Hello!
To determine the Kb of gallic acid is actually very simple.
The
dissociation reaction of Gallic Acid (HGal) is the following:
HGal+H₂O ⇄ H₃O⁺ + Gal⁻The equation for converting from Ka to Kb is the following:

So, the Kb is
2,19*10⁻¹²Have a nice day!
Answer:
Carbon tetrachloride would be 2.2 fold heavier than water
Explanation:
Carbon tetrachloride (2.20g/mL) is denser than water (1.00g/mL)
Answer:

Explanation:
Due to Coulomb´s law electric force can be described by the formula
, where K is the Coulomb´s constant (
),
= Charge 1 (Na+ in this case),
is the charge 2 (Cl-) and r is the distance between both charges.
Work made by a force is W=F.d and total work produced is the change in energy between final and initial state. this is
.
so we have ![W=W_{f} -W_{i} =(K\frac{q_{(Na+)}q_{(Cl-)}rf}{r_{f} ^{2}})-(K\frac{q_{(Na+)}q_{(Cl-)}ri}{r_{i} ^{2}})=Kq_{(Na+)}q_{(Cl-)[\frac{1}{{r_{f}}} -\frac{1}{{r_{i}}}]](https://tex.z-dn.net/?f=W%3DW_%7Bf%7D%20-W_%7Bi%7D%20%3D%28K%5Cfrac%7Bq_%7B%28Na%2B%29%7Dq_%7B%28Cl-%29%7Drf%7D%7Br_%7Bf%7D%20%5E%7B2%7D%7D%29-%28K%5Cfrac%7Bq_%7B%28Na%2B%29%7Dq_%7B%28Cl-%29%7Dri%7D%7Br_%7Bi%7D%20%5E%7B2%7D%7D%29%3DKq_%7B%28Na%2B%29%7Dq_%7B%28Cl-%29%5B%5Cfrac%7B1%7D%7B%7Br_%7Bf%7D%7D%7D%20-%5Cfrac%7B1%7D%7B%7Br_%7Bi%7D%7D%7D%5D)
Given that ri= 1.1nm=
and rf= infinite distance
![W=(9x10^{9})(1.6x10^{-19})(-1.6x10^{-19})[\frac{1}{\alpha }-\frac{1}{(1.1x10^{-9})}]=2.1x10^{-19}J](https://tex.z-dn.net/?f=W%3D%289x10%5E%7B9%7D%29%281.6x10%5E%7B-19%7D%29%28-1.6x10%5E%7B-19%7D%29%5B%5Cfrac%7B1%7D%7B%5Calpha%20%7D-%5Cfrac%7B1%7D%7B%281.1x10%5E%7B-9%7D%29%7D%5D%3D2.1x10%5E%7B-19%7DJ)
The title of Scientist was formally bestowed upon Sir Isaac Newton when he was
awarded the Merit Badge in Science at the age of 15, and he remained a Scientist
until he died, at the age of 84, on March 20, 1727, for a total duration of 69 years.
Yes, He was a productive scientist.He is one of the most important contributors to our understanding of how the universe works.
Answer:
The freezing point will be 
Explanation:
The depression in freezing point is a colligative property.
It is related to molality as:

Where
Kf= 
the molality is calculated as:




Depression in freezing point = 
The new freezing point = 