The new volume is 330.2 ml
<u><em>calculation</em></u>
The new volume is calculated using the Charles law formula
that is V1/T1= V2/T2
where T1= 25.0 c into kelvin = 25 +273 = 298 K
V1= 300.0 ml
T2 = 55.0 c into kelvin = 273 +55 =328 K
V2 = ? ml
make V2 the subject of the formula by multiplying both side by T2
V2= V1T2/ T1
V2 =[ (300.0 ml x 328 k) / 298 k} = 330.2 ml
Answer:
127.0665 amu
Explanation:
Firstly, to answer the question correctly, we need to access the percentage compositions of the iodine and the contaminant iodine. We can do this by placing their individual masses over the total and multiplying by 100%.
We do this as follows. Since the mass of the contaminant iodine is 1.00070g, the mass of the 129I in that particular sample will be 12.3849 - 1.00070 = 11.3842g
The percentage abundances is as follows:
Synthetic radioisotope % = 1.0007/12.3849 * 100% = 8.1%
Since there are only two constituents, the percentage abundance of the 129I would be 100 - 8.1 = 91.9%
Now, we can use these percentages to get the apparent atomic mass. We get this by multiplying the percentage abundance’s by the atomic masses of both and adding together.
That is :
[8.1/100 * 128.9050] + [91.9/100 * 126.9045] = 10.441305 + 116.6252355 = 127.0665 amu
2.10098*10^47 atoms
Because no. Of atoms = no. Of moles * avogadros no
Answer:
<h3>
</h3>
Explanation:
First balance the chemical equation:
⇄ 
two components are solid so these two will not exert any kind of pressure in the container so at equilibrium only CO2 will apply pressure on the container
Therefore only partial pressure of CO2 will be taken for the calculation of equilibrium pressure constant i.e. Kp
![K_p=[CO_2]](https://tex.z-dn.net/?f=K_p%3D%5BCO_2%5D)
![[CO_2]=p](https://tex.z-dn.net/?f=%5BCO_2%5D%3Dp)
