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DochEvi [55]
2 years ago
10

In a soda-acid fire extinguisher, concentrated sulfuric acid reacts with sodium hydrogen carbonate to produce carbon dioxide, so

dium sulfate, and water.
a. how many moles of sodium hydrogen carbonate would be needed to react with 150.0 g of sulfuric acid?
b. how many moles of each product would be formed?
Chemistry
1 answer:
vlabodo [156]2 years ago
7 0
Chemical reaction: 2NaHCO₃ + H₂SO₄ → Na₂SO₄ + 2CO₂ + 2H₂O.
m(H₂SO₄) = 150.0 g.
n(H₂SO₄) = m(H₂SO₄) ÷ M(H₂SO₄).
n(H₂SO₄) = 150 g ÷ 98 g/mol.
n(H₂SO₄) = 1.53 mol.
From chemical reaction: n(H₂SO₄) : n(NaHCO₃) = 1 : 2.
n(NaHCO₃) = 2 · 1.53 mol = 3.06 mol.
n(H₂SO₄) : n(Na₂SO₄) = 1 : 1.
n(Na₂SO₄) = 1.53 mol.
n(H₂SO₄) : n(CO₂) = 1 : 2.
n(CO₂) = 3.06 mol.
n(H₂SO₄) : n(H₂O) = 1 : 2.
n(H₂O) = 3.06 mol.

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lyudmila [28]
Metallic elements can bend because they have the property of being ductile. This means that a solid material stretches under tensile stress. If a material is ductile then it may be stretched into a wire. Further, the material can also be malleable. 
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What is the concentration of Iodine I2 molecules in a solution containing 2.54 g of iodine 250 cm3 of solution? A 0.01mol/dm3 B
gulaghasi [49]

Answer:

C. 0.04 moles per cubic decimeter.

Explanation:

The molar mass of the Iodine is 253.809 grams per mole and a cubic decimeter equals 1000 cubic centimeters. The concentration of Iodine (c), measured in moles per cubic decimeter, can be determined by the following formula:

c = \frac{m}{M\cdot V} (1)

Where:

m - Mass of iodine, measured in grams.

M - Molar mass of iodine, measured in grams per mol.

V - Volume of solution, measured in cubic decimeters.

If we know that m = 2.54\,g, M = 253.809\,\frac{g}{mol} and V = 0.25\,dm^{3}, then the concentration of iodine in a solution is:

c = \frac{2.54\,g}{\left(253.809\,\frac{g}{mol} \right)\cdot (0.25\,dm^{3})}

c = 0.04\,\frac{mol}{dm^{3}}

Hence, the correct answer is C.

3 0
2 years ago
A 1.850 g mixture of SrCO3 and SrO is heated. The SrCO3 decomposes to SrO and CO2. What was the mass percentage of SrCO3 in the
Oliga [24]
<span>decomposition of SrCO3 to SrO and CO2 =change in mass

 moles of CO2 =(1.850 g - 1.445 g). 
</span>Mass of <span>C<span>O2</span></span><span> in mixture: 1.850-1.445 = 0.405g
</span>0.405g/44.01 g/mol <span>C<span>O2</span></span><span> = 0.0092 moles </span><span>C<span>O2</span></span><span>.
</span>ratio of <span>C<span>O2</span></span><span> to SrO in Sr</span><span>C<span>O3</span></span><span> is 1:1
</span><span> mass ratio = 1.358/1.850 = 0.7341, </span>
or 73.41% Sr<span>C<span>O3</span></span><span>.
</span>hope this helps
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2 years ago
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Lars observes a substance to be a solid and to float in water at room temperature (23°C). Based on the given properties, which s
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Answer:

D. Sulfur Hexafluride

Explanation:

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I hope this helped !!

4 0
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aleksandr82 [10.1K]

Answer:

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They are often designated NPK fertilizers.

  Now we know that the numbers 10-20-20 depicts the nitrogen-phosphorus and potassium content of the fertilizer.

From the designation,

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8 0
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