Answer:
V₂ = 4.34 L
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 3.50 L
Initial pressure = 150 Kpa (150/101.325 = 1.5 atm)
Initial temperature = 330 K
Final temperature = 273 K
Final volume = ?
Final pressure = 1 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.5 atm × 3.50 L × 273 K / 330 K × 1 atm
V₂ = 1433.3 atm .L. K / 330 k.atm
V₂ = 4.34 L
O: 1*2 = 2*1
<span>H 2 + 2 = 2*2 </span>
<span>answer C hope you get it right</span>
Explanation:
The mode is the most common number.
Um = 55
The mean is the sum of the numbers divided by the quantity.
Uavg = (38 + 44 + 45 + 48 + 50 + 55 + 55 + 57 + 58 + 60) / 10
Uavg = 51
The RMS (root mean square) is the square root of the sum of the squares of the numbers divided by the quantity.
Urms = √[(38² + 44² + 45² + 48² + 50² + 55² + 55² + 57² + 58² + 60²) / 10]
Urms = 51.451
Based on Pauling Scale, electro negativity of Cl = 3.2, Na = 0.9 and H = 2.1
Thus, Electronegativity difference in

= 3.2 -3.2 = 0
Electronegativity difference in NaCl = 3.2-0.9 = 2.3
Similarly, Electronegativity difference in HCl = 3.2 - 2.1 = 1.1
Thus, among the listed molecules following is the decreasing order of electronegativity difference: NaCl> HCl >
Answer:
for this reaction at this temperature is 0.029
Explanation:
Moles of
= 2.00 mole
Volume of solution = 4.00 L
Initial concentration of
The given balanced equilibrium reaction is,

Initial conc. 0.500 M 0 M 0 M
At eqm. conc. (0.500-2x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[H_2\times [Br_2]}{[HBr]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5Ctimes%20%5BBr_2%5D%7D%7B%5BHBr%5D%5E2%7D)
Equilibrium concentration of
= x = 0.0955 M
Now put all the given values in this expression, we get :


Thus
for this reaction at this temperature is 0.029