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patriot [66]
2 years ago
13

Read the information on Hydrochloric Acid. List four ways you can avoid injury while using HCl and three steps you would take in

case of an accidental exposure to HCl.
Chemistry
1 answer:
lisabon 2012 [21]2 years ago
3 0

Answer:

Find the list and explanation below.

Explanation:

Hydrochloric acid shortened as HCl is a harmful chemical when not handled properly. Four ways to avoid injury with hydrochloric acid include;

1. Dilution: It is advised to dilute the concentrated hydrochloric acid with a reasonable amount of water so that its corrosive effect can be significantly reduced.

2. Wear a laboratory coat: When working with hydrochloric acid in the laboratory it is always advised to wear a laboratory suit so as to ensure a minimal amount of harm in case of an accident or spillage with the acid.

3. Wear a face shield: It is also important that a face shield is worn while working with the acid to prevent contact with the eyes.

4. Wear a protective rubber glove: The rubber gloves would ensure that there is minimal contact of the acid with the hands.

Three steps to be taken in case of an accidental exposure include;

1. Medical Attention: In serious cases, such as in a case of ingesting the acid, urgent medical help should be sought for immediately.

2. Water: If there is contact with the skin or eye, a lot of water should be used on the affected area, and then medical help obtained.

3. Inhalation of fresh air: In a case whereby the hydrochloric acid was inhaled for a long time, the affected person should try to get some fresh air and if other effects are noticed, urgent medical attention should be gotten.

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8 0
2 years ago
Balance the equation xcl2(aq)+agno3(aq)=x(no3)2(aq)+agcl(s)
lisabon 2012 [21]

Explanation:

XCl _{2(aq)} + 2AgNO _{3(aq)}→X(NO _{3}) _{2(aq)}   +2 AgCl _{(s)}

6 0
2 years ago
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You are presented with a white solid and told that due to careless labeling it is not clear if the substance is barium chloride,
Lady bird [3.3K]

The given salts are Barium chloride, lead chloride and zinc chloride.

The balanced chemical reaction between barium chloride and sodium sulfate:

BaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->2NaCl(aq)+BaSO_{4}(s)_{white precipitate}

The balanced chemical reaction between lead chloride and sodium sulfate:

PbCl_{2}(aq)+Na_{2}SO_{4}(aq)-->2NaCl(aq)+PbSO_{4}(s)_{white precipitate}

The balanced chemical reaction between zinc chloride and sodium sulfate:

ZnCl_{2}(aq)+Na_{2}SO_{4}(aq)-->2NaCl(aq)+ZnSO_{4}(aq)

Both Barium chloride and lead chloride produce a white precipitate of their respective sulfates upon reaction with sodium sulfate. But BaCl2 is readily soluble in water where as Lead chloride is insoluble in water.

Therefore, the compound is barium chloride.

5 0
2 years ago
What fraction of the carbon dioxide exhaled by animals is generated by the reactions of the citric acid cycle
puteri [66]

Answer:

1/3

Explanation:

Pyruvate is produced by the glycolysis in cytoplasm. The oxidation of pyruvate takes place in mitochondrial matrix.  

Pyruvate is converted to acetyl-CoA in the reaction given below:

Pyruvate + NAD⁺ + CoA-SH ⇒ acetyl-CoA + NADH + CO₂

1 molecule of carbon dioxide is eliminated from 1 molecule of pyruvate.

Also,  

2 molecules of carbon dioxide is eliminated from 2 molecules of pyruvate (as glucose on glycolysis yields 2 molecules of pyruvate).

Also, acetyl-CoA further goes into the citric acid cycle and produces 2 molecules of carbon dioxide.

Thus pyruvate produces total 3 molecules of CO₂  and hence glucose produces 6 molecules of CO₂ (as glucose on glycolysis yields 2 molecules of pyruvate)

Thus,

<u>Fraction = 2/6 = 1/3</u>

4 0
2 years ago
Calculate the mass of water vapour present in a room of volume 400 m3 that contains air at 27 °C on a day when the relative humi
Alex73 [517]

Answer:

Mass of water = 6251. 706g or 6.25Kg

Explanation:

Relative humidity = (actual vapor pressure/saturation vapor pressure) * 100%

Actual vapor pressure, Pw = relative humidity * saturation vapor pressure

Pw = 60% * (35.6 *0.001)atm = 0.0216atm

Note: 1mbar = 0.001atm

Using the ideal gas equation: PV=nRT; where P = Pw= 0.02136atm, V= (400

* 1000)dm^3, R= 0.082 atmdm^3/kmol, T= (27+273)K, n = number of moles

Note: 1m^3 = 1000dm^3,R is the molar gas constant.

Making n subject of the formula, n = PV/RT

n= (0.02136 * 400000)/(0.082 * 300) = 347.317 moles

Mass (g) = number of moles (n) * molar mass

molar mass of water=18g

Mass of water = 347.317 * 18 = 6251. 706g or 6.25Kg

6 0
2 years ago
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