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dmitriy555 [2]
2 years ago
15

What acid chloride would be needed to prepare the following ketone from benzene using a Friedel-Crafts acylation? Click the "dra

w structure" button to launch the drawing utility.

Chemistry
1 answer:
Paraphin [41]2 years ago
3 0

Answer:

                    Benzoyl Chloride

Explanation:

                     Friedel-Craft Acylation is reaction utilized to add electrophiles (particularly carbonyl group) across double bonds of aromatic compounds.

In given case benzophenone is synthesized using benzene and benzoyl chloride.

Mechanism:

Step 1: In first step benzoyl chloride is treated with lewis acid to generate an electrophile i.e. oxo(phenyl)methylium.

Step 2: In the second step benzene undergoes electrophilic substitution reaction and adds the electrophile.

Step 3: In last step the aromaticity of benzene is restored with the elimination of proton.

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Draw the condensed structural formula in the equation for the saponification of trimyristin with koh
Ludmilka [50]

Explanation: Saponification reaction is a reaction in which hydrolysis of fats takes place under basic conditions giving glycerol and a salt of corresponding fatty acid.

We are given a Fatty acid called as Trimyristin.

Its reaction with KOH leads to the formation of soap and is given by the equation:

Trimyristin+3 KOH\rightarrow Glycerol+Soap

C_{45}H_{86}O_6+3KOH\rightarrow C_3H_5(OH)_3+3CH_3(CH_2)_{12}CO_2K

The condensed structural formula for the equation is given in the image attached.

4 0
2 years ago
Read 2 more answers
Quinine, an antimalarial drug, is 8.63% nitrogen. There are two nitrogen atoms per molecule. What is the molecular weight of qui
Furkat [3]

Answer:

324.18 g/mol

Explanation:

Let the molecular mass of the antimalarial drug, Quinine is x g/mol

According to question,

Nitrogen present in the drug is 8.63% of x

So, mass of nitrogen = \frac {8.63}{100}\times x

Also, according to the question,

2 atoms are present in 1 molecule of the drug.

Mass of nitrogen = 14.01 amu = 14.01 g/mol (grams for 1 mole)

So, mass of nitrogen = 14.01×2 = 28.02

These 2 must be equal so,

\frac {8.63}{100}\times x=28.02

solving for x, we get:

<u>x = 324.18 g/mol</u>

6 0
2 years ago
1.05 Quiz: Measure Angles
Lelechka [254]
There’s no question for me to answer ?
6 0
2 years ago
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For the reaction: MgF2(s) ⇌ Mg2+(aq) + 2F- (aq), Ksp= 6.4 × 10-9, the addition of 0.10 M NaF to the solution cause what effect o
galina1969 [7]

Answer:

Shifts the equilibrium to the left. reduces solubility.

Explanation:

  • MgF2(s) ↔ Mg2+(aq) + 2F-(aq)

          S                   S              2S

∴ Ksp = 6.4 E-9 = [ Mg2+ ] * [ F- ]² = S * (2S)²

⇒ 4S² * S = 6.4 E-9

⇒ 4S³ = 6.4 E-9

⇒ S³ = 1.6 E-9

⇒ S = 1.1696 E-3 M

  • NaF(s) → Na+(aq)  +  F-(aq)

        0.10M     0.10M        0.10M

  • MgF2(s) ↔ Mg2+(aq)  + 2F-(aq)

          S'                 S'              2S' + 0.10

⇒ Ksp = 6.4 E-9 = (S')*(2S' + 0.10)²

If we compare the concentration (0.10 M) of the ion with Ksp ( 6.4 E-9 ); thne we can neglect S' as adding:

⇒ 6.4 E-9 = (S')*(0.10)² = 0.01S'

⇒ S' = 6.4 E-7 M

∴ % S' = ( 6.4 E-7 / 0.1 )*100 = 6.4 E-4% <<< 5%, we can make the assumption

We can observe that S >> S' ( 1.1696 E-3 M >> 6.4 E-7 M ), which shows that the solubility  is reduced by the efect of the common ion from the salt, which causes the equilibrium to shift to the left, precipitating part of MgF2(s).

8 0
2 years ago
Balance the following oxidation-reduction reaction: Fe(s)+Na+(aq)→Fe2+(aq)+Na(s) Express the coefficients as integers separated
aliina [53]

Answer:

The answer to your question is: 1, 2, 1, 2

Explanation:

                       1 Fe(s)  + 2 Na⁺(aq)  → 1 Fe²⁺(aq)  + 2 Na(s)

                             Fe⁰   -   2e⁻       ⇒           Fe⁺²        Oxidases

                             Na⁺   +  1 e⁻       ⇒           Na⁰         Reduces

                      1 x ( 1 Fe⁰      ⇒         1 Fe⁺²)      Interchange number of

                      2 x ( 2Na⁺       ⇒       2 Na⁰ )      electrons

6 0
2 years ago
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