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Rasek [7]
2 years ago
13

The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles

of air.
First, complete the unit conversion using dimensional analysis:

A ×
B
C
= ? g Air

A:
B:
Chemistry
2 answers:
erica [24]2 years ago
8 0

A: 3.33 mol Air

B: 28.97 g Air

C: 1 mol Air

poizon [28]2 years ago
6 0
<h3>Answer:</h3>

               Mass = 96.47 g

<h3>Solution:</h3>

Data Given:

                  M.Mass  =  28.97 g.mol⁻¹

                  Moles  =  3.33 mol

                  Mass  =  ??

Formula Used:

                  Moles  =  Mass ÷ M.Mass

Solving for Mass,

                  Mass  =  Moles × M.Mass

Putting values,

                  Mass  =  3.33 mol × 28.97 g.mol⁻¹

                  Mass  =  96.4701 g

Rounding to four significant numbers,

                 Mass = 96.47 g


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A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is
e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

  • ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
2 years ago
Lithium has an atomic mass of 6.941 amu. Lithium has two common isotopes. The one isotope has a mass of 6.015 amu and a relative
koban [17]

Answer:

The atomic mass of second isotope is 7.016

Explanation:

Given data:

Average Atomic mass of lithium = 6.941 amu

Atomic mass of first isotope = 6.015 amu

Relative abundance of first isotope = 7.49%

Abundance of second isotope = ?

Atomic mass of other isotope = ?

Solution:

Total abundance = 100%

100 - 7.49 = 92.51%

percentage abundance of second isotope = 92.51%

Now we will calculate the mass if second isotope.

Average atomic mass of lithium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

6.941 = (6.015×7.49)+(x×92.51) /100

6.941 =  45.05235 + (x92.51) / 100

6.941×100 = 45.05235 + (x92.51)

694.1 - 45.05235   = (x92.51)

649.04765 = x 92.51

x = 485.583 /92.51

x = 7.016

The atomic mass of second isotope is 7.016

3 0
2 years ago
Determine the velocity of a marble (m = 8.66 g) with a wavelength of 3.46 × 10-33m.a.45.2 m/sb.11.3 m/sc.22.1 m/sd.38.8 m/se.52.
Damm [24]

Answer:

Velocity = 22.11 m/s

Explanation:

Using the equation;

λ = h / mv;

where  

λ = wavelength ( 3.46 x 10^-33 )  

m = mass of the marble ( 8.66 g )  

v = velocity ( we gotta find out )  

h = planck's constant ( 6.626 * 10^-34 )  

Making v the subject of the formula;

V = h /mλ

  =(6.626 x 10^-34 ) / 0.00866 ( 3.46 x 10^-33 )  

  = 22.1135

≈ 22.11 m/s

6 0
2 years ago
In a polar reaction mechanism, the atom that gives away electrons in a neutral nucleophile will end up as a(n):
Ray Of Light [21]

The question is incomplete, the complete question is shown in the image attached.

Answer:

Cation

Explanation:

In a polar reaction mechanism, a specie must give out electrons and another specie must accept those electrons.

The specie that gives out electrons becomes electron deficient and positively charged so we refer to such a specie as a cation.

Hence, the specie that looses electrons becomes a cation.

5 0
2 years ago
Protein x has an absorptivity of 0.4 ml·mg-1 ·cm-1 at 280 nm. What is the absorbance at 280 nm of a 2.0 mg ·ml-1 solution of pro
Evgen [1.6K]

Absorbance measures the ability of the substance to absorb light at a specific wavelength.

Absorbance is also equal to the product of molar absorptivity, path length and molar concentration.

The mathematical expression is given as:

A= \epsilon l c       (1)

where, A = absorbance

\epsilon =  molar absorptivity

l = path length

c  = molar concentration.

The above formula is said to Beer's Law.

Absorptivity of protein x  = 0.4 mLmg^{-1}cm^{-1}

Path length = 1 cm

Molar concentration = 2.0 mg mL^{-1}

Put the values in formula (1)

Absorbance at 280 nm = 0.4 mL mg^{-1}cm^{-1}\times 1 cm \times 2.0 mg mL^{-1}

= 0.8

Thus, absorbance at 280 nm = 0.8

3 0
2 years ago
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