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lianna [129]
1 year ago
9

Marisa is a 120 pound female who attended a party where alcohol was being served. She began drinking at 9 pm. After finishing he

r 5th drink at midnight, she left, driving her own car. She was pulled over about a mile from the party location.
Chemistry
1 answer:
tiny-mole [99]1 year ago
4 0

Answer:

Explanation:

hour that passes and she drank for 3 hours so .045% must be subtracted. .20% - .045 % = .155%2) Obviously drunk, staggering, irrational behavior, no coordination 3) Yes, she is driving intoxicated because Texas’ legal limit is .08% and she is above that. Scenario 2 4) David drank 6 drinks. At 240 lbs, he is at .10%. However, subtracting .060% (.015% per hour x 4 hours) gives a BAC of .04%5) Relaxed, mellow, may show slight signs of impairment 6) David is okay to drive at .04% according to Texas law. However, the effects of alcohol can vary greatly for many reasons. 7) Even though Anthony drank the same amount during the same amount of time, several factors could cause Anthony’s BAC to be higher than David’s, thus making him “more drunk.”

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(a) What are the possible values of l for n = 4? (Enter your answers as a comma-separated list.)
vodka [1.7K]

Answer:

(a) 0,1,2,3      (b) -3,-2,-1,0,1,2,3              (c) 6               (d) 5

Explanation:

(a) for the principal quantum number 'n', the possible values of I = 0 to n-1. Thus, if the principal quantum number 'n' =4, I = 0,1,2,3.

(b) for a given number of 'I', the possible values of ml = -I to +I. Therefore, if I =3, then ml = -3,-2,-1,0,1,2,3

(c) 'I' which is the orbital angular momentum quantum number usually has values from 0,1,2,⋯,n−1. Therefore, for n greater than or 6, t would be greater than or equal to 5. Thus, the smallest possible value of n for which I can be 6 is 6.

(d) In a 3-dimensional figure,  If the z-component of the orbital angular momentum Lz for which I=5 is measured, The possible outcomes will be:

mħ = -5ħ, -4ħ, -3ħ, -2ħ, -1ħ, 0, 1ħ, 2ħ, 3ħ, 4ħ, 5ħ.

Thus, the smallest possible l that can have a z component of 5ℏ is 5.

4 0
2 years ago
The specific rotation of (R) carvone is (+) 61°. The optical rotation of a sample of a mixture of R &S carvone is measured a
shusha [124]

Answer:

See explanation

Explanation:

% optical purity = specific rotation of mixture/specific rotation of pure enantiomer  * 100/1

specific rotation of mixture = 23°

specific rotation of pure enantiomer = 61°

Hence;

% optical purity = 23/61 * 100 = 38 %

More abundant enantiomer = 100% - 38 % = 62%

Hence the pure  (S) carvone is (-) 62° is the more abundant enantiomer.

Enantiomeric excess = 62 - 50/50 * 100 = 24%

Hence

(R) - carvone  =  38 %

(S) - carvone = 62%

7 0
1 year ago
Read 2 more answers
Imagine you needed to identify if an object has undergone a physical change or a chemical change. What information would you nee
pishuonlain [190]
How it looks. basically the thing that tells you how it change. for example if an ice cube was melted (heat), it only changed physically not chemically as the h20 molecules are still there. however lets say you burn woos— you cant get that would back. its ash now and it has changed chemically.
7 0
1 year ago
A compound contains 10.13% C and 89.87% Cl (by mass). Determine both the empirical formula and the molecular formula of the comp
d1i1m1o1n [39]

Answer:

The empirical formula is = CCl_3

The molecular formula = C_2Cl_6

Explanation:

Moles =\frac {Given\ mass}{Molar\ mass}

% of C = 10.13

Molar mass of C = 12.0107 g/mol

% moles of C = 10.13 / 12.0107 = 0.8434

% of Cl = 89.87

Molar mass of Cl = 35.453 g/mol

% moles of Cl = 89.87 / 35.453 = 2.5349

Taking the simplest ratio for C and Cl as:

0.8434 : 2.5349

= 1 : 3

The empirical formula is = CCl_3

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12*1 + 3*35.5 = 118.5 g/mol

Molar mass = 237 g/mol

So,  

Molecular mass = n × Empirical mass

237 = n × 118.5

⇒ n ≅ 2

The molecular formula = C_2Cl_6

4 0
2 years ago
Air pressure is lower at high altitudes. An airplane cabin can adjust, but as the plane rises, passengers can experience tempora
-BARSIC- [3]

Answer:

The air pressure in the ears increases

The volume of air in the ears increases

The change in volume causes discomfort

It takes time for the ears to dispell excess air past the ear drum.

Explanation:

As the plane engages in a steep incline into the atmosphere, the outside atmospheric pressure decreases with altitude. The air pressure in the ear, therefore, become greater than atmospheric pressure. The air volume in the ear therefore grows and pushes on the ear causing discomfort. As the air in the cabin pressurizes the discomfort eases away as pressure equalization is restored relative to the ear.

4 0
2 years ago
Read 2 more answers
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