In part 2 of the experiment, you will be analyzing a sample of household bleach. A 0.0800 g sample of household bleach is comple
tely reacted with KI(s). The resulting solution is then titrated with 0.150 M NaS2O3 solution. 0.500 mL of the solution is required to reach the colorless endpoint. What is the mass percent of NaOCl (MM = 74.44 g/mole) in the bleach?
1 answer:
Answer:
The mass percent of NaOCl = 3.48%
Explanation:
The mass percent of sodium hypochlorite in household bleach is determined by an oxidation-reduction titration with sodium thiosulfate.
In this reaction, the iodide is oxidized to form aqueous iodine, I₂ (aq) Iodine is not very soluble in water but in the presence of iodide ions, it immediately converts to the tri iodide ion (I₃⁻ ) which is soluble and forms a deep yellow solution.
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Answer:
The velocity of the particle is 2 m/s,
Explanation:
Kinetic energy is defined as energy of the body due to its motion. It is given by :
Where :
m = mass of the object
v = velocity of the object
We have , particle with mass m and its kinetic energy is twice its mass.
And unit of velocity are m/s , so the velocity of the particle is 2 m/s.
0.208 is the specific heat capacity of the metal.
Explanation:
Given:
mass (m) = 63.5 grams 0R 0.0635 kg
Heat absorbed (q) = 355 Joules
Δ T (change in temperature) = 4.56 degrees or 273.15+4.56 = 268.59 K
cp (specific heat capacity) = ?
the formula used for heat absorbed and to calculate specific heat capacity of a substance will be calculated by using the equation:
q = mc Δ T
c =
c =
= 0.208 J/gm K
specific heat capacity of 0.208 J/gm K
The specific heat capacity is defined as the heat required to raise the temperature of a substance which is 1 gram. The temperature is in Kelvin and energy required is in joules.
Answer:
c) 22
Explanation:
Let's consider the following balanced equation.
N₂(g) + 3 H₂(g) ----> 2 NH₃(l)
According to the balanced equation, 34.0 g of NH₃ are produced by 1 mol of N₂. For 170 g of NH₃:
According to the balanced equation, 34.0 g of NH₃ are produced by 3 moles of H₂. For 170 g of NH₃:
The total gaseous moles before the reaction were 5.00 mol + 15.0 mol = 20.0 mol.
We can calculate the pressure (P) using the ideal gas equation.
P.V = n.R.T
where
V is the volume (50.0 L)
n is the number of moles (20.0 mol)
R is the ideal gas constant (0.08206atm.L/mol.K)
T is the absolute temperature (400.0 + 273.15 = 673.2K)