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fomenos
2 years ago
7

Use the periodic table to identify the element indicated by each electron configuration by typing in the chemical symbol for the

element. 1s22s22p6: 1s22s22p63s23p3: 1s22s22p63s23p64s1: 1s22s22p63s23p64s23d8: 1s22s22p63s23p64s23d104p65s24d3:
Chemistry
2 answers:
solniwko [45]2 years ago
4 0

1s22s22p6: Ne

1s22s22p63s23p3 : P

1s22s22p63s23p64s1: K

1s22s22p63s23p64s23d8: Ni

1s22s22p63s23p64s23d104p65s24d3: Nb


Marina CMI [18]2 years ago
3 0
To determine what elements are represented by the electron configuration given above, we need to know the sum of the exponents of each term or subshell involved in the configuration as this represent the atomic number of the element.

                                                                 Atomic Number          Element
<span>1s2 2s2 2p6:                                      2 + 2 + 6 = 10                         neon
1s2 2s2 2p6 3s2 3p3:            </span>2 + 2 + 6 + 2 + 3 = <span>15                  phosphorus
1s2 2s2 2p6 3s2 3p6 4s1: </span>2 + 2 + 6 + 2 + 6+1 = <span>19                    potassium
1s2 2s2 2p6 3s2 3p6 4s2 3d8:              20 + 8 =  28                    nickel
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d3:  30 + 6 + 2 +3 = 41                    niobium</span>
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Combining aqueous solutions of bai2 and na2so4 affords a precipitate of baso4. Which ions are spectator ions in the reaction?
Marina86 [1]

Answer:

I⁻ (aq) and Na⁺ (aq)

Explanation:

We have the chemical reaction:

BaI₂ + Na₂SO₄ → BaSO₄ + 2 NaI

However if you want to determine the spectator ions you need  to write the states of compounds:

(aq) - ions dissolved in water

(s) - solid

Ba²⁺ (aq) + 2 I⁻ (aq) + 2 Na⁺ (aq) + SO₄²⁻ (aq) → BaSO₄ (s) + 2 Na⁺ (aq) + 2 I⁻ (aq)

The ions which does not change the state and remains dissolved in the solution are spectator ions. For our chemical reaction we have the following spectator ions:

I⁻ (aq) and Na⁺ (aq)

3 0
2 years ago
Which statement is true? Nuclear power plants require more fuel than conventional power plants. There is a short supply of high
Bas_tet [7]
I believe the correct answer would be option 4. The only statement that is true would be that it is difficult to responsibly dispose of nuclear waste products. This is because nuclear waste products are radioactive and are very harmful to the society and to the environment. It could cause serious damage to every being in contact to it.
3 0
2 years ago
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The decantate from Question 1 that possibly contains K, Zn, or Cr, is neutralized with acetic acid and divided into the appropri
stepladder [879]

Answer:

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4 0
2 years ago
For each of the following substituents, indicate whether it withdraws electrons inductively, donates electrons by hyperconjugati
AveGali [126]

Answer:

a. withdraws electrons inductively

b. donates electrons by hyperconjugation

c. donates electrons by resonance

d.  withdraws electrons inductively

Explanation:

a.  The bromide ion is a highly electronegative ion (in the halide series). Electronegative substituents on acids increase the acidity by inductive electron withdrawal method. The higher the electronegativity of a substance, the greater the acidity. The halogens have this order of electronegativity:

F > Cl > Br>I

b.  The carboxyl groups have a stabilization of the sigma and pi bonds. This is achieved through a special delocalization of electrons.  Because of the delocalization, hyperconjugation is the result effect.

c. The NHCH₃ group has a highly electonegative nitrogen atom that pulls the electron cloud towards itself. In this case, it withdraws electrons inductively. As a result, it donates electrons by resonance.

d. The OCH₃ group has a highly electonegative oxygen atom. This oxygen atom withdraws electron cloud towards itself. As a result, it withdraws electrons inductively.

3 0
2 years ago
You are presented with a mystery as part of your practical experiment. You have a solution of Pb(NO3)2 that has a worn label mak
Orlov [11]

Answer:

Minimum volume of H₂SO₄ required for H₂SO₄ to be in excess = 0.0556 mL

Explanation:

Pb(NO₃)₂ + H₂SO₄ -----> PbSO₄ + 2HNO₃

For this reaction, we know that the max concentration of Pb(NO₃) according to the bottle is 0.999M and to ensure the other reactant in the reaction is in excess, we'll do the calculation with a Pb(NO₃) that's a bit higher, that is, 1.0M.

Knowing that Concentration in mol/L = (number of moles)/(volume in L)

Number of moles of Pb(NO₃) added = concentration in mol/L × volume in L = 1 × 0.001 = 0.001 mole

According to the reaction,

1 mole of Pb(NO₃) reacts with 1 mole of H₂SO₄

0.001 mole of Pb(NO₃) will react with 0.001×1/1 mole of H₂SO₄

Therefore number of H₂SO₄ required for the reaction and for the H₂SO₄ to be in excess is 0.001 mole of H₂SO₄

So, the concentration of commercial H₂SO₄ is usually 18.0M, using this as the assumed value.

Volume of H₂SO₄ = (number of H₂SO₄ required for it to be in excess)/(concentration of H₂SO₄)

Volume of H₂SO₄ = 0.001/18 = 0.0000556 L = 0.0556 mL.

QED!!!

5 0
2 years ago
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