5 plates is the highest amount that can be served
There’s only 5 sandwiches so 7 is automatically ruled out, there’s 14 corn cobs and 5 sandwiches only need 10 so it works out
Let's Assign Symbols to molecules like,
C₂O₄ = X
and
H₂O = Y
Then,
K [ Co (X)₂ (Y)₂ ]
As, Potassium (K) has a O.N = +1
To neutralize, the coordination sphere must have -1 oxidation number.
So,
[ Co (X)₂ (Y)₂ ] = -1
As,
O.N of X = -2
Then
O.N of (X)₂ = -4
Also,
O.N of H₂O is zero as it is neutral, So,
[Co - 4 + 0 ] = -1
Or,
Co = -1 + 4
Co = +3
Result:
Oxidation Number of Coordination Sphere is -1 and Oxidation Number of Cu is +3.
Answer:
CaS, CaBr₂, VBr₅, and V₂S₅.
Explanation:
- The ionic compound should be neutral; the overall charge of it is equal to zero.
- Binary ionic compound is composed of two different ions.
<u>Ca²⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.</u>
- CaS can be formed via combining Ca²⁺ with S²⁻ to form the neutral binary ionic compound CaS.
- CaBr₂ can be formed via combining 1 mole of Ca²⁺ with 2 moles of Br⁻ to form the neutral binary ionic compound CaBr₂.
<u>V⁵⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.</u>
- V₂S₅ can be formed via combining 2 moles of V⁵⁺ with 5 moles of S²⁻ to form the neutral binary ionic compound V₂S₅.
- VBr₅ can be formed via combining 1 mole of V⁵⁺ with 5 moles of Br⁻ to form the neutral binary ionic compound VBr₅.
<em>So, the empirical formula of four binary ionic compounds that could be formed is: CaS, CaBr₂, VBr₅, and V₂S₅.</em>
<em></em>
Answer:
4.02
Explanation:
The mass ratios will be given by dividing the mass of O₂ into the mass of N₂.
So lets do our calculations:
First Compound:
53.3 g O₂ / 46.7 g N₂ = 1.14
Second Compound:
82.0 g O₂ / 17.9 g N₂ = 4.58
Ratio = 4.58 / 1.14 = 4.02
This result for all practical purposes is a whole number, and it is telling us that there are 4 times as many oxygen atoms in the second coumpound as in the first compound. This is so because the ratio we just calculated is also the ratio in mol atoms:
Ratio = [ mass O₂ / MW O2/ mass N₂/ MW N₂] 2nd compound / [mass O₂ / MW O2/ mass N₂/ MW N₂ !st compound]
and the molecular weights cancel each other.
The only N and O compounds that follow this ratio are N₂O₄ and N₂O, and this question could be made in a multiple choice to match formulas.
