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AfilCa [17]
2 years ago
9

The mass of a solid copper penny is 3.46 g. how many copper atoms are in the penny?

Chemistry
2 answers:
solong [7]2 years ago
3 0
3.46 g Cu 1 mol Cu 6.02*10^23 atoms Cu =
63.55 g Cu 1 mol Cu

3.28*10^22 atoms Cu






garri49 [273]2 years ago
3 0

Answer:

n° atoms = 3.275x10²² atoms

Explanation:

To do this, we need to use the molecular weight of the copper, which is 63.55 g/mol.

Now, to know the number of atoms of any compound, we use the avogadro number which is relationed to the number of moles of any compound so:

1 mol = 6.02x10²³ atoms

In order to know the atoms, we need to calculate the moles of copper with the following expression:

n = m/MW

Doing so, we have the moles, and then, use the avogadro number to calculate the atoms:

First the moles:

n = 3.46/63.55 = 0.0544 moles

Now, let's calculate the atoms:

n° atoms = n * Av. number

n° atoms = 0.0544 ¨* 6.02x10²³

n° atoms = 3.275x10²² atoms

This would be the atoms in the penny.

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1 year ago
Calculate the number of molecules in 46.0 grams of water
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Explanation:

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Like all equilibrium constants, Kw varies somewhat with temperature. Given that Kw is 3.31 × 10−13 at some temperature, compute
Artyom0805 [142]
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Complete combustion of a compound containing hydrogen and carbon produced 2.641 g of carbon dioxide and 1.442 grams of water as
klio [65]

  The empirical   formula  of hydrocarbon is C₃H₈

The  molecular formula of hydrocarbon   is C₆H₁₆


<u><em> Empirical  formula  calculation</em></u>

Hydrocarbon  contain  carbon and hydrogen

  Step 1:  find the  mass  carbon (C) in carbon dioxide (CO₂)  and hydrogen (H )  in water

mass of  of element = molar mass  of element/ molar mass molecule x total mass of    molecule

From periodic table the molar mass  of C =12,    for CO₂ = 12+( 16 x2) =44 g/mol,     for H = 1.00 g/mol,    for H₂O = (2 x1)+16 = 18 g/mol

mass of C = 12/44 x 2.641 =0.7203 g

since there are 2 atom  of H in H₂O the molar mass of H = 1 x2 = 2 g/mol

mass of H  is therefore =  2/18 x 1.442 =0.1602 g


Step 2:  find the moles of C and H

moles = mass÷ molar mass

moles of C = 0.7203 g÷ 12 g/mol = 0.060  moles

moles of H  =  0.1602÷ 1 g/mol = 0.1602 moles


Step 3: find the mole ratio  of C and H by dividing  each  mole by smallest mole ( 0.06)

for C = 0.06/0.06 =1

  For H = 0.1602/0.06 =2.67

multiply   by 3  to remove the decimal

For C = 1 x3 =3

For H = 2.67 x3 =8

therefore the empirical formula = C₃H₈


<u><em>The molecular formula calculation</em></u>

[C₃H₈]n  = 88.1 g/mol

[12 x 3)+( 1 x8)]n =88.1 g/mol

44 n = 88.1

divide both side by 44

n=2

therefore [C₃H₈]₂   = C₆H₁₆



7 0
1 year ago
Read 2 more answers
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