What is the chemical formula of trisilicon tetranitride? A. Si3N4 B. Si4N3 C. Si3N6 D. Si6N3 E. Si4N6 Reset Next

Chemistry

2 answers:

kherson [118]2 years ago

5 0

The answer is Si3N4 (A).

vekshin12 years ago

4 0

Answer : The correct option is, (A) $Si_3N_4$

Explanation :

Trisilicon tetranitride is a covalent compound because sharing of electrons takes place between silicon and nitrogen. Both the elements are non-metals and hence, will form a covalent bond.

The formula of covalent compound is given by :

The less electronegative element is written first.
The more electronegative element is written next.
If atoms of an element is greater than 1 that means their prefixes are written in the respective element's subscript.

As per given name of compound, the less electronegative element is 'Si' and more electronegative element is 'N'.

So, the chemical formula of trisilicon tetranitride is, $Si_3N_4$

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Calculate the amount, in moles, of PO43- present at equilibrium when excess Sr3(PO4)2 is added to 750. mL 1.2 M Sr(NO3)2(aq). As

Crank

Answer:

1.8 × 10⁻¹⁶ mol

Explanation:

(a) Calculate the solubility of the Sr₃(PO₄)₂

Let s = the solubility of Sr₃(PO₄)₂.

The equation for the equilibrium is

Sr₃(PO₄)₂(s) ⇌ 3Sr²⁺(aq) + 2PO₄³⁻(aq); Ksp = 1.0 × 10⁻³¹

1.2 + 3s 2s

$K_{sp} =\text{[Sr$^{2+}$]$^{3}$[PO$_{4}^{3-}$]$^{2}$} = (1.2 + 3s)^{3}\times (2s)^{2} = 1.0 \times 10^{-31}\\\text{Assume } 3s \ll 1.2\\1.2^{3} \times 4s^{2} = 1.0 \times 10^{-31}\\6.91s^{2} = 1.0 \times 10^{-31}\\s^{2} = \dfrac{1.0 \times 10^{-31}}{6.91} = 1.45 \times 10^{-32}\\\\s = \sqrt{ 1.45 \times 10^{-32}} = 1.20 \times 10^{-16} \text{ mol/L}\\$