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fomenos
2 years ago
7

Use the periodic table to identify the element indicated by each electron configuration by typing in the chemical symbol for the

element. 1s22s22p6: 1s22s22p63s23p3: 1s22s22p63s23p64s1: 1s22s22p63s23p64s23d8: 1s22s22p63s23p64s23d104p65s24d3:
Chemistry
2 answers:
solniwko [45]2 years ago
4 0

1s22s22p6: Ne

1s22s22p63s23p3 : P

1s22s22p63s23p64s1: K

1s22s22p63s23p64s23d8: Ni

1s22s22p63s23p64s23d104p65s24d3: Nb


Marina CMI [18]2 years ago
3 0
To determine what elements are represented by the electron configuration given above, we need to know the sum of the exponents of each term or subshell involved in the configuration as this represent the atomic number of the element.

                                                                 Atomic Number          Element
<span>1s2 2s2 2p6:                                      2 + 2 + 6 = 10                         neon
1s2 2s2 2p6 3s2 3p3:            </span>2 + 2 + 6 + 2 + 3 = <span>15                  phosphorus
1s2 2s2 2p6 3s2 3p6 4s1: </span>2 + 2 + 6 + 2 + 6+1 = <span>19                    potassium
1s2 2s2 2p6 3s2 3p6 4s2 3d8:              20 + 8 =  28                    nickel
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d3:  30 + 6 + 2 +3 = 41                    niobium</span>
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Answer:

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3 0
2 years ago
It requires 0.0780L of a 0.12 M HCl solution to completely neutralize 0.0280L of an unknown LiOH solution. What is the concentra
kari74 [83]

Answer:

C₂ = 0.334 M

Explanation:

Given data:

Volume of HCl  = 0.0780 L

Concentration of HCl = 0.12 M

Volume of LiOH = 0.0280 L

Concentration of LiOH = ?

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Concentration of HCl

V₁ = Volume of HCl

C₂ = Concentration of LiOH

V₂ = Volume of LiOH

Now we will put the values in formula.

C₁V₁ = C₂V₂

0.12 M × 0.0780 L =  C₂ × 0.0280 L

0.00936  M.L = C₂ × 0.0280 L

C₂ = 0.00936 M.L/0.0280 L

C₂ = 0.334 M

4 0
2 years ago
Los automóviles actuales tienen “parachoques de 5 mi/h (8 km/h)” diseñados para comprimirse y rebotar elásticamente sin ningún d
PilotLPTM [1.2K]

Answer:

k = 23045 N/m

Explanation:

To find the spring constant, you take into account the maximum elastic potential energy that the spring can support. The kinetic energy of the car must be, at least, equal to elastic potential energy of the spring when it is compressed to its limit. Then, you have:

K=U\\\\\frac{1}{2}Mv^2=\frac{1}{2}kx^2    (1)

M: mass of the car = 1050 kg

k: spring constant = ?

v: velocity of the car = 8 km/h

x: maximum compression of the spring = 1.5 cm = 0.015m

You solve the equation (1) for k. But first you convert the velocity v to m/s:

v=8\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=2.222\frac{m}{s}

k=\frac{Mv^2}{x^2}=\frac{(1050kg)(2.222m/s)^2}{(0.015m)^2}=23045\frac{N}{m}

The spring constant is 23045 N/m

3 0
2 years ago
How much energy is required to decompose 612 g of pcl3, according to the reaction below? the molar mass of pcl3 is 137.32 g/mol
Assoli18 [71]
The reaction is:

4 PCl3 (g) ---> P4(s) + 6 Cl2(g).

Now, you need to convert the mass of PCl3 into number of moles, for which you use the molar mass of PCl3 in this way:

number of moles = number of grams / molar mass =>

number of moles of PCl3 = 612 g / 137.32 g/mol = 4.4567 moles of PCl3.

Now use the proportion with the ΔH rxn given.

4 mol PCl3 / 1207 kJ = 4.4567 mol / x => x = 4.4567 mol * 1207 kJ / 4 mol = 1,344.8 kJ = 1.34 * 10^3 kJ.

Answer: 1.34 * 10 ^3 kJ (option d)
8 0
2 years ago
Read 2 more answers
A sample of gas initially occupies 3.35 L at a pressure of 0.950 atm at 13.0oC. What will the volume (in L) be if the temperatur
Marat540 [252]

Answer: V= 3.13 L

Explanation: solution attached:

Use combine gas law equation:

P1 V1 / T1 = P2 V2/ T2

Derive to find V2

V2 = P1 V1 T2 / T1 P2

Convert temperatures in K

T1= 13.0°C + 273 = 286 K

T2= 22.5°C + 273 = 295.5 K

Substitute the values.

4 0
2 years ago
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