<span>440 g
First, determine the volume of each sheet. And it's easier if each dimension is using the same unit of measure. So each sheet is 28 cm by 22 cm by 0.30 cm. Multiply them together
28 cm * 22 cm * 0.30 cm= 184.8 cm^3
Since we have 2 identical sheets, double the total volume
184.8 cm^3 * 2 = 369.6 cm^3
Now multiple the volume by the density
369.6 cm^3 * 1.2 g/cm^3 = 443.52 g
Round the results to 2 significant digits since all of the given figures are only 2 significant digits long.
443.52 g = 440 g</span>
<span>30.%
Determine the molar mass of NH3 and NO
Atomic weight nitrogen = 14.0067
Atomic weight hydrogen = 1.00794
Atomic weight oxygen = 15.999
Molar mass NH3 = 14.0067 + 3 * 1.00794 = 17.03052 g/mol
Molar mass NO = 14.0067 + 15.999 = 30.0057 g/mol
Moles NH3 = 8.5 / 17.03052 = 0.499103962 mol
Moles NO = 4.5 / 30.0057 = 0.149971505 mol
Looking at the balanced equation, for every mole of NH3 consumed, you should get one mole of NO. So if we had 100% yield, we should have 0.499103962 moles of NO. But we don't. The percent yield is a simple matter of division by what we did get by what we should get. So
0.149971505 / 0.499103962 = 0.300481497 = 30.0481497%
Rounding to 2 significant figures gives 30.% yield.</span>
Answer:
Pd(O2C2H3)2
Explanation:
<u>Percentage composition of elements in the compound:</u>
Pd= 47.40%
O=28.50%
C=21.40%
H= 2.69%
<u>Molar mass of each element</u>
Pd= 106g/mol
O= 16g/mol
C= 12g/mol
H= 1g/mol
Step 1
Find the moles of each element in 100g sample using the formula
no. of moles(n)=mass/molar mass
<u>For Pd:</u> 47.40g/106g/mol
n= 0.447 moles
<u>For O:</u> 28.50/16
n= 1.78 moles
<u>For C:</u> 21.40/12
n= 1.783 moles
<u>For H:</u> 2.69/1
n= 2.69moles
Step 2
Now divide the no. of moles separately by the smallest number of moles. Smallest number of moles is <em>0.447</em>
Pd= 0.447/0.447
= 1
O= 1.78/0.447
= 3.9=4
C= 1.78/0.447
= 3.9=4
H= 2.69/0.447
= 6
Hence empirical formula is PdO4C4H6
The probable molecular formula is 
The answers are the following that can be answered using the chart:
A. Which type of hurricane is expected to strike more frequently this century?
Category 4 + 5C. In general, will hurricanes likely become stronger or weaker this century?
Stronger, because there are more stronger ones thant he weaker ones that can result to hurricane.
E. Which types of hurricanes are expected to drop in frequency by more than 25% this century?
Categories 1, 2, 3