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e-lub [12.9K]
2 years ago
9

To show the electron configuration for an atom, when would it be better to use an orbital notation than to use a written configu

ration with numbers, letters, and superscripts?
A.when the aim is to use less space
B.when the aim is to show electron spins
C.when the aim is to show orbital shapes in subshells
D.when the aim is to show electron distributions in shells
Chemistry
1 answer:
VikaD [51]2 years ago
8 0
The answer is <span>D.when the aim is to show electron distributions in shells. This is because there are some instances when elements don't possess a regular or normal electron configuration. There are those who have special electron configurations wherein a lower subshell isn't completely filled before occupying a higher subshell. It is best to visualize such cases using the orbital notation.</span>
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sekiranya kutu tinggal di badan arnab dan menghisap darah arnab , apakah jenis interaksi antara kutu dengan arnab ?​
MrRa [10]

Answer:

Parasitisme.

Explanation:

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8 0
2 years ago
a radiator is filled with a mixture of 3.25kg ethylene glycol (C2H6O2) in 7.75kg of water. calculate the molality of this questi
Vladimir [108]
3.25 kg in g = 3.25 * 1000 = 3250 g

Molar mass C₂H₆O₂ =  62.0 g/mol

Mass solvent = 7.75 kg

Number of moles:

n = mass solute / molar mass

n = 3250  / 62.0 

n = 52.419 moles

Molality = moles of solute / kilograms of solvent

M = 52.419 / 7.75

M = 6.7637 mol/kg

hope this helps!
5 0
2 years ago
A gas effuses 1.55 times faster than propane (C3H8)at the
stepladder [879]

Answer:  The mass of the gas is 18.3 g/mol.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{Rate_{X}}{Rate_{C_3H_8}}=1.55

\frac{Rate_{X}}{Rate_{C_3H_8}}=\sqrt{\frac{M_{C_3H_8}}{M_{X}}}

1.55=\sqrt{\frac{44}{M_{X}}

Squaring both sides and solving for M_{X}

M_{X}=18.3g/mol

Hence, the molar mas of unknown gas is 18.3 g/mol.

5 0
2 years ago
Read 2 more answers
Calculate the molar mass of a gas that diffuses three times faster than oxygen under similar conditions.
JulsSmile [24]
<span> rate 3/1= square root of 32/x
square both sides
9/1=32x
x = 32/9
= 3.6
Must be He
molar mass =4
</span>
7 0
2 years ago
Read 2 more answers
You wish to extract an organic compound from an aqueous phase into an organic layer (three to six extractions on a marco scale).
AVprozaik [17]

Answer:

Explanation:

It will be better to use solvents that are lighter than water, because their density has an influence on the miscibility . This will give you a better separation during extraction.

7 0
2 years ago
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