How many moles of oxygen atoms are in 132.2 g of MgSO4?
1 answer:
4.4moles of oxygen atoms
Explanation:
Given parameters:
Mass of MgSO₄ = 132.2g
Unknown:
Number of moles of oxygen atoms = ?
Solution:
The number of moles is the quantity of substance that contains the avogadro's number of particles.
To solve for this;
Number of moles =
Molar mass of MgSO₄ = 24 + 32 + 4(16) = 120g/mole
Number of moles = = 1.1 moles
In
1 moles of MgSO₄ we have 4 moles of oxygen atoms
1.1 moles of MgSO₄ contains 4 x 1.1 moles = 4.4moles of oxygen atoms
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Molecular formula: C5H10
Answer:
What mass (g) of barium iodide is contained in 188 mL of a barium iodide solution that has an iodide ion concentration of 0.532 M?
A) 19.6
B) 39.1
C) 19,600
D) 39,100
E) 276
The correct answer to the question is
B) 39.1 grams
Explanation:
To solve the question
The molarity ratio is given by
188 ml of 0.532 M solution of iodide.
Therefore we have number of moles = 0.188 × 0.532 M = 0.100016 Moles
To find the mass, we note that the Number of moles = from which we have
Mass = Number of moles × molar mass
Where the molar mass of Barium Iodide = 391.136 g/mol
= 0.100016 moles ×391.136 g/mol = 39.12 g