Answer:
Heat transferred, Q = 1542.42 J
Explanation:
Given that,
Mass of water, m = 30 grams
Initial temperature, 
Final temperature, 
We need to find the energy transferred. The energy transferred is given by :

c is specific heat of water, c = 4.18 J/g °C
So,

So, 1542.42 J of energy is transferred.
Pressure is 5.7 atm
<u>Explanation:</u>
P1 = Standard pressure = 1 atm
P2 = ?
V1 = Volume = 10L
V2= 2.4L
T1 = 0°C + 273 K = 273 K
T2 = 100°C + 273 K = 373 K
We have to find the pressure of the gas, by using the gas formula as,

P2 can be found by rewriting the above expression as,

Plugin the above values as,

Answer:
Concentration for the solution is 0.153 mol/L
Explanation:
Formula for the osmotic pressure is π = M . R . T . i
where M is molarity (concentration), R the universal constant for gases and T is Absolute T° (T°C + 273)
π = Osmotic pressure.
Let's replace the data given:
3.9 atm = M . 0.082L.atm/mol.K . 310K
3.9 atm / 0.082 mol.K/L.atm . 310K = 0.153 mol/L (M)
i = Van't Hoff factor (ions from the solute dissolved in solution)
In this case, we assumed no ion pairing, so i = 1
Answer:
The answer to your question is e. 3.99 g
Explanation:
Data
Cu₂S = 5g
theoretical yield = ?
Chemical reaction
Cu₂S + O₂ ⇒ 2Cu + SO₂
Process
1.- Calculate the molecular mass of Cu₂S and Cu
Cu₂S = (2 x 64) + 32 = 160 g
Cu = 2 x 64 = 128 g
2.- Calculate the theoretical production of Cu
160 g of Cu₂S --------------- 128 g of Cu
5 g of Cu₂S -------------- x
x = (5 x 128) / 160
x = 640 / 160
x = 4 g of Cu
Answer:
429.4 kJ are absorbed in the endothermic reaction.
Explanation:
The balanced chemical equation tells us that 1168 kJ of heat are absorbed in the reaction when 4 mol of NH₃ (g) react with 5 mol O₂ (g).
So what we need is to calculates how many moles represent 25 g NH₃(g) and calculate the heat absorbed. (NH₃ is the limiting reagent)
Molar Mass NH₃ = 17.03 g/mol
mol NH₃ = 25.00 g/ 17.03 g/mol = 1.47 mol
1168 kJ /4 mol NH₃ x 1.47 mol NH₃ = 429.4 kJ