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givi [52]
2 years ago
10

Which number is equal to -906,060?

Chemistry
2 answers:
Eva8 [605]2 years ago
7 0

Answer:

it would be c

Explanation:

jshshsyyehdhdhdhdhdhhdhshdbdhdhfhdhdhdhd

Lyrx [107]2 years ago
5 0

<u>Answer:</u> The given number is equal to -9.0606\times 10^{5}

<u>Explanation:</u>

Scientific notation is defined as the notation in which a number is expressed in the decimal form. This means that the number is always written in the power of 10 form. The numerical digit lies between 0.1.... to 9.9.....

If the decimal is shifting to right side, the power of 10 is negative and if the decimal is shifting to left side, the power of 10 is positive.

We are given:

A quantity having a value of -906,060

Converting this into scientific notation, we get:

\Rightarrow -906,060=-9.0606\times 10^{5}

As, the decimal point is shifting to left side, thus the power of 10 is positive.

Hence, the given number is equal to -9.0606\times 10^{5}

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Morant Bay is 33 km south of Port Antonio a pigeon can fly at a speed of 1.2 m s what is the displacement of morant bay from Por
valkas [14]

Answer:

33km due south

Explanation:

Morant Bay is 33km south of Port Antonio;

  Problem: displacement of Morant bay from Port Antonio;

Displacement is a vector quantity. It is the length of path between two position and the direction inclusive.

So, it has magnitude and must be specified with a direction.

  • Therefore, the displacement of Morant Bay from Port Antonio is 33km due south.
4 0
2 years ago
What is the specific heat of an unknown substance if a 2.50 g sample releases 12 calories as its
pishuonlain [190]

Answer:

c = 4016.64 j/g.°C

Explanation:

Given data:

Mass of substance = 2.50 g

Calories release = 12 cal (12 ×4184 = 50208 j)

Initial temperature = 25°C

Final temperature = 20°C

Specific heat of substance = ?

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Solution:

Q = m.c. ΔT

ΔT  = T2 - T1

ΔT  = 20°C - 25°C

ΔT  = -5°C

50208 j = 2.50 g . c. -5°C

50208 j = -12.5 g.°C .c

50208 j /-12.5 g.°C =  c

c = 4016.64 j/g.°C

7 0
2 years ago
The percent composition by mass of a compound is 76.0% c, 12.8% h, and 11.2% o. the molar mass of this compound is 284.5 g/mol.
Leokris [45]
You have a few steps to solve this one. First, we'll find the molar mass by percentage of each element in the molecule. Then, we'll divide each of those relative masses by the atomic mass of each element. The number of times the mass divides into the relative mass is the number of atoms of that element in the molecule:

C: 284.5 x .76 = 216.22
H: 284.5 x .128= 36.416
O: 284.5 x .112 = 31.864.

Now we divide out each element's atomic mass (from the periodic table). it's okay if they're approximated from the decimal answer.
C: 216.22 ÷ 12.011 ≈ 18
H: 36.416 ÷ 1.008 ≈36
O: 31.864 ÷ 15.999 ≈ 2

Therefore, the molecular formula is C18H36O2. 

The empirical formula would be found by dividing out all factors of those subscript numbers. In our case, all of them can be divided by 2. The empirical formula would be C9H18O




7 0
2 years ago
The specific heats of two natural substances are shown in the table. Specific Heat Natural Substance Specific Heat Wet Mud 2.5 J
Novay_Z [31]

The specific heat of a substance is heat released or absorbed by one gram for a change in 1 degree celsius

so higher the specific heat, more the heat required to raise the temperature by same extent or more the heat released on decrease in temperature upto same extent (for two substance)

Here the specific heat of sandy clay is 1.4 J/g °C

So it is less than that of wet mud hence sandy clay is needs to release less energy to decrease its temperature

5 0
2 years ago
For the reaction below, Kp 5 1.16 at 800.8C. CaCO3(s) 34 CaO(s) 1 CO2(g) If a 20.0-g sample of CaCO3 is put into a 10.0-L contai
Elena L [17]

Answer:

The mass percentage of calcium carbonated reacted is 2.5%.

Explanation:

The reaction is:

CaCO_{3}(s)--->CaO(s)+CO_{2}(g)

Thus the Kp of the equilibrium will be:

Kp = partial pressure of carbon dioxide [as the other are solid]

Moles of calcium carbonate initially present = \frac{mass}{molarmass}=\frac{20}{100}=0.2

Let us apply ICE table to the equilibrium given:

                        CaCO_{3}(s)--->CaO(s)+CO_{2}(g)

Initial                       0.2                       0          0

Change                 -x                            +x        +x

Equilibrium           0.2-x                         x          x

Kp = partial pressure of carbon dioxide

Kp = Kc(RT)ⁿ

where n = difference in the number of moles of gaseous products and reactants

for given reaction n = 1

R = gas constant = 8.314 J /mol K

T = temperature = 800 ⁰C = 1073 K

Putting values

Kc =\frac{Kp}{RT}=\frac{1.16}{8.314X1073}=1.3X10^{-4}

Kc = \frac{[CO_{2}][CaO]}{[CaCO_{3}]}= \frac{x^{2} }{(0.2-x)}=1.3X10^{-4}

1.3X10^{-4}(0.2-x)=x^{2}

x^{2} = 0.26X10^{-4}-1.3X10^{-4}x

On calculating

x =  0.005

where x = the moles of calcium carbonate dissociated or reacted.

Percentage of the moles or mass reacted = \frac{molesreacted X100}{initialmoles}=\frac{0.005X100}{0.2}=2.5%

7 0
2 years ago
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