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rjkz [21]
2 years ago
13

Calculate the enthalpy of combustion, δh∘comb, for c6h14. you'll first need to determine the balanced chemical equation for the

combustion of c6h14. express your answer to four significant figures and include the appropriate units.
Chemistry
1 answer:
Vedmedyk [2.9K]2 years ago
3 0
<span>Answer: Enthalpy Change = (6 x -393.5) + (7 x -285.8) - (-204.6) + (19/2) 0.....??? like.. (6 x Enth CO2) + ( 7 x Enth H2O) - (Enth C6H14) + (19/2) Enth O2</span>
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Consider isotopes ions protons and electrons. how many of these did dalton not discuss in his atomic theory?
MAVERICK [17]

Answer: He did not discuss about any of these.

Explanation: Dalton proposed some of the postulates for his atomic theory. They are:

1) Matter is made up of atoms which are not divisible.

2) Atoms of different elements combine in a fixed ratio to form compounds.

3) The atomic properties of given element are same including mass. This states that all the atoms of an element have same mass but the atoms of different elements have different masses.

4) No atoms are either created or destroyed during a chemical reaction.

5) Atoms of an element are identical in mass, size and other chemical and physical properties.

As it is visible from the postulates, he only discussed only about the atoms but not subatomic particles or isotopes.

8 0
2 years ago
Adjacent water molecules interact through the ________. a. sharing of electrons between the hydrogen of one water molecule and t
Yakvenalex [24]

Answer: Option (c) is the correct answer.

Explanation:

A water molecule is made up of two hydrogen atoms and one oxygen atom. Due to the difference in electronegativity of hydrogen and oxygen, the electrons are pulled more towards oxygen atom.

As a result, a partial positive charge will develop on hydrogen atom and a partial negative charge will develop on oxygen atom.

Thus, we can conclude that adjacent water molecules interact through the  electrical attraction between the hydrogen of one water molecule and the oxygen of another water molecule.

7 0
2 years ago
The health codes cover all issues, except:
viva [34]

Answer:

the health codes would not cover the food service complaints

3 0
2 years ago
Read 2 more answers
When 9.2 g of frozen N2O4 is added to a 0.50 L reaction vessel and the vessel is heated to 400 K and allowed to come to equilibr
Amanda [17]

<u>Answer:</u> The value of K_c for the given reaction is 1.435

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

Given mass of N_2O_4 = 9.2 g

Molar mass of N_2O_4 = 92 g/mol

Volume of solution = 0.50 L

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{9.2g}{92g/mol\times 0.50L}\\\\\text{Molarity of solution}=0.20M

For the given chemical equation:

                 N_2O_4(g)\rightleftharpoons 2NO_2(g)

<u>Initial:</u>          0.20

<u>At eqllm:</u>     0.20-x        2x

We are given:

Equilibrium concentration of N_2O_4 = 0.057

Evaluating the value of 'x'

\Rightarrow (0.20-x)=0.057\\\\\Rightarrow x=0.143

The expression of K_c for above equation follows:

K_c=\frac{[NO_2]^2}{[N_2O_4]}

[NO_2]_{eq}=2x=(2\times 0.143)=0.286M

[N_2O_4]_{eq}=0.057M

Putting values in above expression, we get:

K_c=\frac{(0.286)^2}{0.143}\\\\K_c=1.435

Hence, the value of K_c for the given reaction is 1.435

6 0
2 years ago
Min is conducting an experiment where he compares the properties of water and lemonade. The first stage of the experiment is foc
vampirchik [111]

Answer: i need help

Explanation:

6 0
2 years ago
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