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2 years ago

Which coefficient correctly balance the equation CaO + H2O -> Ca(OH)2

Chemistry

1 answer:

deff fn [24]2 years ago

4 0

For the equation that we are given:

$CaO+H_{2}O$ → $Ca(OH)_{2}$

We see that on the reactants side we have:

Ca: 1 mol

O: 2 mol

H: 2 mol

And then we see that on the products side we have:

Ca: 1 mol

O: 2 mol

H: 2 mol

Therefore since we have equal moles of each of the elements on both sides of the equation, this equation is balanced how it is.

So the correct coefficients for this equation are: B) 1, 1, 1.

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A certain element X has four isotopes. 4.350% of X has a mass of 49.94605 amu. 83.79% of X has a mass of 51.94051 amu. 9.500% of

sesenic [268]

Answer: The average atomic mass of the element X is 51.99592 amu

Explanation:

Mass of isotope 1 = 49.94605 amu

% abundance of isotope 1 = 4.350% = $\frac{4.350}{100}=0.0435$

Mass of isotope 2 = 51.94051 amu.

% abundance of isotope 2 = 83.79% = $\frac{83.79}{100}=0.8379$

Mass of isotope 3 = 52.94065 amu.

% abundance of isotope 2 = 9.500% = $\frac{9.500}{100}=0.095$

Mass of isotope 4 = 53.93888 amu.

% abundance of isotope 2 = 2.360% = $\frac{2.360}{100}=0.0236$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=(49.94605\times 0.0435)+(51.94051 \times 0.8379)+ (52.94065\times 0.095)+(53.93888\times 0.0236)$

$A=51.99592amu$

Therefore, the average atomic mass of the element X is 51.99592 amu

5 0

2 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Ca2+, V5+, Br-

Jet001 [13]

Answer:

CaS, CaBr₂, VBr₅, and V₂S₅.

Explanation:

The ionic compound should be neutral; the overall charge of it is equal to zero.

Binary ionic compound is composed of two different ions.

Ca²⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.

CaS can be formed via combining Ca²⁺ with S²⁻ to form the neutral binary ionic compound CaS.

CaBr₂ can be formed via combining 1 mole of Ca²⁺ with 2 moles of Br⁻ to form the neutral binary ionic compound CaBr₂.

V⁵⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.

V₂S₅ can be formed via combining 2 moles of V⁵⁺ with 5 moles of S²⁻ to form the neutral binary ionic compound V₂S₅.

VBr₅ can be formed via combining 1 mole of V⁵⁺ with 5 moles of Br⁻ to form the neutral binary ionic compound VBr₅.

So, the empirical formula of four binary ionic compounds that could be formed is: CaS, CaBr₂, VBr₅, and V₂S₅.

5 0

2 years ago

Consider the dissolution of 1.50 grams of salt XY in 75.0 mL of water within a calorimeter. The temperature of the water decreas

-BARSIC- [3]

Answer:

The quantity of heat lost by the surroundings is 258,5J

Explanation:

The dissolution of salt XY is endothermic because the water temperature decreased.

The total heat consumed by the dissolution process is:

4,184 J/g°C × (75,0 + 1,50 g) × 0,93°C = 297,7 J

This heat is consumed by the calorimeter and by the surroundings.

The heat consumed by the calorimeter is:

42,2 J/°C × (0,93°C) = 39,2 J

That means that the quantity of heat lost by the surroundings is:

297,7J - 39,2J = 258,5 J

I hope it helps!

8 0

2 years ago

What is I2O8 compound name?

julsineya [31]

Answer:

Formula in Hill system is I2O8. Computing molar mass (molar weight). To calculate molar mass of a chemical compound enter its formula and click 'Compute'. In chemical formula you may use: Any chemical element.

Explanation:

7 0

2 years ago

Analyze and solve this partially completed galvanic cell puzzle. There are 4 electrodes each identified by a letter of the alpha

klasskru [66]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is $E_{cell}__{AC}} = 0.94$

Explanation:

From the question we are told that

the cell voltage for AD is $E_{cell}__{AD}} = 1.56V$

From the data give we can see that

$E_{cell}__{AD}} - E_{cell}__{BD}} = E_{cell}__{AB}}$

i.e $1.56 - 1.53 = 0.03$

In the same way we can say that

$E_{cell}__{AD}}-E_{cell}__{CD}} = E_{cell}__{AC}}$

=> $E_{cell}__{AC}}=1.56- 0.62$

$E_{cell}__{AC}} = 0.94$

5 0

2 years ago