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Nataly [62]
1 year ago
14

Magnesium metal burns with a bright white flame. What conclusions can you draw about the electron transitions that can take plac

e for a magnesium atom ?
Chemistry
1 answer:
Verizon [17]1 year ago
3 0

Different wavelength are involved.

Explanation:

If magnesium burns with a bright white flame, one can conclude that different wavelengths accompany the electron transitions for the magnesium atom.

  • When an atom burns, the electrons in it are excited.
  • They give out characteristic light commensurate with their energy.
  • A white light is made up of different combinations of wavelength of radiations.
  • When we see a white light we can infer that different joined together in the emission observed.

Learn more:

Spectrum brainly.com/question/6255073

#learnwithBrainly

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Answer: 800”

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How many grams of chromium metal are plated out when a constant current of 8.00 a is passed through an aqueous solution containi
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We can solve this without a concrete formula through dimensional analysis. This works by manipulating the units such that you end up with the unit of the final answer. Manipulate them by cancelling units that appear both in the numerator and denominator side. As a result, we must be left with the units of g. The current in A or amperes is equivalent to amount of Coulombs per second. Since this involves Coulombs, we will use the Faraday's constant which is 96,500 C/mol electron. The reaction is:

Cr³⁺(aq) + 3e⁻ --> Cr(s)

This means that for every 3 moles of electron transferred, 1 mole of Chromium metal is plated. The molar mass of Cr: 52 g/mol. The solution is as follows:

Mass of Chromium metal = (8 C/s)(60 s/1 min)(160 min)(1 mol e⁻/96,500 C)(1 mol Cr/3 mol e)(52 g/mol)
<em>Mass of Chromium metal = 13.79 g</em>
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A fox spots a rabbit in a field. The fox begins to chase the rabbit, and the rabbit runs away. Which statement best describes th
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After a reaction, a new compound contains 0.73 g Mg and 0.28 g N. What is the empirical formula of this compound?
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Answer:

Mg₃N₂

Explanation:

The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound. Using molecular mass of Mg (24,305g/mol) and mass of nitrogen (14,006g/mol), moles of each element are:

0,73g × (1mol / 24,305g) = 0,03 moles of Mg

0,28g × (1mol / 14,006g) = 0,02 moles of N

Dividing each value in 0,01 to obtain natural numbers:

0,03 moles of Mg / 0,01 = 3

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Thus, empirical formula is: <em>Mg₃N₂</em>

<em></em>

I hope it helps!

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1 year ago
A student uses visible spectrophotometry to determine the concentration of CoCl2(aq) in a sample solution. First the student pre
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Answer:

4\times 10^{-9} J is the approximate energy of one photon of this light.

Explanation:

Energy of the photon can be calculated by

E=h\nu=\frac{h\times c}{\lambda}  (Planck's equation)

where,

E = energy of photon

h = Planck's constant = 6.63\times 10^{-34}Js

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E=3.9\times 10^{-19}J\approx 4\times 10^{-9} J

4\times 10^{-9} J is the approximate energy of one photon of this light.

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