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Romashka-Z-Leto [24]
2 years ago
6

A magnesium ion, Mg2+, with a charge of 3.2×10−19C and an oxide ion, O2−, with a charge of −3.2×10−19C, are separated by a dista

nce of 0.25 nm. How much work would be required to increase the separation of the two ions to an infinite distance?
Chemistry
1 answer:
baherus [9]2 years ago
7 0

Explanation:

Formula for work done is as follows.

           W = -k \frac{q_{1}q_{2}}{d}    

where,  k = proportionality constant = 8.99 \times 10^{9} Jm/C^{2}

            q_{1} = charge of Mg^{2+} = 3.2 \times 10^{-19} C

            q_{2} = charge of O_{2-} = -3.2 \times 10^{-19} C

            d = separation distance = 0.45 nm = 0.45 \times 10^{-9} m

Now, we will put the given values into the above formula and calculate work done as follows.

         W = -k \frac{q_{1}q_{2}}{d}    

           = \frac{-[8.99 \times 10^{9} Jm/C^{2} \times 3.2 \times 10^{-19} C \times -3.2 \times 10^{-19} C]}{0.25 \times 10^{-9} m}  

           = 3.68 \times 10^{-18} J

Thus, we can conclude that work required to increase the separation of the two ions to an infinite distance is 3.68 \times 10^{-18} J.

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The empirical formula of a gaseous fluorocarbon is CF2. At a certain temperature and pressure, a 1-L volume holds 8.93 g of this
dimaraw [331]

Answer:

C₄F₈

Explanation:

Using their mole ratio to compute their mass

molar mass of carbon = 12.0107 g/mol

molar mass of fluorine gas = 37.99681

let x = mass of carbon

given mass of fluorine = 1.70 g

x / 12.01067 = 1.70 / 37.99687

cross multiply

x = ( 1.70 × 12) / 37.99687 = 20.4 / 37.99687 = 0.53688 g

mass of one mole of CF₂ = 0.53688 + 1.70 = 2.23688 g

number of mole of CF₂ = 8.93 g / 2.23688 = 3.992 approx 4

molecular formula of CF₂ = 4 (CF₂) = C₄F₈

3 0
2 years ago
An atom in the ground state contains a total of 5 electrons 5 protons and 5 neutrons. Which Lewis electron-dot diagram represent
Luba_88 [7]
I don't know if you didn't gave a picture choice or if i didn't get the picture.
But lets call this atom A. Electron dot formula doesn't require Neutron and Protons, its main concern is valance elections.

So atom A has 5 electrons which means 2,3 it has 3 valance electrons. Its dot formula will become
:A.

I hope this helped.
7 0
2 years ago
Cacodyl, which has an intolerable garlicky odor and is used in the manufacture of cacodylic acid, a cotton herbicide, has a mass
Papessa [141]

Answer:

The molecular formula of cacodyl is C₄H₁₂As₂.

Explanation:

<u>Let's assume we have 1 mol of cacodyl</u>, in that case we'd have 209.96 g of cacodyl and the<u> following masses of its components</u>:

  • 209.96 g * 22.88/100 = 48.04 g C
  • 209.96 g * 5.76/100 = 12.09 g H
  • 209.96 g * 71.36/100 = 149.83 g As

Now we convert those masses into moles:

  • 48.04 g C ÷ 12 g/mol = 4.00 mol C
  • 12.09 g H ÷ 1 g/mol = 12.09 mol H
  • 149.83 g As ÷ 74.92 g/mol = 2.00 mol As

Those amounts of moles represent the amount of each component in 1 mol of cacodyl, thus, the molecular formula of cacodyl is C₄H₁₂As₂.

3 0
2 years ago
Unknown element x has four energy levels, five valence electrons, and is a metalloid. what is elements x?
kykrilka [37]

Answer:

Element X is Arsenic (As)

Explanation:

  • Elements in the periodic table are either metals, non-metals or metalloids.
  • Metals are elements that react by losing electrons to obtain a stable configuration and form cation.
  • Non-metals are those elements that react by gaining electrons to form a stable configuration and form anion.
  • Metalloids are elements in the periodic table that have both metallic and non-metallic properties.
  • Examples of metalloids include Selenium, Arsenic, Boron, etc.
  • Arsenic is a metalloid in period 4 (four energy levels) with five valence electrons.
8 0
2 years ago
Apumpis used toraisethe pressure of a fluid, and it operatesby converting the mechanical shaft work to mechanicalenergyof the fl
Ksivusya [100]

Answer:

maximum possible volume flow rate = V = 0.5m^3/s

Explanation:

Given power consumed = 3.5kW

pressure difference ( delta -P) = 7kPa

let maximum possible volume flow rate = V

The rate of flow of work = W = V x Delta -P

hence, V = W/delta P

V = 3.5/7

V = 0.5m^3/s

6 0
2 years ago
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