First, we write the half equations for the reduction of the chemical species present:
Cu⁺² + 2e → Cu; E° = 0.34 V
Ni⁺² + 2e → Ni; E° = - 0.23 V
In order to determine the potential of the cell, we find the difference between the two values. For this:
E(cell) = 0.34 - (-0.23)
E(cell) = 0.57 V
The second option is correct. (The difference in values is due to different values in literature, and it is negligible)
Answer:
Explanation:
N₂ + 3H₂ = 2 NH₃
1 vol 2 vol
786 liters 1572 liters
786 liters of dinitrogen will result in the production of 1572 liters of ammonia
volume of ammonia V₁ = 1572 liters
temperature T₁ = 222 + 273 = 495 K
pressure = .35 atm
We shall find this volume at NTP
volume V₂ = ?
pressure = 1 atm
temperature T₂ = 273
liter .
mol weight of ammonia = 17
At NTP mass of 22.4 liter of ammonia will have mass of 17 gm
mass of 303.44 liter of ammonia will be equal to (303.44 x 17) / 22.4 gm
= 230.28 gm
=.23 kg / sec .
Rate of production of ammonia = .23 kg /s .
Answer:
Sodium will an electron and chlorine will gain an electron
Explanation:
The electronic configurations of sodium and chlorine are;
Sodium- 1s2 2s2 2p6 3s1
Chlorine- 1s2 2s2 2p6 3s2 3p5
Hence, sodium can easily loose one electron to chlorine to attain a noble gas configuration while chlorine accepts one electron to attain the noble gas configuration.
Water typically exist in its gaseous state in the atmosphere. Fog contains droplets of liquid water suspended in the air. Thus to produce a fog, vapor in the air would undergo condensation with a state change from gas to liquid.
Intermolecular interactions between water molecules strengthen as the vapor condenses to produce a liquid. The condensation of vapor thus involves a production of energy. With all the extra intermolecular interactions, molecules in the fog would find it more difficult to move around and therefore see a decrease in their motion.
