answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
harkovskaia [24]
2 years ago
7

A 126.1-gram block of granite at 92.6°C is dropped into a tub of water at 24.7°C in an isolated system. The final temperature of

both the granite and the water is 51.9°C. The specific heat capacity of granite is 0.795 joules/gram degree Celsius, and the specific heat capacity of water is 4.186 joules/gram degree Celsius.
The granite block transferred 1.____ of energy, and the mass of the water is 2.____ .Copy


1
A. 21,500 joules
B. 6,810 joules
C. 4,080 joulesCopy


2
A. 189 grams
B. 55.8 grams.
C. 35.8 grams
Chemistry
1 answer:
Romashka-Z-Leto [24]2 years ago
7 0

The granite block transferred <u>4080 J</u> of energy, and the mass of the water is <u>35.8 g</u>.

1. <em>Energy from granite block </em>

The formula for the heat (<em>q</em>) transferred is

<em>q = mC</em>Δ<em>T</em>

<em>m</em> = 126.1 g; <em>C</em> = 0.795 J·°C⁻¹g⁻¹; Δ<em>T</em> = <em>T</em>_f – <em>T</em>_i = 51.9 °C - 92.6 °C = -40.7 °C

∴ <em>q</em> = 126.1 g × 0.795 J·°C⁻¹g⁻¹ × (-40.7 °C) = -4080 J

The granite block transferred 4080 J.

2. <em>Mass of water </em>

<em>q = mC</em>Δ<em>T </em>

<em>m = q</em>/(<em>C</em>Δ<em>T</em>)

<em>q </em>= 4080 J; <em>C</em> = 4.186 J·°C⁻¹g⁻¹; Δ<em>T</em> = <em>T</em>_f – <em>T</em>_i = 51.9 °C – 24.7 °C = 27.2 °C

∴ <em>m</em> = 4080 J/(4.186 J·°C⁻¹g⁻¹ × 27.2 °C) = 35.8 g

The mass of the water is 35.8 g.

You might be interested in
Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produ
Kisachek [45]

<u>Answer:</u> The empirical and molecular formula for the given organic compound is C_9H_{12}O and C_{18}H_{24}O_2

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=39.01g

Mass of H_2O=10.65g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 39.01 g of carbon dioxide, \frac{12}{44}\times 39.01=10.64g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 10.65 g of water, \frac{2}{18}\times 10.65=1.18g of hydrogen will be contained.

Mass of oxygen in the compound = (13.42) - (10.64 + 1.18) = 1.6 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{10.64g}{12g/mole}=0.886moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.18g}{1g/mole}=1.18moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.6g}{16g/mole}=0.1moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.1 moles.

For Carbon = \frac{0.886}{0.1}=8.86\approx 9

For Hydrogen = \frac{1.18}{0.1}=11.8\approx 12

For Oxygen = \frac{0.1}{0.1}=1.99\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 9 : 12 : 1

The empirical formula for the given compound is C_9H_{12}O

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 272.38 g/mol

Mass of empirical formula = 136 g/mol

Putting values in above equation, we get:

n=\frac{272.38g/mol}{136g/mol}=2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(2\times 9)}H_{(2\times 12)}O_{(2\times 1)}=C_{18}H_{24}O_2

Hence, the empirical and molecular formula for the given organic compound is C_9H_{12}O and C_{18}H_{24}O_2

6 0
2 years ago
What is the mass, in grams, of 0.450 moles of Sb?
murzikaleks [220]

Answer:

54.9 g

Explanation:

0.450 mol x 122g/mol

7 0
2 years ago
Read 2 more answers
An old sample of concentrated sulfuric acid to be used in the laboratory is approximately 98.1 percent h2so4 by mass. calculate
Airida [17]
Basis: 100 mL solution

From the given density, we calculate for the mass of the solution.

