

[E]t = 2.22*10⁻⁷

Vmax = 0.758 umole/min/ per mL

= 758 mmole/L/min

=758000 mole/L/min => 758000 M

Therefore :

Kcat = Vmax/ [E]t

Kcat = 758000 / 2.2*10⁻⁷ M

Kcat = 3.41441 *10¹² / min

Kcat = 3.41441*10¹² / 60 per sec

Kcat = 5.7*10¹⁰ s⁻¹

Hence   kcat of   xyzase is  5.7*10¹⁰ s⁻¹


Hope that helps!



4 0
2 years ago
One of the commercial uses of sulfuric acid is the production of calcium sulfate and phosphoric acid. If 19.9 g of Ca₃(PO₄)₂ rea
Natasha_Volkova [10]

57.5 % is the percent yield if 10.9 g of H₃PO₄ is formed.

Explanation:

Balanced equation for the reaction:

Ca₃(PO₄)₂ (s) + 2H₂SO₄ (aq) → H₃PO₄ (aq) + 2CaSO₄ (aq)

data given:

mass of Ca₃(PO₄)₂ = 19.9 grams

mass of  H₂SO₄, = 54.3 grams

mass of H₃PO₄ produced = 10.9 grams (actual yield)

percent yield=?

atomic mass of Ca₃(PO₄)₂  = 310.17 grams/mole

atomic mass of H₂SO₄ = 98.07 grams/mole

number of moles is calculated as:

number of moles  = \frac{mass}{atomic mass of one mole}

putting the values in the above equation:

for Ca₃(PO₄)₂  = \frac{19.9}{310.17}

                        = 0.064 moles

moles of H₂SO₄ = \frac{54.3}{98.07}

                            = 0.55 moles

from the reaction, it can be found that the limiting reagent is Ca₃(PO₄)₂

1 mole of Ca₃(PO₄)₂ reacts to form 1 mole of phosphoric acid

0.064 moles of  Ca₃(PO₄)₂ will produce x moles of phosphoric acid

0.064 moles of phosphoric acid produced

mass = number of moles x atomic mass of  H3PO4

             =0.064 x 97.994

           = 6.27 grams (theoretical yield)

FORMULA FOR PERCENT YIELD:

percent yield = \frac{actual yield}{theoretical yield} x 100

                      = \frac{6.27}{10.9} x 100

                       = 57.5 %

7 0
2 years ago
Which of the following descriptions best describes a weak base?
Westkost [7]

Answer:

umm.. B. a base that generates a lot of hydroxide ions in water.

5 0
2 years ago
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