In part 2 of the experiment, you will be analyzing a sample of household bleach. A 0.0800 g sample of household bleach is comple
tely reacted with KI(s). The resulting solution is then titrated with 0.150 M NaS2O3 solution. 0.500 mL of the solution is required to reach the colorless endpoint. What is the mass percent of NaOCl (MM = 74.44 g/mole) in the bleach?
1 answer:
Answer:
The mass percent of NaOCl = 3.48%
Explanation:
The mass percent of sodium hypochlorite in household bleach is determined by an oxidation-reduction titration with sodium thiosulfate.
In this reaction, the iodide is oxidized to form aqueous iodine, I₂ (aq) Iodine is not very soluble in water but in the presence of iodide ions, it immediately converts to the tri iodide ion (I₃⁻ ) which is soluble and forms a deep yellow solution.
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Answer:
Molar mass = 3.9236 g/mol ≅ 4 g/mol
This corresponds to Helium gas.
Explanation:
Let the moles of nitrogen gas = x moles
Moles of carbon dioxide = x moles ( As both are filled at same temperature and pressure conditions )
Given:
Molar mass of nitrogen gas, = 28.014 g/mol
The formula for the calculation of moles is shown below:
Thus,
Mass of nitrogen gas = 28.014x g
So,
Let,
Similarly,
Molar mass of nitrogen gas, = 44.01 g/mol
The formula for the calculation of moles is shown below:
Thus,
Mass of nitrogen gas = 44.01x g
So,
Solving the two equations, we get :
x = 0.00943 moles
Thus, Given:
Mass of the gas = 0.037 moles
Moles = 0.00943 moles
The formula for the calculation of moles is shown below:
Thus,
Molar mass = 3.9236 g/mol ≅ 4 g/mol
This corresponds to Helium gas.