                        density  = mass / volume
                        mass = density x volume

                       mass = (1.83 g/mL) x (100 mL) = 183 grams

Then, we calculate for the mass H2SO4 given the percentage.
                   
                      mass of H2SO4 = (183 grams) x (0.981) = 179.523 grams

Calculate for the number of moles of H2SO4,
                  moles H2SO4 = (179.523 grams) / (98.079 g/mol)
                        moles H2SO4 = 1.83 moles

Molarity:
                     M = moles H2SO4 / volume solution (in L)
                         = 1.83 moles / (0.1L ) = 18.3 M

Molality:
                     m = moles of H2SO4 / kg of solvent
                        = 1.83 moles / (183 g)(1-0.983)(1 kg/ 1000 g) = 588.24 m
8 0
2 years ago
Sulfur is composed of three isotopes: 32S, 33S, and 34S. The atomic masses of these isotopes are given below. 32S: 31.97207 amu
elena-14-01-66 [18.8K]

Answer:

Abundance of 32S is 94.41%

Explanation:

The average atomic mass is defined as the sum of the atomic masses of each isotope times its abundance:

Average atomic mass = ∑ Atomic mass istope*Abundance

For the sulfur:

32.07amu = 31.97207X + 32.97146Y + 33.96786*0.0422 <em>(1)</em>

<em>Where X is abundance of 32S and Y abundance of 33S</em>

Also we can write:

1 = X + Y + 0.0422 <em>(2)</em>

0.9578 - X = Y

Because the sum of the abundances = 1

Replacing (2) in (1):

32.07amu = 31.97207X + 32.97146(0.9578 - X) + 33.96786*0.0422

32.07 = 31.97207X + 31.58006 - 32.97146X + 1.43344

-0.9435 = -0.99939X

0.9441  =X

In percentage, abundance of 32S is 94.41%

3 0
1 year ago
a 15.0 kg chunk of ice falls off the top of an iceberg if the chunk of ice Falls 8.00 to the surface of the water what is the ki
kvv77 [185]
When we can get the Kinetic energy from this formula KE= 1/2 M V^2and we can get the potential energy from this formula PE =  M g H
we can set that the kinetic energy at the bottom of the fall equals the potential energy at the top so, KE = PE
1/2 MV^2 = M g H
1/2 V^2 = g H
when V is the velocity, g is an acceleration of gravitational force (9.8 m^2/s) and H is the height of the fall (8 m).
∴ v^2 = 2 * 9.8 * 8 = 156.8
∴ v= √156.8 = 12.5 m/s
8 0
1 year ago
Other questions:
  • Sara tells Michael she is 160 centimeters tall, while Michael says he is 60 inches tall. If there are 2.54 centimeters in an inc
    8·1 answer
  • Why does blowing carbon dioxide gas into aqueous barium hydroxide reduce?
    8·2 answers
  • A mixture of three noble gases has a total pressure of 1.25 atm. The individual pressures exerted by neon and argon are 0.68 atm
    7·2 answers
  • The oh concentration in a 1.0 x10 3 m ba oh 2 solution is
    8·2 answers
  • A 50.0 mL sample of 0.600 M calcium hydroxide is mixed with 50.0 mL sample of 0.600 M hydrobromic acid in a Styrofoam cup. The t
    14·1 answer
  • Classify each of these reactions. 2 NaOH ( aq ) + Pb ( ClO 3 ) 2 ( aq ) ⟶ 2 NaClO 3 ( aq ) + Pb ( OH ) 2 ( s ) 2NaOH(aq)+Pb(ClO3
    13·1 answer
  • Select the correct answer. Clive finds that the water coming out of the faucet is a little muddy. He concludes that the color in
    6·1 answer
  • Why is it necessary to assign organic chemistry exclusively to the study of carbon compounds?​
    10·1 answer
  • Which postulate of Dalton’s atomic theory has not been disproved by further investigation?
    13·1 answer
  • Please hurry!!! True or false? In a chemical reaction, energy may be gained or lost but the atoms stay the same
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!