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Rasek [7]
1 year ago
13

The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles

of air.
First, complete the unit conversion using dimensional analysis:

A ×
B
C
= ? g Air

A:
B:
Chemistry
2 answers:
erica [24]1 year ago
8 0

A: 3.33 mol Air

B: 28.97 g Air

C: 1 mol Air

poizon [28]1 year ago
6 0
<h3>Answer:</h3>

               Mass = 96.47 g

<h3>Solution:</h3>

Data Given:

                  M.Mass  =  28.97 g.mol⁻¹

                  Moles  =  3.33 mol

                  Mass  =  ??

Formula Used:

                  Moles  =  Mass ÷ M.Mass

Solving for Mass,

                  Mass  =  Moles × M.Mass

Putting values,

                  Mass  =  3.33 mol × 28.97 g.mol⁻¹

                  Mass  =  96.4701 g

Rounding to four significant numbers,

                 Mass = 96.47 g


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Polycarbonate plastic has a density of 1.2 g/cm3 . A photo frame is constructed from two 3.0 mm sheets of polycarbonate. Each sh
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6 0
2 years ago
A sample of 8.5 g nh3 on oxidation produces 4.5 g of no. calculate the percent yield. reaction: 4 nh3 5 o2 → 4 no 6 h2o
AnnZ [28]
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5 0
2 years ago
PLEASE HELP!!!!!!!!!!!!!
lions [1.4K]

Answer:

Pd(O2C2H3)2

Explanation:

<u>Percentage composition of elements in the compound:</u>

Pd= 47.40%

O=28.50%

C=21.40%

H= 2.69%

<u>Molar mass of each element</u>

Pd= 106g/mol

O= 16g/mol

C= 12g/mol

H= 1g/mol

Step 1

Find the moles of each element in 100g sample using the formula

no. of moles(n)=mass/molar mass

<u>For Pd:</u> 47.40g/106g/mol

      n=   0.447 moles

<u>For O:</u> 28.50/16

      n= 1.78 moles

<u>For C:</u> 21.40/12

       n= 1.783 moles

<u>For H:</u> 2.69/1

     n= 2.69moles

Step 2

Now divide the no. of moles separately by the smallest number of moles. Smallest number of moles is <em>0.447</em>

Pd= 0.447/0.447

    = 1

O= 1.78/0.447

  = 3.9=4

C= 1.78/0.447

  = 3.9=4

H= 2.69/0.447

 = 6

Hence empirical formula is PdO4C4H6

The probable molecular formula is Pd(O_{2}C_{2}H_{3})2

8 0
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