Two students titrated a 25.0 mL aliquot of pear juice with 0.107 M NaOH to the phenolphthalein end point. The initial buret read
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Answer:
-) 3-bromoprop-1-ene
-) 2-bromoprop-1-ene
-) 1-bromoprop-1-ene
-) bromocyclopropane
Explanation:
In this question, we can start with the <u>I.D.H</u> (<em>hydrogen deficiency index</em>):
In the formula we have 3 carbons, 5 hydrogens, and 1 Br, so:
We have an I.D.H value of one. This indicates that we can have a cyclic structure or a double bond.
We can start with a linear structure with 3 carbon with a double bond in the first carbon and the Br atom also in the first carbon (<u>1-bromoprop-1-ene</u>). In the second structure, we can move the Br atom to the second carbon (<u>2-bromoprop-1-ene</u>), in the third structure we can move the Br to carbon 3 (<u>3-bromoprop-1-ene</u>). Finally, we can have a cyclic structure with a Br atom (<u>bromocyclopropane</u>).
See figure 1
I hope it helps!
Explanation:
For AX type ceramic material, the number of formula per unit cells is as follows.
or,
where, n' = no. of formula units per cell
= molecular weight of cation = 90.5 g/mol
= molecular weight of anion = 37.3 g/mol
= volume of cubic cell = 3.55
a = edge length of unit cell =
= Avogadro's number =
= density = 3.55
Now, putting the given values into the above formula as follows.
=
= 0.9
= 1 (approx)
Therefore, we can conclude that out of the given options crystal structure of cesium chloride is possible for this material.
57.5 % is the percent yield if 10.9 g of H₃PO₄ is formed.
Explanation:
Balanced equation for the reaction:
Ca₃(PO₄)₂ (s) + 2H₂SO₄ (aq) → H₃PO₄ (aq) + 2CaSO₄ (aq)
data given:
mass of Ca₃(PO₄)₂ = 19.9 grams
mass of H₂SO₄, = 54.3 grams
mass of H₃PO₄ produced = 10.9 grams (actual yield)
percent yield=?
atomic mass of Ca₃(PO₄)₂ = 310.17 grams/mole
atomic mass of H₂SO₄ = 98.07 grams/mole
number of moles is calculated as:
number of moles =
putting the values in the above equation:
for Ca₃(PO₄)₂ =
= 0.064 moles
moles of H₂SO₄ =
= 0.55 moles
from the reaction, it can be found that the limiting reagent is Ca₃(PO₄)₂
1 mole of Ca₃(PO₄)₂ reacts to form 1 mole of phosphoric acid
0.064 moles of Ca₃(PO₄)₂ will produce x moles of phosphoric acid
0.064 moles of phosphoric acid produced
mass = number of moles x atomic mass of H3PO4
=0.064 x 97.994
= 6.27 grams (theoretical yield)
FORMULA FOR PERCENT YIELD:
percent yield = x 100
= x 100
= 57.5 %