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Mamont248 [21]
1 year ago
5

Both black and white road surfaces radiate energy. at midnight on a starry night the warmer road surface is the

Chemistry
1 answer:
luda_lava [24]1 year ago
5 0
The black road because during the day it absorbed more radiation than the with one
You might be interested in
The acid-dissociation constant, ka, for gallic acid is 4.57 ⋅ 10-3. what is the base-dissociation constant, kb, for the gallate
LiRa [457]
Hello!

To determine the Kb of gallic acid is actually very simple. 

The dissociation reaction of Gallic Acid (HGal) is the following:

HGal+H₂O ⇄ H₃O⁺ + Gal⁻

The equation for converting from Ka to Kb is the following:

Ka*Kb=Kw \\  \\ Kb= \frac{Kw}{Ka}= \frac{1*10^{-14} }{4,57*10^{-3} }=2,19 * 10^{-12}

So, the Kb is 2,19*10⁻¹²

Have a nice day!
3 0
1 year ago
Read 2 more answers
Suppose you had used carbon tetrachloride, a liquid of density 2.20 g/mL, to determine the actual volume measured by your pipet.
VARVARA [1.3K]

Answer:

Carbon tetrachloride would be 2.2 fold heavier than water

Explanation:

Carbon tetrachloride (2.20g/mL) is denser than water (1.00g/mL)

4 0
1 year ago
A sodium ion, Na+, with a charge of 1.6×10−19C and a chloride ion, Cl− , with charge of −1.6×10−19C, are separated by a distance
sasho [114]

Answer:

W\geq 2.1x10^{-19}J

Explanation:

Due to Coulomb´s law electric force can be described by the formula F=K\frac{q_{1}.q_{2}}{r^{2}}, where K is the Coulomb´s constant (9x10^{9} N\frac{m^{2} }{C^{2} }), q_{1}= Charge 1 (Na+ in this case), q_{2} is the charge 2 (Cl-) and r is the distance between both charges.

Work made by a force is W=F.d and total work produced is the change in energy between final and initial state. this is W=W_{f} -W_{i}.

so we have W=W_{f} -W_{i} =(K\frac{q_{(Na+)}q_{(Cl-)}rf}{r_{f} ^{2}})-(K\frac{q_{(Na+)}q_{(Cl-)}ri}{r_{i} ^{2}})=Kq_{(Na+)}q_{(Cl-)[\frac{1}{{r_{f}}} -\frac{1}{{r_{i}}}]

Given that ri= 1.1nm= 1.1x10^{-9}m and rf= infinite distance

W=(9x10^{9})(1.6x10^{-19})(-1.6x10^{-19})[\frac{1}{\alpha }-\frac{1}{(1.1x10^{-9})}]=2.1x10^{-19}J

6 0
2 years ago
2. Newton began his academic career in 1667. For how long was he a working scientist? Was he a very productive scientist? Justif
Alla [95]
The title of Scientist was formally bestowed upon Sir Isaac Newton when he was
awarded the Merit Badge in Science at the age of 15, and he remained a Scientist
until he died, at the age of 84, on March 20, 1727, for a total duration of 69 years.

Yes, He was a productive scientist.He is one of the most important contributors to our understanding of how the universe works.
5 0
1 year ago
Cyclohexane has a freezing point of 6.50 ∘C and a Kf of 20.0 ∘C/m. What is the freezing point of a solution made by dissolving 0
ExtremeBDS [4]

Answer:

The freezing point will be 2.9^{0}C

Explanation:

The depression in freezing point is a colligative property.

It is related to molality as:

Depressioninfreezing point=K_{f}Xmolality

Where

Kf= 20\frac{^{0}C}{m}

the molality is calculated as:

molality=\frac{moles_{solute}}{mass_{solvent}}

moles=\frac{mass}{molarmass}=\frac{0.694}{154}=0.0045mol

massofcyclohexane=25g=0.025Kg

molarity=\frac{0.0045}{0.025}=0.18m

Depression in freezing point = 20X0.18=3.6^{0}C

The new freezing point = 6.5^{0}C-3.6^{0}C=2.9^{0}C

5 0
2 years ago
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