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DochEvi [55]
2 years ago
10

In a soda-acid fire extinguisher, concentrated sulfuric acid reacts with sodium hydrogen carbonate to produce carbon dioxide, so

dium sulfate, and water.
a. how many moles of sodium hydrogen carbonate would be needed to react with 150.0 g of sulfuric acid?
b. how many moles of each product would be formed?
Chemistry
1 answer:
vlabodo [156]2 years ago
7 0
Chemical reaction: 2NaHCO₃ + H₂SO₄ → Na₂SO₄ + 2CO₂ + 2H₂O.
m(H₂SO₄) = 150.0 g.
n(H₂SO₄) = m(H₂SO₄) ÷ M(H₂SO₄).
n(H₂SO₄) = 150 g ÷ 98 g/mol.
n(H₂SO₄) = 1.53 mol.
From chemical reaction: n(H₂SO₄) : n(NaHCO₃) = 1 : 2.
n(NaHCO₃) = 2 · 1.53 mol = 3.06 mol.
n(H₂SO₄) : n(Na₂SO₄) = 1 : 1.
n(Na₂SO₄) = 1.53 mol.
n(H₂SO₄) : n(CO₂) = 1 : 2.
n(CO₂) = 3.06 mol.
n(H₂SO₄) : n(H₂O) = 1 : 2.
n(H₂O) = 3.06 mol.

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Answer:

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Explanation:

First, the empirical formula needs to be calculated as follows

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O = 54.24/16 = 3.39moles

Next, we divide each mole value by the smallest (3.39moles)

C = 3.39/3.39 = 1

H = 5.08/3.39 = 1.5

O = 3.39/3.39 = 1

To get the empirical formula of this molecule, we multiply all by 2 to have:

C = 2

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Next, we find the molecular formula as follows:

(C2H3O2)n = 118.1

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24 + 3 + 32 = 118.1

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(C2H3O2)2

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5 0
2 years ago
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Answer:

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Explanation:

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11.9 mL of 0.160 M NaOH were used. The reacting moles of NaOH were:

0.0119 L × 0.160 mol/L = 1.90 × 10⁻³ mol

The molar ratio of HCl to NaOH is 1:1. The reacting moles of HCl are 1.90 × 10⁻³ moles.

1.90 × 10⁻³ moles of HCl are in 10.0 mL of solution. The molarity of HCl is:

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Answer:

a, b

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Electrolytes dissociate to make ions, because of it  they conduct electricity.

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Answer:

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Explanation:

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