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fomenos
2 years ago
7

Use the periodic table to identify the element indicated by each electron configuration by typing in the chemical symbol for the

element. 1s22s22p6: 1s22s22p63s23p3: 1s22s22p63s23p64s1: 1s22s22p63s23p64s23d8: 1s22s22p63s23p64s23d104p65s24d3:
Chemistry
2 answers:
solniwko [45]2 years ago
4 0

1s22s22p6: Ne

1s22s22p63s23p3 : P

1s22s22p63s23p64s1: K

1s22s22p63s23p64s23d8: Ni

1s22s22p63s23p64s23d104p65s24d3: Nb


Marina CMI [18]2 years ago
3 0
To determine what elements are represented by the electron configuration given above, we need to know the sum of the exponents of each term or subshell involved in the configuration as this represent the atomic number of the element.

                                                                 Atomic Number          Element
<span>1s2 2s2 2p6:                                      2 + 2 + 6 = 10                         neon
1s2 2s2 2p6 3s2 3p3:            </span>2 + 2 + 6 + 2 + 3 = <span>15                  phosphorus
1s2 2s2 2p6 3s2 3p6 4s1: </span>2 + 2 + 6 + 2 + 6+1 = <span>19                    potassium
1s2 2s2 2p6 3s2 3p6 4s2 3d8:              20 + 8 =  28                    nickel
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d3:  30 + 6 + 2 +3 = 41                    niobium</span>
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Answer:

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For this reaction, we know that the max concentration of Pb(NO₃) according to the bottle is 0.999M and to ensure the other reactant in the reaction is in excess, we'll do the calculation with a Pb(NO₃) that's a bit higher, that is, 1.0M.

Knowing that Concentration in mol/L = (number of moles)/(volume in L)

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According to the reaction,

1 mole of Pb(NO₃) reacts with 1 mole of H₂SO₄

0.001 mole of Pb(NO₃) will react with 0.001×1/1 mole of H₂SO₄

Therefore number of H₂SO₄ required for the reaction and for the H₂SO₄ to be in excess is 0.001 mole of H₂SO₄

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5 0
2 years ago
Sodium oxide (Na2O) crystallizes in a structure in which the O2– ions are in a face - centered cubic lattice and the Na+ ions ar
melisa1 [442]

We have to know the number of Na⁺ ions in the unit cell.

The number of Na⁺ ions in the unit cell is (D) 8.

Sodium oxide (Na2O) crystallizes in a structure in which the O2– ions are in a face - centered cubic lattice and the Na+ ions are in tetrahedral holes.

O²⁻ ions are in a face centred cubic lattice, so the number of O²⁻ ions per unit cell is equal to 4. The number of  tetrahedral hole= 2 X 4=8. Na+ ions are present in tetrahedral holes, which indicates there are 8 number of Na+ ions in the unit cell.


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2 years ago
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mote1985 [20]
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2 years ago
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laiz [17]

Answer:

See explanation

Explanation:

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Answer:

The 1st and 4th options are correct

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Standard reduction potential which is also referred to as standard cell potential can be described as the potential difference that exist between cathode and anode of the cell. In the standard reduction potential most times the species will be reduced which is usually analysed in a reduction half reaction.

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