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Free_Kalibri [48]
2 years ago
9

Consider the dissolution of 1.50 grams of salt XY in 75.0 mL of water within a calorimeter. The temperature of the water decreas

ed by 0.93 oC. The heat capacity of the calorimeter is 42.2 J/oC. The density of the water (and the solution) is 1.00 g/mL. The specific heat capacity of the solution is 4.184 J/goC. Calculate the quantity of heat lost by the surroundings.
Chemistry
1 answer:
-BARSIC- [3]2 years ago
8 0

Answer:

The quantity of heat lost by the surroundings is 258,5J

Explanation:

The dissolution of salt XY is endothermic because the water temperature decreased.

The total heat consumed by the dissolution process is:

4,184 J/g°C × (75,0 + 1,50 g) × 0,93°C = 297,7 J

This heat is consumed by the calorimeter and by the surroundings.

The heat consumed by the calorimeter is:

42,2 J/°C × (0,93°C) = 39,2 J

That means that the quantity of heat lost by the surroundings is:

297,7J - 39,2J = <em>258,5 J</em>

I hope it helps!

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How many capsules containing 75mg of Tamiflu could be produced from 155g of star anise.?
jeyben [28]
From the question you will find that:
one capsule of tamiflu is obtained from 2.6 g of star anise.
1 capsule   = 2.6 g tamiflu
? capsules = 155 g tamiflu
by cross multiplication = \frac{(1 x 155)}{2.6} = 59 capsules
7 0
2 years ago
Where in a data table should units of measurement be shown?
Vikentia [17]
The unites of measurement in a data table should be shown in the headings of some columns.
6 0
2 years ago
Read 2 more answers
CuSO4(aq) + 2NaOH(aq) Cu(OH)2(s) + Na2SO4(aq)
REY [17]
Your answer is right.

Important elements to consider:

- to use the balanced equation (which you did)
- divide the masses of each compound by the correspondant molar masses (which you did)
- compare the theoretical proportions with the current proportions

Theoretical: 2 mol of Na OH : 1 mol of CuSO4
Then 4 mol of NaOH need 2 mol of CUSO4.

Given that you have more than 2 mol of of CUSO4 you have plenty of it and the NaOH will consume first, being this the limiting reagent.

6 0
2 years ago
Select the correct set of quantum numbers (n, l, ml, ms) for the first electron removed in the formation of a cation for stronti
matrenka [14]

Answer:

5,0,0,-1/2

Explanation:

The quantum numbers are a way to characterize the electrons, and so, identify the region that it's more probable to find it (orbital). They are:

- Principal quantum number (n): represents the shell or level, and varies from 1 to 7, and are represented by the letter K, L, M, N, O, P, and Q.

- Azimuthal quantum number (l): represents the subshell or sublevel, and is represented by 0,1,2,3.., and for the letters s, p, d, f,...

- Magnetic quantum number (ml): represents the orbital. It varies from -l to +l passing by 0. Each orbital can have 2 electrons.

- Spin quantum number (ms): represents the spin of the electron. It can be +1/2 or -1/2.

The strontium has an atomic number equal to 38, by the Linus Pauling's diagram, the electronic distribution is:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²

The valence electron is at the subshell 5s, which has only one magnetic quantum number: 0. Because it has 2 electrons, the first one has spin =1/2, and the other -1/2. So the first electron of the formation of cation has quantum numbers:

n = 5; l = 0; ml = 0; ms = -1/2

7 0
2 years ago
How many Cl- ions are there in 400.5 grams of AlCl3?
den301095 [7]

Answer:

The answer to your question is letter A

Explanation:

Process

1.- Calculate the molecular mass of AlCl₃

Al = 1 x 27 = 27

Cl = 3 x 35.5 = 106.5

AlCl₃ = 27 + 106.5 = 133.5

2.- Find the number of ions of Cl using proportions

               133.5 grams of AlCl₃ ------------- 3 ions of Chlorine

               400.5 grams of AlCl₃ ------------   x

                x = (400.5 x 3) / 133.5

                x = 9

6 0
2 years ago
Read 2 more answers
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