An experiment in chm 2045 requires students to prepare a 1.0 M aqueous solution of potassium phosphate.Jennifer fills a 1.0 lite
1 answer:
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The given question is incomplete. The complete question is :
For the reaction at equilibrium, which statement correctly describes the effects of increasing pressure and adding
, respectively
a) Increasing pressure causes shift to reactants, adding causes shift to products.
b) Increasing pressure causes shift to products ,adding causes shift to reactants.
c) Increasing pressure causes shift to products, adding causes shift to products.
d) Increasing pressure causes shift to reactants,adding causes shift to reactants
Answer: Increasing pressure causes shift to reactants, adding causes shift to products.
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
For the given equation:
a) If the pressure is increased, the volume will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. As the number of moles of gas molecules is lesser at the reactant side. So, the equilibrium will shift in the left direction. i.e. towards reactants.
b) If is added, the equilibrium will shift in the direction where
is decreasing. So, the equilibrium will shift in the right direction. i.e. towards products.
Answer:
Ionic, metal, organic
Explanation:
In this case, we have to analyze each compound:
-)
In this compound, we have a non-metal atom (Cl) and a metal atom (Ca) . So, we will have a high electronegativity difference between these atoms, With this in mind, we will have an ionic bond. Ions can be produced:
The cation would be and the anion is
. So, we will have an <u>ionic compound.</u>
-)
In this case, we have a single atom. If we check the periodic table we will find this atom in the transition metals section (in the middle of the periodic table). So, this indicates that Cu (Copper) is a <u>metal.</u>
-)
In this molecule, we have single bonds between carbon and hydrogen. The electronegativity difference between C and H are not high enough to produce ions. So, with this in mind, we will have covalent bonds. This is the main characteristic of <u>organic compounds. </u> (See figure 1)
<u>Answer:</u> The empirical and molecular formula for the given organic compound is and
<u>Explanation:</u>
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.
We are given:
Mass of
Mass of
We know that:
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
- <u>For calculating the mass of carbon:</u>
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 9.06 g of carbon dioxide, of carbon will be contained.
- <u>For calculating the mass of hydrogen:</u>
In 18g of water, 2 g of hydrogen is contained.
So, in 5.58 g of water, of hydrogen will be contained.
- Mass of oxygen in the compound = (6.38) - (2.47 + 0.62) = 3.29 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen =
Moles of Oxygen =
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.206 moles.
For Carbon =
For Hydrogen =
For Oxygen =
- <u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of C : H : O = 1 : 3 : 1
Hence, the empirical formula for the given compound is
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is:
We are given:
Mass of molecular formula = 124 amu = 124 g/mol
Mass of empirical formula = 31 g/mol
Putting values in above equation, we get:
Multiplying this valency by the subscript of every element of empirical formula, we get:
Thus, the empirical and molecular formula for the given organic compound is and