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2 years ago

A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.314 kg of water?

Chemistry

1 answer:

Mariulka [41]2 years ago

5 0

Answer:

g NaCl = 424.623 g

Explanation:

C NaCl = 3.140 m = 3.140 mol NaCl / Kg solvent

∴ solvent: H2O

∴ mass H2O = 2.314 Kg

mol NaCl:

⇒ mol NaCl = (3.140 mol NaCl/Kg H2O)×(2.314 Kg H2O) = 7.266 mol NaCl

∴ mm NaCl = 58.44 g/mol

⇒ g NaCl = (7.266 mol NaCl)×(58.44 g/mol) = 424.623 g NaCl

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NNADVOKAT [17]

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B, ionization energy tends to increase across a period because the nuclear charge increases.
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2 years ago

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Lin received 200 new laptops to be issued to company employees. Lin was asked to set them up and distribute them to everyone on

OleMash [197]

Answer:

Inventory management documentation

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2 years ago

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In the chemical equation 3c2h4 how many atoms of carbon are represented

Scorpion4ik [409]

An example.
water is H2O

2 hydrogen, 1 oxygen

so the number to the right means how much of what is on the left.

so it looks like 2, because C2, but look at the 3 at the beginning. that means
3 (c2h4)

so 6 carbons, 12 hydrogen

the ratio of c2 to h4 doesn't change it's always 1:2.

but the 3 at the front is a different number relating to how much you have

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2 years ago

Isopentyl acetate (C7H14O2), the compound responsible for the scent of bananas, can be produced commercially. Interestingly, bee

lora16 [44]

Answer:

The answer to your question is:

a) 4.64 x 10 ¹⁵ molecules

b) 9.28 x 10 ¹⁵ atoms of O2

Explanation:

MW C7H14O2 = 84 + 14 + 32 = 130 g

a) 130 g of C7H14O2 ---------------- 1 mol of C7H14O2

1 x 10 ⁻⁶ g --------------- x

x = 7.7 x 10 ⁻⁹ mol

1 mol of C7H14O2 -------------- 6 .023 x 10 ²³ molecules

7.7 x 10⁻⁹ mol -------------- x

x = 4.64 x 10¹⁵ molecules

b) 130 g of C7H14O2 ---------------- 1 mol of C7H14O2

1 x 10⁻⁶ C7H14O2 ----------------- x

x = 7.7 x 10 ⁻⁹ mol of C7H14O2

1 mol of C7H14O2 --------------- 2 mol of O2

7.7 x 10 ⁻⁹ ---------------- x

x = 1.54 x 10⁻⁸ mol of O2

1 mol of O2 ----------------- 6.023 x 10 ²³ atoms

1.54 x 10 ⁻⁸ ---------------- x

x = 9.28 x 10 ¹⁵ atoms of O2

8 0

2 years ago

The volume of distilled water that should be added to 10.0 mL of 6.00 M HCl(aq) in order to prepare a 0.500 M HCl(aq) solution i

bija089 [108]

Answer:

110ml

Explanation:

Using the dilution equation, C1V1 = C2V2

Where C1 is the initial concentration of solution

C2 is final concentration of solution

V1 is intital volume of solution

V2 is final volume of solution.

From the question , C1=6M, C2=0.5M, V1=10ml, V2=?

$V2 =\frac{C1V1}{C2}$

$V2 =\frac{10*6}{0.5}$

$V2 =120ml$

volume of water added = final volume -initial volume

= 120-10

=110ml

3 0

2 years ago