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podryga [215]
2 years ago
9

An experiment in chm 2045 requires students to prepare a 1.0 M aqueous solution of potassium phosphate.Jennifer fills a 1.0 lite

r volumetric flask to the calibration line with water. She then weighs out 212.3 g of potassium phosphate and adds it to the volumetric flask.Joe weighs out 212.3 g of potassium phosphate and adds it to a 1.0 liter volumetric flask. He then fills the volumetric flask to the calibration line with water.Which student has correctly prepared a 1.0 M aqueous solution of potassium phosphate?
Chemistry
1 answer:
horrorfan [7]2 years ago
6 0

Answer:

Joe correctly prepared the solution.

Explanation:

When comparing both methods, we see that the mass of potassium phosphate weighed is the same for Jennifer and Joe, so that's not a factor.

The difference lies in the fact that Jennifer added the solid to 1.0 liters of water, so<u> the final volume is higher than 1.0 L</u>, that's why t<u>he concentration will be lower than 1.0 M</u>.

The final volume of Joe's solution is 1.0 L, that's why he prepared the solution correctly.

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A 1.44-g sample of an unknown pure gas occupies a volume of 0.335 L at a pressure of and a temperature of 100.0°C. The unknown g
Zepler [3.9K]

Answer:

Xenon

Explanation:

Step 1: Given data

  • Mass (m): 1.44 g
  • Volume (V): 0.335 L
  • Pressure (P): 1.00 atm (I looked it up)
  • Temperature (T): 100.0°C

Step 2: Convert the temperature to Kelvin

K = °C + 273.15 = 100.0°C + 273.15 = 373.2 K

Step 3: Calculate the number of moles (n)

We will use the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.00 atm × 0.335 L / (0.0821 atm.L/mol.K) × 373.2 K

n = 0.0109 mol

Step 4: Calculate the molar mass of the gas

M = 1.44 g / 0.0109 mol = 132 g/mol

Step 5: Identify the gas

The gas with a molar mass of about 132 g/mol is xenon.

8 0
2 years ago
A researcher suspects that the pressure gauge on a 54.3-L gas cylinder containing nitric oxide is broken. An empty gas cylinder
mixer [17]

Answer:

Number of moles nitric acid in the cylinder is 400.539g/mol.

Explanation:

From the given,

Weight of empty gas cylinder W_{1}= 90.0 lb= 40823.3 gramsWeight of full cylinder[tex]W_{2} = 116.5 lb= 52843.511 gramsThe critical temperature = 287 KThe critical pressure 54.3 LMolar mass of nitric acid = [tex]M_{NO} = 30.01 g/mol

Number of moles nitric acid = n_{NO} =?

The mass of nitric acid in the cylinder = W_{NO}=W_{2}-W_{1}

=52843.511-40823.3 =12,020.2g

Number of moles of nitric acid =

\frac{Given\,mass}{Molar\,mass}=\frac{12,020.2}{30}=400.539g/mol

Therefore, number of moles nitric acid in the cylinder is 400.539g/mol.

3 0
2 years ago
What is the oxidation state of an individual bromine atom in kbro2?
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Since, KBrO2 is neutral so, 
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-3 + X = Zero
So, X = +3 
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Instrumental methods of analysis rely on machines.The visualization of single molecules, single biological cells, biological tissues and nanomaterials is very important and attractive approach in analytical science.
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The correct answer is 1. Lose electrons and become positive ions.


I hope my answer was beneficial to you! c:
5 0
2 years ago
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