Water at the bottom of a narrow metal tube is held at a constant temperature of 293 K. The total pressure of air (assumed dry) i
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Answer:
0.60 mol·L⁻¹
Explanation:
Data:
LiBr: c = 0.50 mol/L; V =300 mL
RbBr: c = 0.70 mol/L; V =300 mL
1. Calculate the moles of Br⁻ in each solution
(a) LiBr
(b) RbBr
2. Calculate the molar concentration of Br⁻
(a) Moles of Br⁻
n = 0.150 mol + 0.210 mol = 0.360 mol
(b) Volume of solution
V = 300 mL + 300 mL = 600 mL = 0.600 L
(c) Molar concentration
<u>Answer:</u> The percentage abundance for isotope is 3.09 %.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
We are given:
Let the fractional abundance for isotope be 'x'
- <u>For
isotope:</u>
Mass of isotope = 27.9769 amu
Percentage abundance of isotope = 92.22 %
Fractional abundance of isotope = 0.9222
- <u>For
isotope:</u>
Mass of isotope = 28.9764 amu
Percentage abundance of isotope = 4.68%
Fractional abundance of isotope = 0.0468
- <u>For
isotope:</u>
Mass of isotope = 29.9737 amu
Fractional abundance of isotope = x
- Average atomic mass of silicon = 28.084 amu
Putting values in equation 1, we get:
Converting this fractional abundance into percentage abundance by multiplying it by 100, we get:
Hence, the percentage abundance for isotope is 3.09 %.