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SashulF [63]
2 years ago
7

Explain what happens to an ionic substance when it dissolves in water. Drag the terms on the left to the appropriate blanks on t

he right to complete the sentences. ResetHelp Ionic compounds dissolve in water and dissociate into the Ionic compounds dissolve in water and dissociate into the blank that make up the compound. For example, NaCl in water will form blank ( a q ) (element of the I group) and blank ( a q ) (element of the VII group). that make up the compound. For example, NaCl in water will form Ionic compounds dissolve in water and dissociate into the blank that make up the compound. For example, NaCl in water will form blank ( a q ) (element of the I group) and blank ( a q ) (element of the VII group).(aq)(element of the I group) and Ionic compounds dissolve in water and dissociate into the blank that make up the compound. For example, NaCl in water will form blank ( a q ) (element of the I group) and blank ( a q ) (element of the VII group).(aq)(element of the VII group).
Chemistry
1 answer:
nignag [31]2 years ago
5 0

Answer:

false

Explanation:

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Explain why neither the oil nor the glass fiber interferes with the diffraction pattern of the crystal.
SVEN [57.7K]
<span>It's because The oil and the glass fibers do not interfere with X-ray crystallographic measurements because only one is crystalline.
</span><span>Glass fibers have a low absorbance for </span>X-rays<span> and is </span><span>not crystalline. Because of this, glass fibers will not interfere with X-Ray patterns. Oil, on the other hand, could be considered as crytalline.</span>
8 0
2 years ago
Compute the end-to-end separation (direct distance between molecule ends), in Angstroms, of a coiled PVC molecule with a number-
MArishka [77]

Answer:

5156  Â

Explanation:

Chains of monomers that are being linked together constitute what is called polymers. in this question; we are to compute the end to end separation (direct distance between molecule ends), in Angstroms, of a coiled PVC molecule.

Using the following approach:

The first step is to determine the repeating units in polymer

The number of repeating unit = average molecular weight/  atomic weight of PVC

Given that:

average molecular weight = 256,131 g/mol

atomic weight of PVC = 62.498 g

Then;

The number of repeating unit = 256,131 g/mol /  62.498 g = 4098.227143 mol

Now the distance is calculated by using the formula:

d = (C-C) × sin 109.5/2

C-C bond length = 1.54 angstroms

tetrahedral bond angle = 109.5°

Then d = (1.54)  × sin 109.5/2

d = 1.258

Thus ; the end to end separation  is :

4098.227143  × 1.258 = 5155.57 Â

The answer is 5156  Â (since no decimal should be included )

6 0
1 year ago
. Calculate the mass of O2 produced if 3.450 g potassium chlorate is completely decomposed by heating in presence of a catalyst
Vesnalui [34]
 <span>2 KClO3(s) → 3 O2(g) + 2 KCl(s) 

</span><span>Note: MnO2 (Manganese Dioxide) is not part of the reaction. A catalyst lowers the activation energy and increases both forward and reverse reactions at equal rates. 
</span>
molar mass of KClO3 = 122.5
Moles of KClO3 =  3.45 / 122.55 = 0.028

Moles of O2 produce = \frac{3}{2} \times 0.028

= 0.042 moles

molar mass of O2 = 32

so, mass of O2 = 32 x 0.042  = 1.35 g



5 0
1 year ago
How much heat is required to raise the temperature of 670g of water from 25.7"C to 66,0°C? The specific heat
inna [77]

Answer:

Explanation:

q= mc theta

where,

Q = heat gained

m = mass of the substance = 670g

c = heat capacity of water= 4.1 J/g°C    

theta =Change in temperature=( 66-25.7)

Now put all the given values in the above formula, we get the amount of heat needed.

q= mctheta

q=670*4.1*(66-25.7)

  =670*4.1*40.3

=110704.1

8 0
2 years ago
A 2.40 kg block of ice is heated with 5820 J of heat. The specific heat of water is 4.18 J•g^-1•C^-1. By how much will it’s temp
MrMuchimi

Answer: The temperature rise is 0.53^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed by ice = 5280 J

m = mass of ice = 2.40 kg = 2400 g   (1kg=1000g)

c = heat capacity of water = 4.18J/g^0C

Initial temperature  = T_i

Final temperature = T_f  

Change in temperature ,\Delta T=T_f-T_i=?

Putting in the values, we get:

5280J=2400g\times 4.18J/g^0C\times \Delta T

\Delta T=0.53^0C

Thus the temperature rise is 0.53^0C

0 0
2 years ago
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