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docker41 [41]
2 years ago
15

What is the chemical formula of trisilicon tetranitride? A. Si3N4 B. Si4N3 C. Si3N6 D. Si6N3 E. Si4N6 Reset Next

Chemistry
2 answers:
kherson [118]2 years ago
5 0

The answer is Si3N4 (A).

vekshin12 years ago
4 0

Answer : The correct option is, (A) Si_3N_4

Explanation :

Trisilicon tetranitride is a covalent compound because sharing of electrons takes place between silicon and nitrogen. Both the elements are non-metals and hence, will form a covalent bond.

The formula of covalent compound is given by :

  • The less electronegative element is written first.
  • The more electronegative element is written next.
  • If atoms of an element is greater than 1 that means their prefixes are written in the respective element's subscript.

As per given name of compound, the less electronegative element is 'Si' and more electronegative element is 'N'.

So, the chemical formula of trisilicon tetranitride is, Si_3N_4

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Which element in period 4 would have chemical properties similar to magnesium? 7. which metalloids would have chemical propertie
azamat
The only solution you'll need to have for this problem is a periodic table. The columns in the table are called groups, and they are number from the left to the right starting with 1. The rows in the table are called periods which are numbered from the top to bottom starting with 1. 

6. Elements that belong to the same group portray similar chemical properties. Therefore, the element in period 4 which is also in group 2 is <em>Calcium (Ca)</em>.

7. The elements that are striked through with the red slanting lines are the metalloids. All the elements to the left of the metalloids are metals. All the elements to the right are nonmetals. Bromine has a symbol of Br. Since At is a metalloid and located in the same group with Br, the <em>answer is Astatine (At).</em>

8. Tin has the chemical symbol of Sn. The nonmetal that is located in the same group is <em>Carbon (C)</em>.

9. All the elements in period 6 would have similar properties. The answers could be: <em>Phosphorus (P), Arsenic (As), Antimony (Sb) and Bismuth (Bi)</em>.

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5 0
2 years ago
Read 2 more answers
How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K?
solong [7]

Answer:

Mass= 2.77g

Explanation:

Applying

P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28

PV=nRT

NB

Moles(n) = m/M

PV=m/M×RT

m= PVM/RT

Substitute and Simplify

m= (2.09×1.13×28)/(0.082×291)

m= 2.77g

6 0
2 years ago
Calculate the ph of a solution that is 0.6 m in sodium acetate and 0.2 m in acetic acid. ka = 1.8 × 10−5 for acetic acid. 1. ph
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1 year ago
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satela [25.4K]
Atomic mass Ni = 58.69 a.m.u

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?? g --------------------- 7.5x10¹⁵ atoms

58.69x (7.5x10¹⁵) / 6.02x10²³

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6 0
2 years ago
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Answer:

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