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2 years ago

A cylinder container can hold 2.45 L of water. It’s radius is 4.00 cm. What is the volume of it in cubic centimeters?

Chemistry

1 answer:

tatuchka [14]2 years ago

7 0

Answer:

2450 cm3

Explanation:

Volume of cylinder = V=πr2h

2.45L = 2450mL

1mL = 1 cm cubed

2450mL = 2450 cm cubed

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A sample of 22K gold contains the following: 22 g gold, 1.0 g silver, and 1.0 g copper. What is the percent gold in the sample?

iris [78.8K]

Answer:

35 percent

Explanation:

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2 years ago

Which parts of acetylsalicylic acid are rigid??

kolezko [41]

The correct answer of the given question above about acetylsalicylic acid would be t<span>he C double bonds with O and the ring structure are </span>rigid<span>. The parts of acetylsalicylic acid that are rigid are the C double bonds with O and the ring structure. Hope this answer helps. </span>

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2 years ago

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At a given set of conditions 241.8 kJ of heat is released when one mole of H2O forms from its elements. Under the same condition

yan [13]

Answer:

44Kj

Explanation:

These are the equations for the reaction described in the question,

Vaporization which can be defined as transition of substance from liquid phase to vapor

H2(g)+ 1/2 O2(g) ------>H2O(g). Δ H

-241.8kj -------eqn(1)

H2(g)+ 1/2 O2(g) ------>H2O(l).

Δ H =285.8kj ---------eqn(2)

But from the second equation we can see that it moves from gas to liquid, we we rewrite the equation for vaporization of water as

H2O(l) ------>>H2O(g)---------------eqn(3)

But the equation from eqn(2) the eqn does go with vaporization so we can re- write as

H2O ------> H2(g)+ 1/2 O2(g)

Δ H= 285.8kj ---------------eqn(4)

To find Delta h of the vaporization of water at these conditions, we sum up eqn(1) and eqn(4)

Δ H=285.8kj +(-241.8kj)= 44kj

5 0

2 years ago

7.00g of Compound X with molecular formula C5H10 are burned in a constant-pressure calorimeter containing 35.00kg of water at 25

horsena [70]

Answer:

The standard heat of formation of Compound X at 25°C is -3095.75 kJ/mol.

Explanation:

Mass of compound X = 7.00 g

Moles of compound X = $\frac{7.00 g}{70 g/mol}=0.100 mol$

Mass of water in calorimeter ,m= 35.00 kg = 35000 g

Change in temperature of the water in calorimeter = ΔT

ΔT = 2.113°C

Specific heat capacity of water ,c= 4.186 J/g °C

Q = m × c × ΔT

$Q=35000 g\times 4.186 J/g ^oC\times 2.113^oC=309,575.6 J=309.575 kJ$

Heat gained by 35 kg of water is equal to the heat released on burning of 0.100 moles of compound X.

Heat of formation of Compound X at 25°C:

$\frac{-Q}{\text{moles of compound X}}=\frac{-309.575 }{0.100 mol}$

= -3095.75 kJ/mol

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2 years ago

What is the enthalpy of reaction for the

nexus9112 [7]

Answer:

$\boxed{\text{656.3 kJ/mol}}$

Explanation:

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is:

$\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})$

CaCO₃(s) ⟶ CaO(s) + CO₂(g)

ΔH°f/kJ·mol⁻¹: -1207.1 -157.3 -393.5

$\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [-157.3 + (-393.5)] - (-1207.1)\\& = & -550.8 +1207.1\\& = & \textbf{656.3 kJ/mol}\\\end{array}\\\\\text{The enthalpy of decomposition is } \boxed{\textbf{656.3 kJ/mol}}$

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2 years ago

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