Using resonance, select the most acidic protons in the hexane-2,4-dione molecule. The most acidic proton is the one that, upon r
emoval, will yield the most stable conjugate base.
Check all that apply.
[Hexane-2,4-dione molecule with protons numbered as follows according to IUPAC nomenclature: protons on C1 are numbered 1 through 3, protons on C3 are numbered 4 and 5, protons on C5 are numbered 6 and 7, protons on C6 are numbered 8 through 10.]
Check all that apply.
Protons 1, 2, or 3
Protons 4 or 5
Protons 6 or 7
Protons 8, 9, or 10
Check all that apply.
[Hexane-2,4-dione molecule with protons numbered as follows according to IUPAC nomenclature: protons on C1 are numbered 1 through 3, protons on C3 are numbered 4 and 5, protons on C5 are numbered 6 and 7, protons on C6 are numbered 8 through 10.]
Check all that apply.
Protons 1, 2, or 3
Protons 4 or 5
Protons 6 or 7
Protons 8, 9, or 10
1 answer:
Answer:
Protons 4 or 5 are most acidic.
Explanation:
As mentioned there are four types of hydrogen in Hexane-2,4-dione.
The numbering are shown in the figure for your better understanding.
As shown in the figure if we remove the proton from carbon number 3 (protons number 4 or 5), it will result in formation of a carbanion. This carbanion is stabilized due to presence of -I group oxygen and there is possibility of resonance (as shown).
Thus protons 4 or 5 are most acidic.
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The Molecule of Sodium Formate along with Formal Charges (in blue) and lone pair electrons (in red) is attached below.
Sodium Formate is an ionic compound made up of a positive part (Sodium Ion) and a polyatomic anion (Formate).
Nomenclature:
In ionic compounds the positive part is named first. As sodium ion is the positive part hence, it is named first followed by the negative part i.e. formate.
Name of Formate:
Formate ion has been derived from formic acid ( the simplest carboxylic acid). When carboxylic acids looses the acidic proton of -COOH, they are converted into Carboxylate ions.
E.g.
HCOOH (formic acid) → HCOO⁻ (formate) + H⁺
H₃CCOOH (acetic acid) → H₃CCOO⁻ (acetate) + H⁺
Formal Charges:
Formal charges are calculated using following formula,
F.C = [# of Valence e⁻] - [e⁻ in lone pairs + 1/2 # of bonding electrons]
For Oxygen:
F.C = [6] - [6 + 2/2]
F.C = [6] - [6 + 1]
F.C = 6 - 7
F.C = -1
For Sodium:
F.C = [1] - [0 + 0/2]
F.C = [1] - [0]
F.C = 1 - 0
F.C = +1
