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lianna [129]
2 years ago
9

Marisa is a 120 pound female who attended a party where alcohol was being served. She began drinking at 9 pm. After finishing he

r 5th drink at midnight, she left, driving her own car. She was pulled over about a mile from the party location.
Chemistry
1 answer:
tiny-mole [99]2 years ago
4 0

Answer:

Explanation:

hour that passes and she drank for 3 hours so .045% must be subtracted. .20% - .045 % = .155%2) Obviously drunk, staggering, irrational behavior, no coordination 3) Yes, she is driving intoxicated because Texas’ legal limit is .08% and she is above that. Scenario 2 4) David drank 6 drinks. At 240 lbs, he is at .10%. However, subtracting .060% (.015% per hour x 4 hours) gives a BAC of .04%5) Relaxed, mellow, may show slight signs of impairment 6) David is okay to drive at .04% according to Texas law. However, the effects of alcohol can vary greatly for many reasons. 7) Even though Anthony drank the same amount during the same amount of time, several factors could cause Anthony’s BAC to be higher than David’s, thus making him “more drunk.”

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Which of the following statements concerning hydrocarbons is/are correct?
Alona [7]

Answer:

1.  Saturated hydrocarbons may be cyclic or acyclic molecules.

2.  An unsaturated hydrocarbon molecule contains at least one double bond.

Explanation:

Hello,

In this case, hydrocarbons are defined as the simplest organic compounds containing both carbon and hydrogen only, for that reason we can immediately discard the third statement as ethylenediamine is classified as an amine (organic chain containing NH groups).

Next, as saturated hydrocarbons only show single carbon-to-carbon bonds and carbon-to-hydrogen bonds, they may be cyclic (ring-like-shaped) or acyclic (not forming rings), so first statement is true

Finally, since we can find saturated hydrocarbons which have single carbon-to-carbon and carbon-to-hydrogen bonds only and unsaturated hydrocarbons which could have double or triple bonds between carbons and carbon-to-hydrogen bonds, the presence of at least one double bond makes the hydrocarbon unsaturated.

Therefore, first and second statements are correct.

Best regards.

6 0
2 years ago
State whether each of the following will be more soluble in water or hexane i. Butane ii. Ch3cooh iii. K2so4
ioda

Explanation:

Solubility is determined by the principle , "like dissolves like" .

i.e. , if a compound is polar then it will dissolve in a polar compound only , and

if a compound is non - polar then it will dissolve in a non - polar compound only .

Hence , from the question ,

Water is a polar molecule , and hence it will dissolve only the polar molecule , i.e. , from the given options the polar molecule is , iii. K₂SO₄

Hexane , is a non - polar molecules ,  hence it will dissolve only the non polar molecule , i.e. , from the given options the non polar molecule is i. Butane .

3 0
2 years ago
Given the following values of pKa, determine which is the weakest base of the answers listed. Acid pKa HClO2 1.95 HClO 7.54 HCOO
professor190 [17]

Answer:

HClO 7.54

Explanation:

Hypochlorous acid (HClO) is a weakest acid because the pKa value of Hypochlorous acid is very high among the options given in the activity. pKa is a method which is used in order to identify the strength of an acid. The higher the value of pKa of a liquid, lower the strength of an acid while lower the value of pKa of chemical, higher the strength of an acid. In the options, HClO2  is a strong acid due to high lower pKa value.

4 0
2 years ago
Which of the following statements will decrease the amount of work the system could perform? (a) Add to the solution (b) Add sol
Dmitry_Shevchenko [17]

Answer:

Increase the concentration of the solution

Explanation:

Increasing the solute would increase the concentration. Increasing the solvent would decrease the concentration. For instance, if your lemonade was too tart, you would add more water to decrease the concentration

8 0
2 years ago
mastering chem If the experiment below is run for 60 s, 0.16 mol A remain. Which of the following statements is or are true? At
Dvinal [7]

Answer: All of the statements are true.

Explanation:

(a) Considering the system mentioned in the equation:-

The sum of total moles in the flask will always be equal to 1 which leads to confirmation of this statement as for 60 secs= 0.16 mol A and 0.84 mol B

(b) 0<t< 20s,  mole A got reduced from 1 mole to 0.54 moles while at 40s to 60s A got decreased from 0.30 moles to 0.16 moles.

0 to 20s is 0.46 (1 - 0.54 = 0.46)mol whereas,

40 to 60s is 0.14 (0.30-.16 = 0.14) mol

(0.46 > 0.14) mol leading this statement to be true as well.

(c) Average rate from t1 = 40 to t2 = 60 s is given by:

\delta moles/\delta time  = 0.30-0.16/60-40 = 0.007 Mol/s which is true as well

7 0
2 years ago
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