If the speed of a vehicle increases by 22%, by what factor does its kinetic energy increase?
2 answers:
Answer:
The kinetic increases by 48.84 %
Explanation:
The expression for the kinetic energy is:-
Where, m is the mass of the object
v is the velocity of the object
Let the new velocity is:- v'
v is increased by 22 %. Thus, v' = 1.22 v
So, the new kinetic energy is:-
<u>Thus, the kinetic increases by 48.84 %</u>
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Answer:
Both reaction A and reaction B are non spontaneous.
Explanation:
For a spontaneous reaction, change in gibbs free energy () should be negative.
We know, , where T is temperature in Kelvin scale.
Reaction A:
As is positive therefore the reaction is non-spontaneous.
If at a temperature T K , the reaction is spontaneous then-
or,
or,
or,
So at a temperature greater than 350 K, the reaction is spontaneous.
Reaction B:
As is positive therefore the reaction is non-spontaneous.
If at a temperature T K , the reaction is spontaneous then-
or,
or,
or,
So at a temperature greater than -16 K, the reaction is spontaneous.
Answer:
a. the maximum number of σ bonds that the atom can form is 4
b. the maximum number of p-p bonds that the atom can form is 2
Explanation:
Hybridization is the mixing of at least two nonequivalent orbitals, in this case, we have the mixing of one <em>s, 3 p </em> and <em> 2 d </em> orbitals. In hybridization the number of hybrid orbitals generated is equal to the number of pure atomic orbital, so we have 6 hybrid orbital.
The shape of this hybrid orbital is octahedral (look the attached image) , it has 4 orbital located in the plane and 2 orbital perpendicular to it.
This shape allows the formation of maximum 4 σ bond, because σ bonds are formed by orbitals overlapping end to end.
And maximum 2 p-p bonds, because p-p bonds are formed by sideways overlapping orbitals. The atom can form one with each one of the orbitals located perpendicular to the plane.
