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shepuryov [24]
2 years ago
15

The image below shows a laser that has been shot into a solid block of transparent plastic from the far left end. Once inside th

e plastic block, the light is repeatedly reflected off of the sides until it reaches the opposite end, on the right.
Image courtesy of Wikipedia

The picture above demonstrates how
A.
optical fibers transmit light signals in high-speed communications.
B.
satellites communicate with ground controllers from outer space.
C.
solar cells transform light energy into electrical energy.
D.
electricity is transmitted from a solar power plant to residential homes.

Chemistry
1 answer:
OlgaM077 [116]2 years ago
7 0

Answer:

A. Optical fibers transmit light signals in high-speed communications.  

Explanation:

You didn't include the image, but it probably showed light bouncing off the sides as in the diagram below.

It demonstrates how optical fibers transmit light signals in high-speed communications.

B is wrong. Satellites communicate by radio waves.

C is wrong. Solar cells convert light energy to  

D is wrong. Power plants transmit electrical energy to homes through copper wires.

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Tanzania [10]
Don't ever return unused chemicals to their original containers. If you do, you could be contaminating the chemical. Discard the leftover chemical in the correct waste box. Ask your teacher if your not sure about what to do.
4 0
2 years ago
Phosphine, ph3(g), combusts in oxygen gas to form water vapor and solid tetraphosphorus decaoxide. express your answer as a bala
djverab [1.8K]

Tetraphosphorus Decaoxide has a molecular formula of P4O10, all else are known. Therefore the balanced chemical equation would be:

4PH3 + 8O2 --> 6H2O + P4O10

 

Taking into account the phases:

4PH3(g) + 8O2(g) --> 6H2O(g) + P4O10(s)

6 0
2 years ago
How many molecules of glucose are in 1 l of a 100 mm glucose solution?
Karolina [17]

Answer is: 6.022·10²² molecules of glucose.

c(glucose) = 100 mM.

c(glucose) = 100 · 10⁻³ mol/L.

c(glucose) = 0.1 mol/L; concentration of glucose solution.

V(glucose) = 1 L; volume of glucose solution.

n(glucose) = c(glucose) · V(glucose).

n(glucose) = 0.1 mol/L · 1 L.

n(glucose) = 0.1 mol; amount of substance.

N(glucose) = n(glucose) · Na (Avogadro constant).

N(glucose) = 0.1 mol · 6.022·10²³ 1/mol.

N(glucose) = 6.022·10²².

6 0
2 years ago
Describe a single measurement that you could make that shows that a kettle is less than 100% efficient (providing evidence that
alexgriva [62]

Answer:

As you haven't explained what measurements you took before solving this problem, I will explain the general procedure to evaluate the efficiency of a kettle. I hope it helps you. I´ll send an attachement file with the full answer, since I couldn't write it here.

I assume that the material that is going to be heated in the kettle is water.

1- You have to boil water in it and take the time it takes to its boiling point (in seconds).  

2- You have to evaluate the amount of energy the water absorbed Q with the efficiency formula which I explain in the attachement file.

3- Divide Q by the time it took to bring the water to boiling so you can have the power it consumed.

4- You divide the last value you obtained by the Kettles's power rating.  

5- Multiply the last value by 100 to obtain a percentage value of efficiency.

Explanation:

Efficiency is the ration of a machine's useful work, in this case how much energy the water absorbed to get to its boiling point divided by the time it took to get to this point, and the total energy expended, in this case the kettles's power rating.

7 0
2 years ago
We have an object with a density of 620 g/ cm3 and a volume of 75 cm3. What is the mass of this object?
Anna11 [10]
M=D*V
D=620 g/cm³
V=75 cm³

m= 620 g/cm³ * 75 cm³=46500 g
m=46500g
8 0
2 years ago
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