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2 years ago

Which of the following shows the correct rearrangement of the the heat equation q = mCpΔT to solve for specific heat?

2 answers:

6 0

When
q = m*Cp*ΔT

when q is Heat energy in Joules

and m is the mass of the substance in Kg

and Cp is the specific heat (J/Kg.K)

and Δ T is the change in temperature in Kelvin

so, by rearranging the formula we can get the specific heat Cp from:

∴Cp = q / m*ΔT

Kipish [7]2 years ago

5 0

Answer:

$C_{p} = \frac{q}{m(deltaT)}$

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PART A: Use the following glycolytic reaction to answer the question. If the concentration of DHAP is 0.125 M and the concentrat

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Answer:

For A: The free energy change of the reaction is -5339.76 J/mol

For B: The units of free energy change of the reaction are kJ/mol

For C: The forward reaction is favorable and reverse reaction is unfavorable.

Explanation:

For the given chemical reaction:

$DHAP\rightleftharpoons G_3P$

For A:

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G^o=-RT\ln K_{eq}$

To calculate the free energy change, we use the equation:

$\Delta G=\Delta G^o+RT\ln Q$

Or,

$\Delta G=-RT^o\ln K_{eq}+RT\ln Q$

where,

$\Delta G$ = Free energy change

R = Gas constant = $8.314J/K mol$

$T^o$ = standard temperature = $25^oC=[273+25]K=298K$

T = temperature of the cell = $37^oC=[273+37]K=310K$

$K_[eq}$ = equilibrium constant = $5.4\times 10^{-2}$

Q = reaction coefficient = $\frac{[G_3P]}{[DHAP]}$

$[G_3P]$ = 0.06 M

[DHAP] = 0.125 M

Putting values in above equation, we get:

$\Delta G=[-(8.314J/mol.K\times 298K\times \ln (5.4\times 10^{-2}))]+[(8.314J/mol.K\times 310K\times \ln (\frac{0.06}{0.125}))]\\\\\Delta G=-[-7231.46]+[-1891.7]=-5339.76J/mol$

Hence, the free energy change of the reaction is -5339.76 J/mol

For B:

Converting the free energy change of the reaction into kilojoules, we use the conversion factor:

1 kJ = 1000 J

So, $-5339.76J/mol\times \frac{1kJ}{1000J}=-5.34kJ/mol$

Hence, the units of free energy change of the reaction are kJ/mol

For C:

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative. But, from the above calculation, the Gibbs free energy of the reaction is positive. Thus, the reaction is non-spontaneous.

As, the free energy change of the reaction is negative.

Hence, the forward reaction is favorable and reverse reaction is unfavorable.

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2 years ago

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So Helium walks into a bar and orders a beer...
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2 years ago

Which statement accurately describes dark matter?

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Answer:

C. It does not emit electromagnetic radiation.

Explanation:

Right now, Dark Matter is only a theory. Scientist proposed this to counter some of the strange phenomenon with matter in space.

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2 years ago

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A gas is confined to a steel tank with a fixed volume . At 293 K, the gas exerts a pressure of 8.53 atm. After heating the tank

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Answer: The temperature of the heated gas is 357 K

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=8.53atm\\T_1=293K\\P_2=10.4atm\\T_2=?$

Putting values in above equation, we get:

$\frac{8.53}{293K}=\frac{10.4}{T_2}\\\\T_2=357K$

Hence, the temperature of the heated gas is 357 K

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2 years ago

1. After clamping a buret to a ring stand, you notice that the set-up is tippy and unstable. What should you do to stabilize the

vampirchik [111]

Answer:

A. Move the buret clamp to a ring stand with a larger base.

Explanation:

The ring stands are used to hold burettes, light in weight to avoid loss of stability, that is why it is necessary to change the size of the ring stand so that it can support the buret that we are going to use. It is not recommended to balance it with the hand since it would give us an inaccurate result in the titration.

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