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Rasek [7]
1 year ago
13

The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles

of air.
First, complete the unit conversion using dimensional analysis:

A ×
B
C
= ? g Air

A:
B:
Chemistry
2 answers:
erica [24]1 year ago
8 0

A: 3.33 mol Air

B: 28.97 g Air

C: 1 mol Air

poizon [28]1 year ago
6 0
<h3>Answer:</h3>

               Mass = 96.47 g

<h3>Solution:</h3>

Data Given:

                  M.Mass  =  28.97 g.mol⁻¹

                  Moles  =  3.33 mol

                  Mass  =  ??

Formula Used:

                  Moles  =  Mass ÷ M.Mass

Solving for Mass,

                  Mass  =  Moles × M.Mass

Putting values,

                  Mass  =  3.33 mol × 28.97 g.mol⁻¹

                  Mass  =  96.4701 g

Rounding to four significant numbers,

                 Mass = 96.47 g


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Write a nuclear equation to describe the spontaneous fission of 95 244 Am to form I-134 and Mo-107. Determine how many neutrons
MissTica

<u>Answer:</u> 3 neutrons are produced in the above nuclear reaction.

<u>Explanation:</u>

In a nuclear reaction, the total mass and total atomic number remains the same.

The nuclear reaction for the fission of Americium-244 isotope follows:

^{244}_{95}\textrm{Am}\rightarrow ^{134}_{53}\textrm{I}+^{107}_{42}\textrm{Mo}+Y^1_0\textrm{n}

<u>To calculate Y:</u>

Total mass on reactant side = total mass on product side

\Rightarrow 244=134+107+(Y\times 1)\\\\\Rightarrow Y=244-241=3

Hence, 3 neutrons are produced in the above nuclear reaction.

4 0
2 years ago
At equilibrium, the concentrations in this system were found to be [ N 2 ] = [ O 2 ] = 0.200 M and [ NO ] = 0.400 M . N 2 ( g )
stiks02 [169]

<u>Answer:</u> The equilibrium concentration of NO after it is re-established is 0.55 M

<u>Explanation:</u>

For the given chemical equation:

N_2(g)+O_(g)\rightleftharpoons 2NO(g)

The expression of K_{eq} for above equation follows:

K_{eq}=\frac{[NO]^2}{[N_2][O_2]}     .....(1)

We are given:

[NO]_{eq}=0.400M

[N_2]_{eq}=0.200M

[O_2]_{eq}=0.200M

Putting values in expression 1, we get:

K_{eq}=\frac{(0.400)^2}{0.200\times 0.200}\\\\K_{eq}=4

Now, the concentration of NO is added and is made to 0.700 M

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle. This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

The equilibrium will shift in backward direction.

                           N_2(g)+O_(g)\rightleftharpoons 2NO(g)

<u>Initial:</u>               0.200    0.200        0.700

<u>At eqllm:</u>      0.200+x   0.200+x     0.700-2x

Putting values in expression 1, we get:

4=\frac{(0.700-2x)^2}{(0.200+x)\times (0.200+x)}\\\\x=0.075

So, equilibrium concentration of NO after it is re-established = (0.700 - 2x) = [0.700 - 2(0.075)] = 0.55 M

Hence, the equilibrium concentration of NO after it is re-established is 0.55 M

4 0
2 years ago
When a radioactive magnesium (Mg) atom decays by emitting a positron, what is the identity of the resulting atom? A. Aluminum (A
iragen [17]

The answer is: D. Sodium (Na).

Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.

There are two types of beta decay: beta minus and beta plus.

In beta plus decay (atomic number Z is decreased by one), a proton is converted to a neutron and positron and an electron neutrino, so mass number does not change.

In this example, magnesium (atomic number 12) is converted to dosium (atomic number 11).

5 0
1 year ago
A certain liquid has a density of 2.67 g/ cm3. what is the mass of 30.5 ml of this liquid? (
lianna [129]
Hey there!

density = 2.67 g/cm³

volume = 30.5 mL

Therefore:

Mass = density * volume

Mass = 2.67 * 30.5

Mass = 81.435 g 
4 0
1 year ago
Explain why CaCl2 is likely to have properties similar to those of CaBr2
trasher [3.6K]

Answer:

Because both compounds (CaCl2 and CaBr2) contain elements (bromine and chlorine) from the same group (group 7)

Explanation:

Elements are organized into groups on the periodic table based on the number of valence electrons contained in their outermost shell. These elements in the same group i.e. same number of valence electrons, will behave in a similar manner chemically.

CaCl2 and CaBr2 are two compounds that contains elements (Chlorine and Bromine) from the same group, which is group 7. Elements in group 7 are called HALOGENS and have 7 valence electrons in their outermost shell.

Bromine (Br) and Chorine (Cl) are responsible for the similarity in the properties of CaCl2 and CaBr2 because the Chlorine and Bromine contained in them will cause them to react similarly and behave similarly in the presence of other compounds.

5 0
1 year ago
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