Answer:
0.020 moles of
can be formed
Explanation:
1. First determine the number of moles of LiOH.
Molarity is given by the following expression:

Solving for moles of solute:
moles of solute = M * Liters of solution
Converting 175.0mL to L:

Replacing values:
moles of solute = 0.227M*0.175L
moles of solute = 0.040
Therefore there are 0.040 moles of LiOH
2. Then write the balanced chemical reaction and use the stoichiometry of the reaction to calculate the number of moles of
produced:

As the problem says that there are excess of
, the limiting reagent is the LiOH.
can be formed
Answer:
4.16L
Explanation:
From the question given, we obtained the following data:
Molarity = 0.225 M
Number of mole of KI = 0.935mole
Volume =?
Molarity = mole / Volume
Volume = mole /Molarity
Volume = 0.935/0.225
Volume = 4.16L
Therefore, 4.16L of KI is needed.
<span>NaCH3COO (s) + HCl (aq) ---> HCH3COO (aq) + NaCl (s)</span>
Answer:
Neon
Explanation:
1s² 2s² 2p⁶ 3s¹ or [Ne] 3s¹
The outer most shell is the 3s¹.
For this atom to achieve stability, if it loses the electron in the 3s shell, it would resemble an inert element with a complete octet configuration. Therefore, the atom would be like:
1s² 2s² 2p⁶ which is the configuration of Ne
Answer:
The answer to be filled in the respective blanks in question is
3 and 1
Explanation:
So, we know that the formation of cabon-dioxide mole and that of Adenosin-Tri-Phosphate (ATP) moles will be in the ratio of 3:1 i.e., three carbon-di-oxide moles and 1 ATP mole.
Therefore, we can say that one pyruvate mole when passed through citric acid cycle and pyruvate dehydrogenase yields carbon-di-oxide and ATP moles in the ratio 3:1